Predict the products of the following reactions, paying attention to stereochemistry when necessary. If more than one product is formed in a reaction indicate which...

Predict the product and give the stereochemistry resulting from reaction of each of the following nucleophiles with $(R)$ - 2 -bromooctane: (a) - CN (b) $\mathrm{CH}_{3} \mathrm{CO}_{2}^{-}$ (c) $\mathrm{CH}_{3} \mathrm{S}^{-}$

Have eyes that some problem. 81 28. You need to credit the product off the given direction. So the parcel is also more slices off. Cyclical came in the presence of zinc and the problem. We'll have both LD head and kitten groups in late, so the double won't pick him and Louisville Gator Kit on on and the hand functional group on the same lonely lives to drop the structure of the Maliki. So this is the kid on and another side. We have going to have this ever go at this Andy head and this is the problem for the first reaction Pontus of injection when the electrical king is directing with petition Parliament an idea in acid X elation these rebels want is going to break and we will get government problems a weak acid and again, in this compound there will be to provoke Cilic assets on the same molecule wanted to the beginning and one at the end. The bad reaction here again, the double bond is going to break. But this is has reparation oxidation reaction and it is going to give us, um and uncle so we know when we're doing head Operation Oxidation We get and go home with a high dosage group is going toe touch to the problem that we just having list substitution. So in this case, this company is having the least substitution. Therefore, um, Hendrickson group is going to end to this carbon and all these have revelation. Oxidation gives us end a product which mean always gives us sin products. In addition, Texas, which means that the have absolute group here and the hydrogen in this travel they're going to be on the same side off the molecule. Now let's draw by structure off, though. Strada, save these Me 10 group is on the back side, off the plane off the paper off the pain of the molecule And the hydroxy little group has been added to the least substituted Adam here and the hydrogen is added to the same sign. I don't want to kill and we have another hydrogen. So this is the product for the 4th 1 Distraction is oxen Operation Democratization reaction again, We're going to get alcohol and the problem problem double bond here will be broken and we will have only a single one. And when we do ox, inauguration, demarcation and absolute group added to the most substituted governmental. Which means that this government is going to have the hydro slip up and the hydrogen. And here and for oxen, decoration, demarcation we always get and a product which means the hydroxy group and the average in group, which is being added to these two car bombs. These are going to have opposite. They're going to add on from the opposite side, clean off the molecule. So let's draw by structure. The high looks ill group is added to the most substituted. Come on, Adam, and the hydrogen is going to be the same site on the opposite side. I hope I look simple and today's other hydrogen here and this is the product. So we get and day addiction Fonda and the sun is inundation.

Okay, um, in this problem, we are talking about the mechanisms and predicting the products of alkaline reactions. Specifically, in this case, we are going to be reacting al canes with hell agents, and that's we're going to be going over today, and we're also going to be using stereo chemistry. So for part A, we have this sigh click structure that has an elk in, and we are reacting it with diatonic probing. Remember that our mechanism arrows always go from electron rich to electron poor. This is the idea of a polar reaction using an electoral file and a nuclear file. So we're going to have this double bond. That's electron rich going to our bro Ming and picking up one of the bro means. And then are we? Pardon me, we will return our two electrons of this diatonic roaming bond onto one of our bro means So now we are going to form this ring that has a essentially a a pox side with this bro. Mean Adam And then we have a leftover negatively charged roaming an ion. So these electrons are going to attack are a pox. I'd ring and open it up and this would be our product. We have this ring here. We have a trans relationship between our roaming atoms where 11 would be appointing above the plain. One would be below, and that would be our product for our first reaction. Now, for our second reaction, we have something very similar. But now are all keen is not internal. It is a terminal, Elkin. So we're going to have a terminal, a pox side. So again, we have this benzene ring attached to this Al Kane, and we are reacting it with di atomic chlorine. So again, we're good for electron, rich to electron, poor are double bond is going to pick up one of these chlorine atoms and return the two electrons onto our chlorine. That's how we're getting an anti on. So we're going to have this benzene ring attached to an a pox side. And instead of an oxygen in this case, we're going to have a positively charged chlorine atom and then our leftover and ions we're going to have these electrons attack are a pox. I'd ring, causing it to open up. And this would be our product. Here we have this ring with this Al Caine structure with two chlorine atoms. And now, finally, we have a very similar, um, reaction as in part B, We start with this Al Keen in this case, we have it to be internal. Remember, we go from electron bridge to electron poor Are double bonds going to pick up one of these electrons or partly one of these chlorine chlorine? Return the two electrons onto our chlorine atom. We're going to form an a pox side with our positive charge. Chlorine atom, our chlorine. An ion is going to attack one of the sides of Europe. Oxide. Returning these electrons onto are positively charged chlorine. And then we're going to produce this product. And as we saw in part A, we have a trans relationship between our two chlorine atoms, and that is the end of this problem. I will make sure that all of our reactions are in one screen for you. I hope this made sense. If you have any questions, please comment or feel free to post a question I'm happy to answer. Um, I hope that this helps you in your current studies in organic chemistry

