5

Agency reports that 11.630MorrcrsParticular country belongedUnions, Suppose sample 400 workers determine whether union embership Thas increasedWcctcgdctermint wheth...

Question

Agency reports that 11.630MorrcrsParticular country belongedUnions, Suppose sample 400 workers determine whether union embership Thas increasedWcctcgdctermint whether union cffortsordanizc hav Incrcoscd union membershipFormulate the hypotheses that can be uzed 0,116 Ha: P = 0.116 Ho: P 0.116 0.116Ho' P 0.116 K P 0.1160,1io 7,P 0.116 Ho: P 0.116 Ha 0.116If the samp results show that 56 of the workers belonged unions what the P-value for your hypothesis test?Fina the value of the test statist

agency reports that 11.630 Morrcrs Particular country belonged Unions, Suppose sample 400 workers determine whether union embership Thas increased Wcctcg dctermint whether union cfforts ordanizc hav Incrcoscd union membership Formulate the hypotheses that can be uzed 0,116 Ha: P = 0.116 Ho: P 0.116 0.116 Ho' P 0.116 K P 0.116 0,1io 7,P 0.116 Ho: P 0.116 Ha 0.116 If the samp results show that 56 of the workers belonged unions what the P-value for your hypothesis test? Fina the value of the test statistic. (Round your answer two decimal places ) Find the p-value (Round your answer four decima places ) O-Vame At & 0.05 what your conciusion; Do not reject Ho' There sufficient evidence conclude that there has been increase Mnian Memderenic Do not reject Ho: There Insuincient evidence conclude that there has been Dmhincrease Mniom membership. Reject Ro Tnere sufficient evidence conclude that there has been an Increase Mncn membership Relect There insufficient evidence conclude tnat there has been Increase union membership



Answers

(a) identify the claim and state $H_{0}$ and $H_{a},(b)$ find the critical value and identify the rejection region, $(c)$ find the test statistic $F,(d)$ decide whether to reject or fail to reject the null hypothesis, and (e) interpret the decision in the context of the original claim. Assume the samples are random and independent, the populations are normally distributed, and the population variances are equal. If convenient, use technology. The table shows the salaries of a sample of individuals from six large metropolitan areas. At $\alpha=0.05,$ can you conclude that the mean salary is different in at least one of the areas? (Adapted from U.S. Bureau of Economic Analysis) $$\begin{array}{|l|l|l|l|c|l|}\hline \text { Chicago } & \text { Dallas } & \text { Miami } & \text { Denver } & \text { San Diego } & \text { Seattle } \\\hline 43,581 & 36,524 & 49,357 & 37,790 & 48,370 & 57,678 \\37,731 & 33,709 & 53,207 & 38,970 & 45,470 & 48,043 \\46,831 & 40,209 & 40,557 & 42,990 & 43,920 & 45,943 \\53,031 & 51,704 & 52,357 & 46,290 & 54,670 & 52,543 \\52,551 & 40,909 & 44,907 & 49,565 & 41,770 & 57,418 \\42,131 & 53,259 & 48,757 & 40,390 & & \\& 47,269 & 53,557 & & & \\\hline\end{array}$$

We're told that in 2005 12.5% of American workers belong to unions. That gives us a proportion of 0.1 to 5. And we're also told that in 2006 we want to test to see if the proportion of American workers and unions has increased. We're told that in 2006 we have a sample of 400 workers for Part 80 were asked to formulate a hypothesis test for this scenario, so the alternative hypothesis would be that proportion is greater than 0.25 and therefore, the no hypothesis is that he is less than or equal to 0.1 to 5, and we can see that this is an upper tail a test. So that's our hypothesis. Test for B were as to calculate the P value for our scenario, and we're told that of the 400 workers in the sample, 52 were in unions, so that is a sample proportion, and that is equal to 0.13 So the next question ask ourselves, is how our sample proportions distributed and because end times p greater than or equal to five this could be verified easily. It's 400 times 0.1 to 5 and in times one minus P is also greater than or equal to five. Therefore, the sample proportions are approximately normally distributed, and so we're using the said statistic. So for sample proportions is that statistic can be estimated by and then plugging in the numbers, and that comes out to the 0.3. So now for the P value, so 0.3 would be somewhere around here. And so once we look when we look up 0.3 on the table, it's going to give us an area that corresponds to the cumulative probability, which is the area in the chart to the left of the said score. But RPI value is the area in the upper tail and from the said from the said table were given that this area is equal to 0.6179 and therefore the P value is equal to one minus 0.6179 So we have P value equals one minus 0.6179 in that equals 0.38 to 1. So that's the P value that that ends. Part B and Part C were asked what we would conclude if at an Alfa level of 0.5 So quite simply, a P value is bigger than Alfa. Therefore, we fail to reject the null hypothesis.

