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licre the ycllow and orangc precipirares arc, rcspectively (a) $\mathrm{Na}_{2} \mathrm{Cr}_{2} \mathrm{O}_{2}, \mathrm{~K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{-}$ (b) $\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}, \mathrm{Na}_{2} \mathrm{Cr}_{2} \mathrm{O}_{2}$ (c) $\mathrm{Na}_{2} \mathrm{CrO}_{4}, \mathrm{~K}_{2} \mathrm{CrO}_{4}$ (d) $\mathrm{Na}_{2} \mathrm{Cr}_{2} \mathrm{O}_{2}, \mathrm{~K}_{2} \mathrm{CrO}_{4}$

We're going to find the component forms um going from .12.2. So each time we'll be taking our second point and subtracting the corresponding component from the first. So for our first factor we would consider that we do negative four minus negative six and a negative one minus negative. To notice those minus negatives end up being adding. So we get 2 to 1. So it can either be written with the brackets or we can write it in R I. J form which would be to I plus one J. And I don't have to write the one. If you just see the J. You know that there's a one there Kate. Now our next vector notice every single time we're going to be doing negative 1 0. Well this is already in kind of its component form because its origination is at zero. So we can really write our vector as just the negative 161 And if we write an I. J and k notation we could have a negative I plus six, J plus K. Now our third we'll have to a nine minus four A one minus one and a negative three minus negative three. So in the end I have no J and K. So in the notation that I've already written with brackets you would actually place in a zero where there are, you know, um no components of that form. But when you go to write it in I. J and K, you just write that as five A. If you don't write the J and K component, then it's known that those are zero.

Were given to factors. You is equal to two I plus J Mom, we can convert this into a component form which would just be too I or +21 and the same thing with V. So v turns into three negative to just looking at the coefficients of each, um I and J. So now we can find the magnitude of you. The magnitude of you is equal to the square root of the sum of the squares of the components is the square root of five and in with scurvy or with magnitude V, we have three squared plus two squared negative two square, which is same thing as tooth positive screwed 24 plus nine is this 13 c squared 13 is our vector or is our magnitude V and for two times you two times you we have four to. So we now do foursquare close to square. This gives us 20 square to 20 just equals who to root five. Or you can believe it as the 20 square twenties find as well. And what half of the is through is uh yeah, 1.5 negative one and the magnitude of these values, plus negative. One squared someone Half a magnitude is square root of one slurred of 13/4 and then we can look at you plus fee. So you plus fee is manager you for we get five negative one and ah, magnitude is five squared. Plus Make it if one squared just 26. So square root of 26 is our magnitude for U plus V and for humanise fee you have native one and three, which means that our, um we now have made it one squared skirt of negative one squared plus three squared, which is 10 square root of 10. And lastly for you manage to the view Money's limited view. What we already know what you issues Screwed of five and magnitude of e is square root of 13 and this is equal to square of 10. You're plugging this into a calculator

We have vectors. U, which is negative. Two plus two U. J two i plus three j and we also have V, which is I minus two j. So these factors and compose converted into component form gives us negative 23 just by looking. The coefficients and V is one. It's that this is I I minus two j one negative too. So the nine itude is found by finding the square root of the sum of the squares off the components. So negative two squared is four plus three squared, which is nine gives us skin is five. So the magnitude of you of after you is five or scare. Sorry. This would be 13 actually Screw of 13 and then for V the magnitude of e, we have one plus four. So this Aziz equal to square root of five and then for to you to two times you we get negative. Four six. I multiplied the components each of the components of you with two, and we get 36 plus 16. So to you is scared of 52. And the magnitude of 1/2 fee is 0.5 negative one, and we're gonna do the same thing. Square root of 0.5 squared plus one plus one square, which is just one. Um, this is equal to square it of five for its And the next one we want to find issue, plus the magnitude of you plus feet. So this one is, um U Plus V is negative one one, which means that our magnitude is scared of to and u minus fee is is us negative three five making this square root of 25 plus nine, which is equal to squared of 34. Finally, the magnitude of U minus magnitude of the well, we really know what the magnitude of us squared of their team. Gonna subtract the magnitude of you which is great of five, and this is equal to and plug this into a calculator, or we can actually leave it as it ist in this form.

In this problem, I'm writing the reactions. So just look at it carefully. OK. FECN six came food, FT CN six plus six. He S CN k s c N will react to form, get to the f e SCN six and now I'm going to write the second reaction. They just look at it carefully Or FECL three. That's pretty careful. F E CN six, then it will give 54 F e CN six plus two old KCL. So option age correct here.


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