All right, so we have the following reaction here. Ah, and we want to predict what products we're going to get. So the first step here is to kind of look at what we have. So first we see that our for a reactant, we have a tertiary bro mind. And for our re agents here, we have water and ethanol. Um, we know that for these re agents, they are weak base and weak nuclear files. Right? So we know we're from this, we're going to get competing s and one anyone reactions, and therefore, we're actually gonna get quite a lot of products from that. So we're gonna here, we're gonna have competing s and one anyone reactions. So why don't we go ahead and draw first R s and one reactions, So we know that both water and ethanol can act as weak nuclear files. And so I'm going to go ahead and draw our what Rs and one reactions using water first also. Ah, we know that for s and want anyone reactions were always going to have a carbon carbo cat eye on for our first step formation. So I'm not really going to show that stuff for anything here. I'm just going to show the resulting products that we get. So using water as our nuclear phone, Let's go ahead and ah, draw everything here in red. So everything here in red is going to be with the water used as a ah used as a local file. Here we have this. And so the cat carbo cat around has been formed already. So I skipped that step here. And when we get water here and the water is going to come in, you can either come in Ah, for front side attack, or it can come in her backside attack. And so we're going to get some Ah, we're gonna get receive, make Mr here following There's a deep throat nation Step her as well in order to get to our heart drug side, which I'm going to skip as well. But just know that we have an additional step in between here. Right? So this is this is just going to be one of our products where we have the hydroxy are the alcohol group coming towards us and we're also gonna have the other product. Um, where the heart drug or where the alcohol is going away from us. So we'll draw that dashed. And now this. Ah, CS three group is coming at us. And for this carbon are, um groups are going to stay the same, right? So what we see here is that this is going to be a receipt. Make mixture. All right, So, um, now, what would happen if we were to draw ethanol? Um, being used as a weak nuclear file for an S and one reaction. So I'm gonna go ahead and draw everything here in green for an ethanol being used as a week Niko file. Right. So again, um, go and skipped the first step here where we have our formation of over of our tertiary carbo Quetta. And now ethanol is going to come in, um, either for front side attack or backside attack. And now we're gonna get the following products. All right, so there is another deeper nation step here as well. I'm sorry. No, no, there is no deportation step my other. It's actually, but I'm not going to show it. So what we're gonna get here is the following product. So we're gonna get another receive X mixture, just like we did with water, right? All right. So here there are foxy group are our foxy group is coming towards us, and now we're gonna show the proxy group going away from us. And then the groups on this carbon remained the same. Oops, sorry. Cider gin is going away from us. Right? So we know that this are these two products are going to be a receiving make sure, But now we got one more set of just one more product here, and that's going to be the result of our elimination reaction. So we go ahead and draw that. Now, I'm gonna draw that in blue here, so we're gonna have ethanol act as a weak base, and it's going to d prone 81 of the beta hydrogen. First, I'm going to draw our tertiary Calabro cat ion and immediate. So the first up here again is skipped. Right? And then we have the hydrogen. They're going away from us. Um, and now so are ethanol going Teoh Abstract A beta, beta hydrogen. So that could either be here or it could be here. Doesn't really matter. Um, we're starting to get the same product regardless. So it's gonna abstract a proton, and then these electrons were going to get pushed to form that pipe on, right? And so we get the following product. Parents are that and that will be all of our products. So just to recap um, in red, here we have our s and one I'm using water as a weak nuclear file in these over get a receipt make mixture of products full. And for the second set of products here we used ethanol and an S. And one reaction is a weak nuclear flow. We got another set of, ah, receive make mixture of products and then for our last ah reaction. Here we is ethanol as, um muse ethanol as a weak base in anyone elimination reaction. And we only got one product from that.