Part one. The coefficient on the year dummy of 1985 is roughly the proportion it changed in wage for a male, and the person has zero years of education. This is not an interesting result because the US working population with any education is without any education is a small girl. Such people are in no way typical part two. What we want to estimate is fate or not equals Delta, not plus 12 Delta one. We could write. Delta not equals fate or not minus 12 Delta one. And we pluck that into equation 13.1 and rearrange We will get log of wage is regressed on beta. Not plus they dare not. Why 85 plus beta one education plus Delta One. Why 85 times education minus 12 and the rest is the same as before. The coefficient we need here is the estimate of fate or not. Seita, not that is 0.339 with a standard error of 0.34 This estimate implies the nominal increase in wage is about 33.9% and the 95% confidence interval is yeah, 33.9 plus and minus 1.96 the critical value times the standard error of 3.4, and we would get 27.2% as the lower bound and 40.6% as the upper bound for three. We find that only the coefficient on the year dummy of 1985 differs from Equation 13.2. The new coefficient is minus 0.383 with a standard error of 0.1 to 4. This shows that real wages have fallen over the seven year period, although less so for the more educated part four. The art square when lock of really, which is the dependent variable, is 40.356 as compared with 0.4 to 6 when the log of which is the dependent variable. If the sum of square residuals from the regressions are the same, but the R Square are not, then the total sum of squares must be different. This is the case for this part part 5 1978. About 30.6% of workers in the sample belong to a union. The number in 1985 is only 18%. Therefore, over the seven year period, there was a notable fall in union membership. Heart Sixth, When we add the interaction term of Ear 85 Union to the Equation, it's coefficients and standard Errol are about minus 0.4 and 0.6 one, respectively. This is very small, and the T statistic is almost zero. We can conclude that there has been no change in the union wage premium over time. March 7 Part four, part five and six do not contradict each other. The two parts implied that why the economic return to union membership has not changed, the fraction of people reaping those benefits has fallen just

Okay. So what we're gonna be looking at is the comparison of I. Q. S. Of kids that went through some sort of lung cancer therapy and those that didn't. So what we're gonna be doing is taking a right tail test since our first group is bigger than the other one, the average is bigger for the other one. So we're gonna split this down right here and this is gonna be at the 1% significance level. So if our tests the state falls in this region we will reject the hypothesis. Mhm. So our test statistic is gonna be given by T. Equals this equation right here and we're going to substitute our values right there. So T. Is going to be equal to 84.4 minus 78.2. And then we're gonna take the sp which is the pool standard deviations sample size for the first one in 74 minus 1, 73. With a standard deviation of 12.6 squared. And for the other one it's 72 minus one. So 71 times the standard deviation of 15 squared. Yeah. And then we're gonna divide by the two adjusted sample sizes, Okay? Which is gonna be our degrees of freedom. Mhm. At 1% significant level. So we'll get a critical value later. But first our full statistic is 13.84 So go and put that in there. Take the square root of the solid reciprocal sample sizes. Mhm. And what we get for our t statistic is 2.71 And when we look in the back of the book we look between 102 100 degrees of freedom since 144 is about between them and we find out that it's 2.35 so obviously 2.71 is greater than 2.35 meaning that we do land in that critical region zone. So at least 1% significance level. We reject the null hypothesis. There is the this means that the accused of the kids that went through that therapy are lower.

