5

Polrts} cectronics manulaclurci nas 0CYC ODCC cjcelremolc contro button trale desidnyd opcralc onacr OClorc falling Wvor consistcniy ranjcm samz of 30 of thc ncw bu...

Question

Polrts} cectronics manulaclurci nas 0CYC ODCC cjcelremolc contro button trale desidnyd opcralc onacr OClorc falling Wvor consistcniy ranjcm samz of 30 of thc ncw buttons sclectca and Bach tested CONtimucus Opetatidn uritil fails work ccnsistently: The resulting lifetirnes &re jjuric navg Samj TT Bwn 248. hours und Swmp standard deviaton 110.8 Indecancent tests TEvBz tFat the mean lifetime of the best remote contro cutton Maket 122C nouts Corauct = Fypothesis tes: determine the nev: buttcn 5

polrts} cectronics manulaclurci nas 0CYC ODCC cjcelremolc contro button trale desidnyd opcralc onacr OClorc falling Wvor consistcniy ranjcm samz of 30 of thc ncw buttons sclectca and Bach tested CONtimucus Opetatidn uritil fails work ccnsistently: The resulting lifetirnes &re jjuric navg Samj TT Bwn 248. hours und Swmp standard deviaton 110.8 Indecancent tests TEvBz tFat the mean lifetime of the best remote contro cutton Maket 122C nouts Corauct = Fypothesis tes: determine the nev: buttcn 5 mean Iifetime exceeds_ 220 hours Rauno calculated answers tD four decimal places The null hypa nesis p =1220,What the alemate hypcthesis? A HA: / > 1220 B. TTA = 1248.6 C. HA: u < 1220 D: HA : u > 1248.6 II^ : M # 1220 wnich oftne Icwino conditicns Tust perform th 5 hypatnesis 05t2 Select the comect arsviers, Tne samo € must o8 large cnough cast 10 buttons fall and succeed The nlmjer fEcTOlE cortoo_ buttore lased [TIR be nonnally distributed The lifetime of remote control buttons Must nom? digributed, Wie must ce able expect that : cast outons wiill fail wck consistertly: The obsurvaicns MTusl b3 incuperdert: Calculatc thc tcst statistic Calculate the p-value Calculate the effect size, Cohen' for this test_d The results this test indicate wre have large small (noderate mcderate large effect size, strong Evidence litt e evidence extremely strong evidence somc Curcncc ver Strard evidenCe tharthe null mozel is not compatible with Our observed rebut



Answers

You and your team are exploring an antiquated research facility in the mountains of southern Argentina that had been abandoned in the 1960 s. You come to a giant locked door that has no visible handles or actuators, but you find a hand-held device nearby that has two buttons, labeled "Open" and "Close." It looks like some kind of crude remote control, but when you push the buttons they just click and nothing happens. You open the device's top cover and inspect it. The internal mechanism resembles an old acoustic remote control called the "Space Command $600 "$ that your parents had for their ancient TV. Pushing a button on the remote actuated a small hammer on the inside that struck the end of an aluminum rod, about 2 or $3 \mathrm{cm}$ in length. The rod vibrated and emitted an ultrasonic sound wave that actuated an electrical circuit in the TV that was sensitive to that frequency. The TV remote had three buttons, and therefore three rods that vibrated at different frequencies. The first frequency turned the $\mathrm{TV}$ on and off, the second made the tuning dial click to the next station, and the third made the dial turn in the opposite direction. You pull off the cover of the device and find that it has places for two $1 / 4$ -inch diameter rods, but both are missing. However, written on the inside of the cover of the device is the following: "Open $=95.50 \mathrm{kHz}$ " and "Close $=102.50 \mathrm{kHz}$ " Your team members search and eventually find a long piece of $1 / 4$ -inch diameter aluminum rod. (a) To what lengths must you cut the rod in order to get the remote to work properly (i.e., so that the fundamental frequencies of the rods match those utilized by the remote)? (b) Suppose you had instead found a titanium rod. What lengths would be required in that case? (Young's moduli are $Y_{\mathrm{Al}}=6.9 \times 10^{10} \mathrm{N} / \mathrm{m}^{2}$ and $Y_{\mathrm{Ti}}=1.2 \times 10^{11} \mathrm{N} / \mathrm{m}^{2} ;$ the mass densities are $\rho_{\mathrm{Al}}=2700 \mathrm{kg} / \mathrm{m}^{3}$ and $\left.\rho_{\mathrm{Ti}}=4500 \mathrm{kg} / \mathrm{m}^{3} .\right)$

