5

The shoulder heights of six calves were measured: The statistics that was found from this random sample is reported below: Sample Mean_ 79.25 Sample Standard Deviat...

Question

The shoulder heights of six calves were measured: The statistics that was found from this random sample is reported below: Sample Mean_ 79.25 Sample Standard Deviation 5.33 cm Assume that the shoulder heights of calves are approximately normally distributed_ Construct 95% confidence interval t0 estimate the population mean of the height of calves:Does the population mean lie in the confidence interval that you constructed? Explain:

The shoulder heights of six calves were measured: The statistics that was found from this random sample is reported below: Sample Mean_ 79.25 Sample Standard Deviation 5.33 cm Assume that the shoulder heights of calves are approximately normally distributed_ Construct 95% confidence interval t0 estimate the population mean of the height of calves: Does the population mean lie in the confidence interval that you constructed? Explain:



Answers

Use the listed paired sample data, and assume that the samples are simple random samples and that the differences have a distribution that is approximately normal. As part of the National Health and Nutrition Examination Survey, the Department of Health and Human Services obtained self-reported heights (in.) and measured heights (in.) for males aged $12-16 .$ Listed below are sample results. Construct a $99 \%$ confidence interval estimate of the mean difference between reported heights and measured heights. Interpret the resulting confidence interval, and comment on the implications of whether the confidence interval limits contain $0 .$ $$\begin{array}{|l|c|c|c|c|c|c|c|c|c|c|c|c|} \hline \text { Reported } & 68 & 71 & 63 & 70 & 71 & 60 & 65 & 64 & 54 & 63 & 66 & 72 \\ \hline \text { Measured } & 67.9 & 69.9 & 64.9 & 68.3 & 70.3 & 60.6 & 64.5 & 67.0 & 55.6 & 74.2 & 65.0 & 70.8 \\ \hline \end{array}$$

Now This time we have N is equal to 36 is equal toe 36. We have sigma That is the population standard deviation as 6.7 cc 6.7 cc then we have mean as 23 cc the mean off sodium chloride concentration was 23 cubic centimeters per cubic meter. So this is 23 23. But he is It's 90% confidence in total or C is equal to zero point tonight. Right now what I'm doing is I'm using an online calculator to calculate this. So my end is 36 my mean is 23. My standard deviation is 6.7 My standard deviation or yeah, my Sigma 6.7 and my confidence level is 90. So let me just input this. This is 90% and my values coming out to be 23 plus minus 1.837 So this is the interval in this case is 23 plus minus 1.837 Okay, so this is going to be my confidence in double. What will this be if I use a calculator for this? But if I just do it directly. This is going to be 21 point one six seven comma 24 point 837 Right. This is correct, right? Yeah. This is my first confidence interval at 90% at 95%. What is going to happen? We know that at 95% the confidence interval is only going to get writer. So at 95% confidence, where my C become zero by 95 she becomes 0.95 What is going to be my confidence interval now if I use the calculator again, this is 95% of now. But here I can see that my confidence intervals 23 plus minus two point when it might. So this is going to be this is going to be 23 plus minus 2.189 We can see that the marginal whether here is smaller than here. Which only makes sense because we already knew that 95% are interval will be wider. Right? So what is going to be our interval? It is going to be 20 point 811 comma. This is 25.189 Now, what does this confidence interval mean? Above 90%. It means that we're 90% confident that the true population mean will lie in this region. And in the second, when we're 95% confident that the true population means will lie in this region. These are my answers.

Let's read this question. Construct the confidence interval estimate of the mean. Okay, there is a sample of 106 body temperatures having a mean off 98.2 on the standard deviation off 0.62 We want a 95% confidence interval to estimate the mean body temperature for the entire population. So what we have is just the sample data, but the sample mean is 98.2 and the sample standard deviation is 0.62 Now, does the results suggest about the common? Believe that 98.6 degrees Fahrenheit is the main body temperature. Let's see our X bar. In this case, X bar, which is the mean, is given us 98 point to 98.2. Uh, yes, that is the standard deviation is given a 0.6 students 0.62 What is the end? End is, I think, 106. This is 106 106 We're going to use the tea distribution. If you want to do it by hand, it is going to be expired plus minus the margin of error margin of error is de Alva by two. Where what is Alfa? In this case, Alfa is going to be 0.0 for myself away to zero point 0 to 5 plus minus. This is T Alfa by two s my route and simply substitute the values and get your answer if we want to do it by hand. But if we want to take the help of a calculator or a statistical software, we can do that as well. So the confidence interval, which in this case turns out to be, is this confidence and evidence are to be 98.8 to 98.3 to 98.8 98.8 to 98 0.32 Now What does that mean? That is generalist thought off. It is 98.6. People think that this is the general temporary normal temperature. But we see that it does not fall in this interval. So we have enough statistical evidence to say at 95% confidence level that the average means is lower than 98.6. This is how we go about doing this problem. How do we find the value of T Alfa by two. We have degree of freedom as 105 and Alfa by two. In this case is going to be 010 to 5. That will give us the value of the alphabet ease 0.25 This is how we go about doing this problem.