In this problem, we're going to be testing the effectiveness off. ECON ASIA In treating calls, we have two groups off subjects. The first subject was given a kidney Asia. The first group was given magnesia, and the second group was given a placebo. So we can say P one hunt represents the proportion off the people who developed the retrovirus infections after being given a condition, and that is 40 45. So that's a fraction off. Those who developed renew various infections after being given akin Asia. And for those who developed in various infections after being given the possible are 88 out off a total of 103 subjects. And to test the effectiveness off back in Asia for Coles, we're going to use two approaches. The fast approach is going to be a hypothesis. Test on the second one is going to be the confidence interval. So we're going to use the 0.5 significance level, and we're testing the clean that back in Asia has an effect on rhinovirus infections. We're not giving, uh, we're not saying that one has ah, one is more effective than they ever were. Just saying that there is no effect on grain of virus infections that makes these tests are two tails test on the critical value on that is plus or minus 1.96 So let's go ahead and get the test statistic, which is that obtained by substituting the values obtained into the formula. And when we do so, we get the calculated value of that zero point 573 and when we compare the calculated value of that and the critical value of that in this case we have it as 1.96 positive and negative 1.96 So the calculated value of that is zero 0.573 and it is not within the critical region and for that reason we fail to reject the narrow hypothesis. Failure to reject an al hypotheses means that there is not sufficient evidence to support the claim that back in Asia has a NIF effect. So we move on to the second test by constructing an appropriate confidence interval and to do so to get a 95% confidence interval. We need to use the formula given and fast work out the margin of error e, and when you substitute the values off into the formula, we get that. The margin of error e is 0.1143 and when we substitute this into their confidence interval, we get that. The intervals limits are negative. 0.7 93 less than P 1 may not be too, and 0.1493 So we noticed that the confidence interval limits do contain zero, so zero is included within the confidence interval limits and thes shows that there is not significance thing. There is not a significant difference between the two proportions because when zero is included, WAY can see that there is not a significant difference between the proportions. In other words, there is no sufficient evidence to support the claim that back in Asia treatments has an effect. And in the last part of the question see, we're answering the question. Does echinacea appear to have any effect on the infection rate and according to the results, we see that back in Asia does not appear to have a significant effect on the infection rate and because it does not appear to have an effect, a significant effect, it should not be recommended because it's a safe for those two proportions do not have any significant difference.