All right. We want to test the hypothesis. New equals 64.5 versus the null hypothesis or alternative hypothesis does not equal 64.5 for population standard deviation 0.6 given the following data at alpha equals 0.1 confidence. This question is testing your knowledge of how to conduct a hypothesis test for population renew. When the standard deviation sigma is known. We see through the five steps listed here to solve first, we verify normality. So from the normal probability bar on the left, in the box, on the right, we conclude that the data is normal without outliers. Thus we can proceed to solve so and be we calculate that sample size and X five simple meat. This is N equals 22 X 5 64.7 Thus you see we can calculate our test statistic, this is zero equals experiments were not over segment about 10, which gives negative 38.53 for alpha equals 0.1 We continue the critical value in step D. For two tailed tests using a Z. Table where the area H 2.5 are critical value is plus or minus 2.58 Thus we can conclude in step E the following first. Let's rewrite our critical Z score correctly. Since our Xena is to the left of our negative 2.58 we can conclude that zero is in the critical region. So we reject H. Not because you know it's a critical region. We also address the fact that ALPHA equals 00.1 is more reasonable than Alpha equals 0.1 because there are severe punishments for making the type point ever in this problem I. E. There's a severe punishment for making an area generally. So we want to keep the 0.0.1 stringent criteria.

We have muse equal to 1300 as a known mean of the population. We want to calculate the sample mean exploring the sample standard deviation s for the randomly sampled data that follows. So to do so, we simply have to remember the definition of expire to ask for a sample. That's why, for example, in some of the data to buy buy em in this case, 12 68 S is some of the deviations about the moon squared, all divided by n minus one. In this case. 37.29 Next, what we want to do is implement a two tailed test. That is we want to test whether or not this sample suggests the actual meaning this population differs either higher or lower. Either direction from the no mean 1300. We're going to do so with an alcohol level of 0.1 and we're gonna know at this point that X is approximately normally distributed. So to implement this test, we have to follow the following procedures, one by one 1st. What is the significance of hypotheses? Alpha equals 0.1 The null hypothesis H not is musical 1300. And the alternative hypothesis H is that it is not equal 1300. Next distribution We're going to use compute the associated testes, cystic. We're going to use a student's t distribution because the population standard deviation sigma is not known. We only have a sample standard deviation S It's appropriate to use the distribution because X is approximately normally distributed, meaning it's both symmetric and round shape necessary to use students T. Six reasons to distribution. Let's calculate the T statistic. It's defined by this formula, expire minus mu divided by s over root end, which in this case equates the negative 2.714 next let's compute the p interval and sketch the results. So, since we have a degree of freedom of n minus one equals nine, no, from a two tailed T table, which we can find in google and the stats textbook, we find that the T statistic corresponds to a p value range between 20.0 to 1.5 We can think of this also as the area underneath the T distribution outside of negative 2.714 and 2.714 The T statistic as is graft on the right. Finally, given this p interval range, we can make a conclusion about this test. Since P is greater than alpha, we have statistically insignificant bindings and we cannot reject h shot. We fail to a general hypothesis. Therefore, we interpret this to mean that we lack evidence suggesting that the population mean differs from its no mean of 1300.