Using the following data identified in the bottom line here, we want to find the sample mean X. Bar the sample standard deviation S. And accordingly constructed 99% confidence interval for the population. Mean you assuming this population is normally distributed To start off with, let's find expire and s using the appropriate definitions expire is simply that some of the data divided by n or 7.487 S is simply the square root of the sum of deviations about the main square, divided by n minus one. In this case. 1.638 next. Since we have a sample standard deviation, not the population, we're going to use the student's T distribution to calculate this confidence interval. The T score we need to identify is that where the students distribution area following between our negative and positive critical value TC is 0.99 for a degree of freedom and minus 24 15. Using a tea table in google or textbook, we obtained T C equals 2.947 Now we need to construct the margin of error E, which is given by TC times sample standard deviation asked, divided by route and plugging in our T C, s and N gives E equals 1.207 And now we can construct a confidence interval using the following formula that mu falls between expo minus E and explore plus key, meaning that our confidence interval is new, following between 6.280 and 8.694 with 99% confidence.

Let us look at this question. Now we're here. It says that we have 1 95 boys. The sample mean and the sample standard deviation is given. And we want to use a 95% confidence level. And it says are the results very different from those found in exercise? Nine. Well, in exercise nine, these were the results. And over here, now we're getting the values. If we put it in the software, if you will get 31.76 to 33.63 31.76 2 33 something so to 33.63 So, yes, they are very different. And does it appear that boys and girls have different ways? Yes, definitely. We can see that these weights are a little higher than as compared to the girls. So, yes, they are different and they do have different rates.