Similar Solved Questions

5 answers
Suppose 18x2 < 0 For which of the following values of x does the inequality above hold? 1)33103 3 4 43
Suppose 18x2 < 0 For which of the following values of x does the inequality above hold? 1)3 3 10 3 3 4 43...
5 answers
Find the general solution of the differential equation(3+)c =0
Find the general solution of the differential equation (3+)c =0...
5 answers
# 23. g(r) = V1+21
# 23. g(r) = V1+21...
5 answers
Two point charges are stationary and separated by a distance R. Which one of the following pairs of charges would result in the largest repulsive force?~q and +5q+2q and +10q3q and -2q+3q and -2q~3q and4q
Two point charges are stationary and separated by a distance R. Which one of the following pairs of charges would result in the largest repulsive force? ~q and +5q +2q and +10q 3q and -2q +3q and -2q ~3q and 4q...
5 answers
Which is the product of the following reaction?LiAIH THFthen NaOH aq"NHz
Which is the product of the following reaction? LiAIH THF then NaOH aq "NHz...
5 answers
An unknown compound has formula of CsHsOz and a boiling point of approximately 102-104 'C The IR and IH NMR spectrum is shown below. Showing your work; propose a structure of this compound3636 3468 J089 3022 2987 2946 2986[743 1100 1650 1032 1447 988 26 [404 3 934 27 1375 999 1234 054 1462 607667 4764d00J0002000T500[000ravenundeRi-I1,02.06,05,04,03,02,0
An unknown compound has formula of CsHsOz and a boiling point of approximately 102-104 'C The IR and IH NMR spectrum is shown below. Showing your work; propose a structure of this compound 3636 3468 J089 3022 2987 2946 2986 [743 1100 1650 1032 1447 988 26 [404 3 934 27 1375 999 1234 054 1462 60...
5 answers
Calculate the producers 'surplus for each of the supply equations at the indicated unit price $ar{p}$.$$q=0.05 p^{2}-20 ; ar{p}=50$$
Calculate the producers 'surplus for each of the supply equations at the indicated unit price $ar{p}$. $$q=0.05 p^{2}-20 ; ar{p}=50$$...
5 answers
Question 11 (1 point) Given A = 309 , 7 = 21 b = 42. Determine whether the given measurements produce one triangle; two triangles or no triangle at all;
Question 11 (1 point) Given A = 309 , 7 = 21 b = 42. Determine whether the given measurements produce one triangle; two triangles or no triangle at all;...
1 answers
Boron consists of two isotopes, $^{10} \mathrm{B}$ and $^{11} \mathrm{B}$. Chlorine also has two isotopes, $,^{35} \mathrm{Cl}$ and $^{37} \mathrm{Cl}$. Consider the mass spectrum of $\mathrm{BCl}_{3}$ How many peaks would be present, and what approximate mass would each peak correspond to in the BCl_ mass spectrum?
Boron consists of two isotopes, $^{10} \mathrm{B}$ and $^{11} \mathrm{B}$. Chlorine also has two isotopes, $,^{35} \mathrm{Cl}$ and $^{37} \mathrm{Cl}$. Consider the mass spectrum of $\mathrm{BCl}_{3}$ How many peaks would be present, and what approximate mass would each peak correspond to in the BC...
1 answers
$\tan ^{2} \theta-\sec ^{2} \theta=$ ______.
$\tan ^{2} \theta-\sec ^{2} \theta=$ ______....
5 answers
QuestionUse the phase diagram below t0 answer the following questions2.001.75L 1.25 1.00 0.75 0.50 0.2530.0088 8 : ? 8 8 ? ? ? Temperature (degrees C)FSA XWhat phase changes are occurring at Point X?100"C to 300"C at constant pressure of 0.75 atm, what will As the temperature is increased from happen to the sample?What forms of this substance exist at 0 %C? Explain your answer(s):17LM
Question Use the phase diagram below t0 answer the following questions 2.00 1.75 L 1.25 1.00 0.75 0.50 0.25 3 0.00 8 8 8 : ? 8 8 ? ? ? Temperature (degrees C) FSA X What phase changes are occurring at Point X? 100"C to 300"C at constant pressure of 0.75 atm, what will As the temperature i...
5 answers
There is an AC series circuit that is constructed of a 150 ohm resistor along with 300 ohm inductive reactance and 200 ohn capacitive reactance. What is the impedance of this circuit?
There is an AC series circuit that is constructed of a 150 ohm resistor along with 300 ohm inductive reactance and 200 ohn capacitive reactance. What is the impedance of this circuit?...
5 answers
2?2 1 F | 1 { H 1 [ { 1 { 1 1 H H 1 W HHh 7 7 2L [ 121 1 08 1 1 8 1 1 1 1 0 [ [ 5 5 } 3 jli 1 L 1!P i ] 8 N 5 VL W 1 8 F [ 07 >
2?2 1 F | 1 { H 1 [ { 1 { 1 1 H H 1 W HHh 7 7 2L [ 121 1 08 1 1 8 1 1 1 1 0 [ [ 5 5 } 3 jli 1 L 1 !P i ] 8 N 5 VL W 1 8 F [ 07 >...
5 answers
Question 2 (5 points)Two 530 g blocks of wood are 2.0 m apart on frictionless table: A 10 g bullet is fired at 400 m/s toward the blocks. It passes all the way through the first block; then embeds itself in the second block: The speed of the first block immediately afterward is 5.4 m/s. What is the speed of the second block after the bullet embeds itself into it?Your Answer:Answerunits
Question 2 (5 points) Two 530 g blocks of wood are 2.0 m apart on frictionless table: A 10 g bullet is fired at 400 m/s toward the blocks. It passes all the way through the first block; then embeds itself in the second block: The speed of the first block immediately afterward is 5.4 m/s. What is the...
5 answers
Cheptcr 04, Problem 01Binuderate mand aeceleteles Gebble Over ncrizcntaplane Miuccnstont acceleralicr(4.01 6,0j) ns"_ Acunievelccicy (3 0i) mVs Whatthe (3} majritude and ( 2} andle das veloxity when # has been disclaced 13.0 I parallel (0 Lne >Mnnehlumbe(b] Number
Cheptcr 04, Problem 01B inuderate mand aeceleteles Gebble Over ncrizcnta plane Miu ccnstont acceleralicr (4.01 6,0j) ns"_ Acunie velccicy (3 0i) mVs What the (3} majritude and ( 2} andle das veloxity when # has been disclaced 13.0 I parallel (0 Lne > Mnnehlumbe (b] Number...
5 answers
He 15 Ii 18 1 2 2' 12.8 2 coefficient S 7 25.7 1 8 8 2 multip 35 th
he 15 Ii 18 1 2 2' 12.8 2 coefficient S 7 25.7 1 8 8 2 multip 35 th...

-- 0.029678--