Following is a solution video to number 24 and this is where we compare to means uh for the soil, water content for field a compared to feel b. And the first part is just to verify that the mean and the standard deviations are in fact these numbers, So the mean for field day is 12.53 and the standard deviation is 2.39 And then the mean for field B was 10.77 with the standard deviation of 2.4, and it says use a calculator something use this T I 84 I went ahead and typed in the means, or sorry, the data values L one and L two, so L one represents fuel day and then L two represents, you'll be and if you go to stat falcon and it's one of our stats and we're going to change that to L one and calculate and that gives us everything we need. So the X bar, is that 12.53 So that's verified. And then we're looking at the s the standard of the sample standard deviation is about 2.39 So for the field A. That is correct. And then let's just go and double check field be. So we're gonna change it to L. Two now because that's where field B. Is, and then that verifies its 10.77 for the mean, then about 2.40 for the standard deviation. So the first part is done, that's verified. And then the second part it says conduct not formally, but we're basically just going to conduct a uh uh two sample T. Test with an alpha value of point oh five. And we're gonna go back to the calculator because doing it by hand can be pretty cumbersome. So if you go to stat and then test now, since we already have, we're gonna go to two sample t. Test since we already have the data in there. I'm just gonna use the data instead of the summary stats. So list one is L. One that's the field A. List to is L. Two. That's field B. And then these frequencies just keep them the same and then we have the the alternative hypothesis and you kinda have to use your context clues here. But this one actually explicitly states is field A. Is the soil content or water content higher or greater than. So I'm going to change this to greater than So μ one is greater than you to warm you. A. is greater than YouTube pulled is usually zero or no unless they tell you otherwise. So we can go ahead and calculate and that's gonna give us everything we need. So the T. Value if you want you can put it down there. But really it's just this P. Value that I want to see. So 00.27 is the p value. So P value equals 0.27 And then we compare that with the alpha value and it's less than the alpha value. So any time it's less than the alpha value. That means we reject the no hypothesis. So we're rejecting the statement that these means are the same. And we are I guess you could say accepting the fact that these two means are in fact the water content and field A. Is greater than the water content and field be on average. So we can type this out as there is enough evidence to suggest that field A. Has on average a higher soil content soil. Sorry, water content. Banfield beat. Okay so this field A. Has on average a higher soil water content on field because since we are rejecting that null hypothesis and accepting the alternative hypothesis.

The following is a nova test based on the mean salaries for different metropolitan areas. So the alternative or the null hypothesis is that all the means are the same. So there are six metropolitan areas, I think it goes Chicago, Dallas Miami, Denver san Diego and Seattle. Uh So the null hypothesis is that all the means are the same. And then the alternative is that at least one of them is different. The second step is to find the critical value and you can do that using either software or a table, But they're essentially three things you need. The first thing is your alpha value, your significance level and that's usually given to you the problem and that's .05. Then you need the degrees of freedom for the numerator and the degrees of freedom for the denominator. And the way you find that Is the degrees of freedom for the numerator is the number of categories -1. So there were six cities that we looked at our metropolitan areas, so 6 -1° of freedom would be five for the numerator. And then for the denominators, the total number of data values minus the number of categories. So there were 36 data values minus the six metropolitan areas. So 30 is your degrees of freedom for the denominator. So that should be enough to use a table. But I use a calculator and I wrote a program in here called inverse. F. I'm not going to show you how to how to write the program. You can youtube it if you wish. Um But this is what I do. So um I put in my area which is my alpha value, my degrees of freedom is five and then my degrees of freedom for the denominator is 30 and That gives me my critical value. About 2.534 2534 is my critical value. I call f. star. So 2.534. Okay so anything greater than 2.534. We reject the annual hypothesis that all the means are the same And anything less than 2.534. We failed to reject meaning the h not is true. Okay so the second step is to find the F statistic and there's a formula but it's a bit of a mess. I always use software you know technology is a great thing. So if you go to stat and you can type in your data values. So these are the mean salaries um So again L1 I think was Chicago and then this is the mean salary for Dallas Miami Denver San Diego and Seattle. So there are six categories. And if you go to stat tests and then we're gonna go to the Unova test and then you just type in your columns separated by commas remember there were six columns, six data columns that we used and we need to make sure that all of them are in there and last one and then also you know make sure you separate those by commons, otherwise it's going to read it wrong. So then um that gives us everything we need. So the F. Is the F statistic, that's the third step. So we're looking at this it's about 2.281 as our F. Value. So two point 281 is our f statistic Which is actually barely in the non rejection region 2.281. So that means we fail to reject. Okay and also we can verify that with this p value here. So the p values 0.7 which is a pretty small p value, but it's still in this case greater than the alpha value. So the alpha value remembers point oh five, so it's barely greater than the alpha value. And whenever it's greater than the alpha value, uh we failed to reject, I should probably put H not there, so we failed to reject H not whenever the P values greater than the alpha. Okay. So then the last step is to summarize everything with actual words. So what does this all mean? It just means that there is not sufficient evidence, there is not sufficient. I guess you could say statistical evidence to suggest that the mean salaries from the different metropolitan areas are different. Okay. And that's the five step process for an Innova one way and over test