Similar Solved Questions

5 answers
Consider these two entries from a fictional table of standard reduction potentials_ X3+ +3e- 37 X(s) Eo = -2.05 VY3+ + 3e- L Y(s)Eo = -0.13 VWhat is the standard potential of a galvanic (voltaic) cell where X is the anode and Y is the cathode?Ecell
Consider these two entries from a fictional table of standard reduction potentials_ X3+ +3e- 37 X(s) Eo = -2.05 V Y3+ + 3e- L Y(s) Eo = -0.13 V What is the standard potential of a galvanic (voltaic) cell where X is the anode and Y is the cathode? Ecell...
5 answers
8 W 1 8 4 V 3 6 312 e/2 412 R/2 3 € 2 1 ele 8 Ia 1 1 0 6 2 6 8 0 3 6 2 8 2 6 6 8 1 p { 1 : 9 1 1 9 2 6 L 1 : 0 &l 17 0 1 { { 1 €2 3 1
8 W 1 8 4 V 3 6 312 e/2 412 R/2 3 € 2 1 ele 8 Ia 1 1 0 6 2 6 8 0 3 6 2 8 2 6 6 8 1 p { 1 : 9 1 1 9 2 6 L 1 : 0 &l 17 0 1 { { 1 € 2 3 1...
5 answers
Solve Ihe equation for exact solutions over tho interval [0, 2x) .cos*+4=0Select the correct choice below and; necessary; fill in Ihe answer box comploto your choice:0 Aj The solution set Is (Type an exact answer; using needed Type your answer in radians. Use Inlegers fractions for any numbers the expressior comma t0 separate answers as needed ) 0 B. The solution is the empty setlick t0 select = and enter your answer(s).
Solve Ihe equation for exact solutions over tho interval [0, 2x) . cos *+4=0 Select the correct choice below and; necessary; fill in Ihe answer box comploto your choice: 0 Aj The solution set Is (Type an exact answer; using needed Type your answer in radians. Use Inlegers fractions for any numbers t...
5 answers
| 8 111
| 8 1 1 1...
5 answers
Solve each equation. (All solutions for these equations are nonreal complex numbers.)$$(4 m-7)^{2}=-27$$
Solve each equation. (All solutions for these equations are nonreal complex numbers.) $$ (4 m-7)^{2}=-27 $$...
5 answers
Ueng the reegenis in Ia tnble, M In tho banks- specity Iho ngonts narded cach 5tep comolate ie 51na3h pictured in tne nuinba 0i eiaoa a3al2*REAGENTS:NOETBr; hvKXHg(OAch I,O NaHHUHz Lindlar ,f-HuOkMz, CCXRt ROOR1BH;-THF NOll IloNatsk NI; (NAMI;MtKuc9-ABN MOl HO;DMSNaNlI; 1l,6IIH , ROOKcII;CI,HtCofuOa NMOI;o1([ pyndung[H;sOslc,(MCPBA WuO WO;
Ueng the reegenis in Ia tnble, M In tho banks- specity Iho ngonts narded cach 5tep comolate ie 51na3h pictured in tne nuinba 0i eiaoa a3al2* REAGENTS: NOET Br; hv KX Hg(OAch I,O NaHH UHz Lindlar , f-HuOk Mz, CC XRt ROOR 1BH;-THF NOll Ilo Natsk NI; ( NAMI; Mt Kuc 9-ABN MOl HO; DMS NaNlI; 1l,6 IIH , R...
5 answers
Consider. binomial random variable with n 100 and D U.USE SALTFlnd the niean for the binomnial random variable *.Fnd the standard devlation tor the Unomlal raridorn varlableUse the correction Ior continuity and approximate Px $ 29) using the normal approximation. (Round vour answer t0 tou P(x 29)
Consider. binomial random variable with n 100 and D U. USE SALT Flnd the niean for the binomnial random variable *. Fnd the standard devlation tor the Unomlal raridorn varlable Use the correction Ior continuity and approximate Px $ 29) using the normal approximation. (Round vour answer t0 tou P(x 29...
5 answers
I1) 132 412) ~Cx &13} s G14) 20x" &15} Z0x 6
I1) 132 4 12) ~Cx & 13} s G 14) 20x" & 15} Z0x 6...
1 answers
A collar $B$ with a weight of $W$ can move freely along the vertical rod shown. The constant of the spring is $k,$ and the spring is unstretched when $\theta=0 .(a)$ Derive an equation in $\theta, W, k,$ and $l$ that must be satisfied when the collar is in equilibrium. (b) Knowing that $W=300 \mathrm{N}, l=500 \mathrm{mm},$ and $k=800 \mathrm{N} / \mathrm{m},$ determine the value of $\theta$ corresponding to equilibrium.
A collar $B$ with a weight of $W$ can move freely along the vertical rod shown. The constant of the spring is $k,$ and the spring is unstretched when $\theta=0 .(a)$ Derive an equation in $\theta, W, k,$ and $l$ that must be satisfied when the collar is in equilibrium. (b) Knowing that $W=300 \mathr...
5 answers
A 12.5 cm tall soft drink can has a mass of 16.9 g and contains 360 g of soda when full. Assuming the can is symmetric, its center of mass is obviously 6.25 cm above its base when full and when empty.(a) Where is its center of mass (in cm) when half full? cm above the base(b) Where is its center of mass (in cm) when one-tenth full? cm above the base
A 12.5 cm tall soft drink can has a mass of 16.9 g and contains 360 g of soda when full. Assuming the can is symmetric, its center of mass is obviously 6.25 cm above its base when full and when empty. (a) Where is its center of mass (in cm) when half full? cm above the base (b) Where is its center o...
5 answers
Arigid rectangular loop of 150 turns, which measures 0.32 m by 0.75 m, carries a current of 230 mA, as shown: A uniform external magnetic field of magnitude 3.5 T in the negative X-direction is present: Segment CD is in the X-z plane and forms a 250 angle with the Z-axis, as shown An external torque applied to the loop keeps it in static equilibrium: The magnitude of the external torque is closest to:0.32 m0.75 m[ =230 MAB=35T22 N 19 N m 12 N m 17 N . m 26 N m259
Arigid rectangular loop of 150 turns, which measures 0.32 m by 0.75 m, carries a current of 230 mA, as shown: A uniform external magnetic field of magnitude 3.5 T in the negative X-direction is present: Segment CD is in the X-z plane and forms a 250 angle with the Z-axis, as shown An external torque...
5 answers
College Mathematies: Leaming WorksheclsChapler &experimcnt consists of rolling Iwo fair dice and Luddine lh: dnts [wn cidcs Assuming Fuch Simpi (icing ten EquaIt- likely find Ihe probability oftha sum of the dots Incictcd Frohlen:SumJiihlThe sur#lensumUner than ind less than 13.
College Mathematies: Leaming Workshecls Chapler & experimcnt consists of rolling Iwo fair dice and Luddine lh: dnts [wn cidcs Assuming Fuch Simpi (icing ten EquaIt- likely find Ihe probability oftha sum of the dots Incictcd Frohlen: Sum Jiihl The sur #len sum Uner than ind less than 13....
5 answers
Qutarthm ring !> Initlaly attetot Ua topaf 20-Unich (ncllned p44 then Il bes N t0 roli down ddsnucd al Ins center Meon ceno hnrnala aettomolnn ndene D}
qutarthm ring !> Initlaly attetot Ua topaf 20-Unich (ncllned p44 then Il bes N t0 roli down ddsnucd al Ins center Meon ceno hnrnala aettomolnn ndene D}...
5 answers
17. Please State the 4Sth percentile value from the please state the 6" Decile, and the /" Quartila data in Problem #13, In addition value, as well
17. Please State the 4Sth percentile value from the please state the 6" Decile, and the /" Quartila data in Problem #13, In addition value, as well...

-- 0.021643--