Let's read this question. Construct the confidence interval estimate of the mean. Okay, there is a sample of 106 body temperatures having a mean off 98.2 on the standard deviation off 0.62 We want a 95% confidence interval to estimate the mean body temperature for the entire population. So what we have is just the sample data, but the sample mean is 98.2 and the sample standard deviation is 0.62 Now, does the results suggest about the common? Believe that 98.6 degrees Fahrenheit is the main body temperature. Let's see our X bar. In this case, X bar, which is the mean, is given us 98 point to 98.2. Uh, yes, that is the standard deviation is given a 0.6 students 0.62 What is the end? End is, I think, 106. This is 106 106 We're going to use the tea distribution. If you want to do it by hand, it is going to be expired plus minus the margin of error margin of error is de Alva by two. Where what is Alfa? In this case, Alfa is going to be 0.0 for myself away to zero point 0 to 5 plus minus. This is T Alfa by two s my route and simply substitute the values and get your answer if we want to do it by hand. But if we want to take the help of a calculator or a statistical software, we can do that as well. So the confidence interval, which in this case turns out to be, is this confidence and evidence are to be 98.8 to 98.3 to 98.8 98.8 to 98 0.32 Now What does that mean? That is generalist thought off. It is 98.6. People think that this is the general temporary normal temperature. But we see that it does not fall in this interval. So we have enough statistical evidence to say at 95% confidence level that the average means is lower than 98.6. This is how we go about doing this problem. How do we find the value of T Alfa by two. We have degree of freedom as 105 and Alfa by two. In this case is going to be 010 to 5. That will give us the value of the alphabet ease 0.25 This is how we go about doing this problem.