Similar Solved Questions

5 answers
DNA fingerprints of Identical twinsC € D 0B BShow are DNA fingerprints of identical (monozygotic) and fraternal (dizygotic) twinsWhich are identical?
DNA fingerprints of Identical twins C € D 0 B B Show are DNA fingerprints of identical (monozygotic) and fraternal (dizygotic) twins Which are identical?...
5 answers
Trigonometric Identities Pythagorean Identity (note: (sin(0))? is often denoted sin? (0).) Compute the folowing sin? ( 3) + cos? ( 82) sin"(#) += Cos?( #) ~sin?(3) cos?(3) = iv sin?(%) + cos? (%) (b) What do You notice about sin?(0) + cos? (0) for any 0? (c) Looking at the unit circle, why does your response to the above question make sens _ for any 0?
Trigonometric Identities Pythagorean Identity (note: (sin(0))? is often denoted sin? (0).) Compute the folowing sin? ( 3) + cos? ( 82) sin"(#) += Cos?( #) ~sin?(3) cos?(3) = iv sin?(%) + cos? (%) (b) What do You notice about sin?(0) + cos? (0) for any 0? (c) Looking at the unit circle, why doe...
5 answers
In terms of chemical bonding why are the water molecules easily removed from the Cuso yet the CuSO4 stays together? 1
In terms of chemical bonding why are the water molecules easily removed from the Cuso yet the CuSO4 stays together? 1...
5 answers
How does the initial ratio of carbon to nitrogen (C:N) of plant litter influence the relative rates of nitrogen mineralization and immobilization during the initial stages of decomposition?
How does the initial ratio of carbon to nitrogen (C:N) of plant litter influence the relative rates of nitrogen mineralization and immobilization during the initial stages of decomposition?...
5 answers
@te fonBascd = r"ulous question Wic moasieu coik "ntratian ' enificantlv Jiartty Lt 977 connmence IuzvcI} Irom (he Erpxcted conconlalion ublmlStunficamtly differentNot sgnla cantly oltcrcnt
@te fon Bascd = r"ulous question Wic moasieu coik "ntratian ' enificantlv Jiartty Lt 977 connmence IuzvcI} Irom (he Erpxcted conconlalion ublml Stunficamtly different Not sgnla cantly oltcrcnt...
1 answers
Show that, for a flat mirror, $h_{i}=h_{\mathrm{o}},$ given that the image is the same distance behind the mirror as the distance of the object from the mirror.
Show that, for a flat mirror, $h_{i}=h_{\mathrm{o}},$ given that the image is the same distance behind the mirror as the distance of the object from the mirror....
5 answers
Consider the following hypotheses test HO: pZ 80 Ha: / < 80A sample of 121 provided sample mean of 77.3. The population standard deviation is known to be 16.5 , Determine the p-value: and using 063 lest the above hypotheses_(Hint: uSe the 2 distribution table t0 findOur p-value il you do nol have the TI-84]
Consider the following hypotheses test HO: pZ 80 Ha: / < 80 A sample of 121 provided sample mean of 77.3. The population standard deviation is known to be 16.5 , Determine the p-value: and using 063 lest the above hypotheses_ (Hint: uSe the 2 distribution table t0 findOur p-value il you do nol ha...
