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For the circuit shown below: A) Use node-voltage analysis to determine the Thevenin voltage between points A and B B) determine the Thevenin resistance between poin...

Question

For the circuit shown below: A) Use node-voltage analysis to determine the Thevenin voltage between points A and B B) determine the Thevenin resistance between points A and B. (10 points)10.0 V910 Q460 Q1100 Q887.00 V

For the circuit shown below: A) Use node-voltage analysis to determine the Thevenin voltage between points A and B B) determine the Thevenin resistance between points A and B. (10 points) 10.0 V 910 Q 460 Q 1100 Q 8 8 7.00 V



Answers

For the circuit shown in Figure P 18.20, calculate (a) the current in the $2.00-\Omega$ resistor and (b) the potential difference between points $a$ and $b, \Delta V=V_{b}-V_{a}.$

In problem three we have this circuit starts at point A you need with a resistor in doctor and to buster and an easy voltage source and the current is 5.75 millimeters to the left. In this direction it's required to find the voltage across there is a this is the resistor and to find the voltage across the resistor it equals I which is the current. To blow it by. There is just equals 5.75 The current deployed by 10 to the power of minus negative three tend to the bar of minus three because we have a million pairs. We multiply it by the resistance 2250. Then the voltage equals 12.9 37 5 voltage. And this is the final answer of our problem.

So here in this problem we have been given the circuit and in these circuits we need to determine the potential difference Between the two points A and B. As shown here provided that we have been given that The two resistors. R one and R two have the resistance is 100 home and 200 respectively. And we have also been given that the emfs of the two cells, Even at 82, our 50 volts and 20 volt respectively. So in this case here, in order to determine the potential difference, let's figure out the current first in the circuit. So we will apply Kirchoff voltage law and considering the current to be moving in a clockwise direction here, Let's assume the potential at this point to be zero. So here as we are moving in the direction of current. So there will be a potential drop across this are too and that will be minus I into our two, that is 200. And there will be again potential drop because we are moving from positive to the negative end of this battery. So that will be -20 fold. And again there will be potential drop across this are one resistor, that will be 100. I and there will be potential gain across this even because we are moving from negative to the positive terminal. So that will be plus 50 vote. And we have again reached the same point where we have considered zero potential. So the overall result is going to be zero in this loop. So from here we can solve and get the value of the current. So taking this and this term to the right side, we get 300 I equals two 30 and that gives us the value of the current as point to one M. Pierre. So now we can easily compute the potential difference across the points A and B. So let's say B has potential zero volt. So the potential at this point will be dropped by I into our two. So that is .1 times are two, which is 200. and there will again be potential drop by 82, which is 20 volt. And this comes out to be 2020. So that's -40. So overall Is having potential -40 with respect to be. And if we compute the potential between difference between the points A and B, that will be V a minus will be. So here we got -40 as the potential of point with respect to B. So answer will be -40. What

Okay this question we're learning about Calvano metres which are used to measure voltage basically what they are is some kind of dial which has a bunch of voltages listed on it um from the circle. And uh there's a little needle which will move Um and up increasing um when the voltage between two points say N. B. I mean this is so in this particular Valvano meter um when there's no external resistor it's just this internal history which is intrinsic to the carbon emitter. Um when a current of four million apps Is run 4.4 million is run through it. Then we get the needle pointing to the maximum value which is called full scale deflection. Um Yeah and we're also told that the internal resistor is but we heard the resistance of internal mysteries But what we want is for the needles point to the end full scale deflection when a voltage of 10V is across this. Um But without this external resistor it will happen much sooner. So what we need to do is slow down the rate that this um this needle turns by increasing the resistance that we get less current Because any time we have for uh .4 million amps running through this device the needle is gonna point to here. So in order to have it delay moving all the way across until 10 folds, we're gonna need a higher resistance. So that's what this external resistors for. Okay so the max voltage, we need 10V and uh we don't they don't tell us exactly what voltage it took to get postcode deflection earlier but we can figure it out using arms law. So let's use arms law. Um Hopefully we're familiar with at this point says that V. Is equal to Ir but be careful because uh we may have labeled things a little bit differently in this case. Um What's called me? Not the amount of voltage between A. And B. Without the external resistor. When we just have the internal resistor. R succeed. Okay, so this current uh uh is enough with just this amount was

In the first part of this question, we are going to complete the potential difference between Point A and B. That is, well, maybe, let's say are one equals 2 10.0 are two equals to 5.0 that a tree close to 20.0. So for cities combination we can right are a prime nickels to our two plus our tree now setting the world is off to end our three. From here into this equation, we will get Ari prime equals to 25. No, for Caroline combination, we could light. I wonder what readable prime he calls to one by our want plus one by our two plus one by Ari Prime. Now setting the well is into this question We will get won by our edible prime equals torn by 10.0 plus one by 5.0 That's one by 25.0. So this will give us Ari double prime equals to 2.94 Now a readable prime and the remaining are wondrous stories in Siri's so we can write again. Ar e equals two are one plus a readable prime. Now sitting the Wellies off. This are one and a readable crime. Into this equation, we will get ar e equals to 12.94 The current supplied by the battery into the circuit is I equals two. We do want it by Ari. While sitting the values into this equation. We will get I calls too. 25 points. Your world divided, but will 250.94 This will give us aye equals to 1.3. So in 90 compare. No, we can write the equation for re A B s. We'll be equals to remind us I are one that scored Equation one. Now sitting the world is into this question we will get. We will be. He calls to 25 points here. Works minus into 1.93 impair into 10.0. So this is it wants to We have vehicles too. 5.6 set world. So this is the answer off us part of this question In part b of this question, we have to find the current passing through the resistance our tree. So let this guarantees I don't want using obsolete. We can, right? I want equals two. We have really wanted by Ari Prime. They're scoring equation, too. No writing Well is for the baby and Ari Prime We will get. I want equal to 5.6 network divided by 25 points your own. So this will be Iwas I want equals two 0.227 a pair. So end of the question


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