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1 e/ee/e/3/e///z 1 1 1 H { 1 12 2 G/: z/e/g 1 U ] 1 1 L M 1 1 1...

Question

1 e/ee/e/3/e///z 1 1 1 H { 1 12 2 G/: z/e/g 1 U ] 1 1 L M 1 1 1

1 e/ee/e/3/e///z 1 1 1 H { 1 12 2 G/: z/e/g 1 U ] 1 1 L M 1 1 1



Answers

$\left[ \begin{array}{lll}{1} & {1} & {1} \\ {1} & {2} & {3} \\ {0} & {1} & {1}\end{array}\right]$

This video's gonna go through the answer to question number 11 from chapter 9.3. So ask to use real reduction to find the inverse off the matrix. That 11 one 121 Thio three. So So we conform the combination matrix with the identity and they tried refugees. Okay, so if we subtract to you off the top equation from the bomb equation, then we're gonna get zero one that to you, minus 20 Maybe it's gonna be minus 201 on the inside. And if we should bottle subtract one of the first question from the middle equation, that's gonna be zero That's gonna be one on that's going to zero months. Well, on zero on me, the top equation as it is, Savior zero. Okay, so now we get to be a stick in court because on left inside the bomb equation on the middle or after the bottom row of the majors in the middle of the matrix. All the same, which means that the ah, the row is off the matrix linearly dependence, which by their a born in the book, means that er the identity that's all right with me

Her being asked to simplify this expression. So first we have to take care of the multiplication. So first, we're gonna multiply negative 1/2 times negative one. How? Which is positive one for? And then we multiply our variables sometimes m, which is I'm squared and we're gonna bring those last two terms down. Negative 1/2 m and negative 1/2 out. Now let's combine our light terms. Well, the first term won four m squared. Doesn't have a late term, so we'll just bring that down. But that we hit do have light terms in negative 1/2 them minus 1/2 m Well, negative 1/2 minus 1/2 is negative one. So we just have negative one m. You can leave this as your final answer. But remember, you don't have to put the one in front of that M term so you could simply say your final answer is 1/4 m squared minus F

Okay for this one. We have a is equal to 12 negative. One 011 and zero. Negative 11 So the characteristic equation for this problem is given by negative Lambda Cubed plus three Lambda squared minus four. Lambda plus two is equal to zero. And when we solve this equation, it's a cubic equation. So you will get the three argon values as 11 plus I and one minus. I noticed that these talking visor complex congregants. So now if we have the Lambda equals one, then upon solving the system, eh? Minus I times u equals zero. We will get that use equal t times 100 and for Lambda equals one. Plus I, using a similar process, we end up getting that you sequel to a T times I'm minus two negative I and one no, for Lambda Contra Kit equals one minus I, which is given here. Then that implies that you is equal to it. Turns out that the Egan vectors are also conflicts congregates of each other. So you was simply gonna be equal to a T times negative. I'm minus two guy and one

Hello students. So in this question we have to determine one m cubed is equal to which of this later. Okay so we have to determine here number. So in this question we have to convert this meter cube into later. So from the converting table we know that one later, it is equal to 1000 centimetre Q. And also we know that one m it is equal to 100 centimeter. Okay so from this value we can obtain that one centimeter. It will be equals to one by 100 m. Okay, so now from this quantity substituting value here so we will get that one later, this will be equals two 1000 particular by Centimeter which is this complete values one x 100 meter and this cube. Okay so from here after solving we will get one by 1000 m cube. So from here we have obtained that one liter, it is equal to this much of meter cube. So from here we can write one m after cross multiplying, we will get 1000 liter. Okay, so this is our one m cube. Okay, so this will be one m cube. So one m cube is, it is equals 2000 liters. So this is what this is the what we want in this question. Okay, so from the given options option for it is our correct answer for this problem. Okay, thank you.


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