5 answers
Draw a quick sketch of the graph of each equation.$$x=y^{2}$$
Draw a quick sketch of the graph of each equation. $$ x=y^{2} $$...
4 answers
What is the pH of a solution where 0.02 L of 1.0 M HCl isadded to 0.1 L of H2O?
What is the pH of a solution where 0.02 L of 1.0 M HCl is added to 0.1 L of H2O?...
5 answers
[Co (NH3)sNOz]Clz and [Co NH:)sONOJClz are related to each other as:Select one:a geometrical isomersb. linkage isomersC_ coordination isomersd.ionization isomersCc
[Co (NH3)sNOz]Clz and [Co NH:)sONOJClz are related to each other as: Select one: a geometrical isomers b. linkage isomers C_ coordination isomers d.ionization isomers Cc...
2 answers
Let (R, T) be a topological space and A,BCR Compute Fr(A) andFr(B), where A = [-3,5]and B={ new}.
Let (R, T) be a topological space and A,BCR Compute Fr(A) and Fr(B), where A = [-3,5] and B={ new}....
5 answers
1.1.3 Gribner BasesDefinition 1.8 A Grabner basis for an ideal in K[r. 'Ta]finite set ofgenerators {91, -Imn } for such thatLT(T) (LT (91)LT (Jm))
1.1.3 Gribner Bases Definition 1.8 A Grabner basis for an ideal in K[r. 'Ta] finite set of generators {91, - Imn } for such that LT(T) (LT (91) LT (Jm))...
5 answers
If f() 4x2 21 + 4, find f' ( _ 3)_Use this to find the equation of the tangent line to the parabola y = 4x? 2x + 4 at the point ( - 3,46). The equation of this tangent line can be written in the form y mc + b where m is:and where b is:
If f() 4x2 21 + 4, find f' ( _ 3)_ Use this to find the equation of the tangent line to the parabola y = 4x? 2x + 4 at the point ( - 3,46). The equation of this tangent line can be written in the form y mc + b where m is: and where b is:...
5 answers
Far &Conedder Ine lollo vino tcacIion2CHa(g) CHa(g) 3Ha(g) concantemon CH] 0.0S6M equilibrimm ConcantnamonUne (eaconCH ' Camed G Ecmeremderamune Kn0 011 M,Find Ine aquilibrivm constaniaiinis lemperaluje2IPiate Your enerar uino (ro aionmcanttloura?AzdSubmilPpueu anatm Recare m [Inconoct; Tly Agah; ettampts retnainlngrovlde FeedbackNen >
Far & Conedder Ine lollo vino tcacIion 2CHa(g) CHa(g) 3Ha(g) concantemon CH] 0.0S6M equilibrimm Concantnamon Une (eacon CH ' Camed G Ecmeremderamune Kn 0 011 M, Find Ine aquilibrivm constaniaiinis lemperaluje 2IPiate Your enerar uino (ro aionmcanttloura? Azd Submil Ppueu anatm Recare m [ In...
5 answers
Integrate f Jov dV , wbere Q is the solid Ixnutuld by 0 :0. +2vplanes
Integrate f Jov dV , wbere Q is the solid Ixnutuld by 0 :0. +2v planes...
5 answers
43. Calc CaBrz (aq) when 26g CaBrzs) yields a 0.1OM CaBrz solution. Use dimensional analysis.5. Calc g CaBrzs) in 38.2mL of a 3.5M CaBrzaq): Use dimensional analysis:
43. Calc CaBrz (aq) when 26g CaBrzs) yields a 0.1OM CaBrz solution. Use dimensional analysis. 5. Calc g CaBrzs) in 38.2mL of a 3.5M CaBrzaq): Use dimensional analysis:...

-- 0.033763--