5

Given chat !rg f(#) docin" cWee#) Orand Hh(=) 7 , Gntd tie Iltnit thit cxita Pniat DNR Iftha lumnit(2) JimUf(z) h(-)l lim]f(-)P' lim 9) f(z) 2f(z) lim h(z...

Question

Given chat !rg f(#) docin" cWee#) Orand Hh(=) 7 , Gntd tie Iltnit thit cxita Pniat DNR Iftha lumnit(2) JimUf(z) h(-)l lim]f(-)P' lim 9) f(z) 2f(z) lim h(z) = f(z)hclp (limit) help (imits) help (limics)help (limits)

Given chat !rg f(#) docin" c Wee#) Orand Hh(=) 7 , Gntd tie Iltnit thit cxita Pniat DNR Iftha lumnit (2) JimUf(z) h(-)l lim]f(-)P' lim 9) f(z) 2f(z) lim h(z) = f(z) hclp (limit) help (imits) help (limics) help (limits)



Answers

Evaluate the limit using the Basic Limit Laws and the limits $\lim _{x \rightarrow c} x^{p / q}=c^{p / q}$ and $\lim _{x \rightarrow c} k=k .$ $$ \lim _{z \rightarrow 0} \frac{3}{z-1} $$

The question asks us to evaluate the limit of Z to the two thirds power as he approaches twenty seven. To solve this, we can use the basic limit law at the limit as X approaches a constant C of X to the P over Q is equivalent to see to the P over cues power. All I need to do now is plug in values. In this case, X equals our variables. E c equals our constant twenty seven p equals the numerator of the Expo in it, too, and Q equals a denominator of denominator of the exponents. Three. So when we combine this, we get the answer that the limit is equivalent to twenty seven to the two thirds power which equals the key route of twenty seven squared, which can be rewritten as three squared, which equals nine. And that is our answer

As he approaches three from the positive direction. Let's see what happens to our function. Z minus one Z minus two, divided by Z minus three In the numerator Weaken just substitutes three and we're getting three minus one times three minus two. So two times one which is to downstairs. We're getting zero from the positive direction because these always slightly more than three and a positive number like two divided by a very small positive number gives us positive. Infinity no for the other side as he approaches three from the negative direction. C minus one times Z minus two divided by C minus three approaches well at the top were getting the same two times. One. But this time we're getting zero from the negative direction because Z, slightly less than three and dividing a positive number by a small negative number gives us negative Infinity Thies to limits and wrote the same. So there is no limit as Z approaches three or for function Z minus juan times Z minus two. Divided by C minus three Ford A. It's plus infinity. Part B is negative. Infinity and parts he is. It doesn't exist

So here we want to find the limit by inspection. So the limit as X approaches eight of seven, we'll keep mind that seven is our function. So our function would look like F of X equal seven. So what is the limit as X approaches eight of seven? Well, it's always going to be seven. So that's the limit. Then we see that. Um If we have negative three to limit as X approaches infinity will be negative three. If we have Pie, the limit as X approaches europe from the right will be pie. These are fairly basic examples if we have three X. We know that as X approaches negative two, it's going to be negative six because this is a continuous function. And we know if we plug in a negative two we get negative six. Then if we have 12 Y, we know that when we plug in three we'll get 36. So that would be the answer for that. And then lastly, if we have negative two, H and H is going to positive infinity, then we know that it's going to be a negative infinity

So we are asked to find the limit of root Z divided by zero minus two as Z approaches nine, we can actually separate this into two different limits, So that will be the limit of Root Z as he approaches. Nine. This looks like a cute Let me fix that divided by, and I'm going to put these limits and two different colors for extra clarity. The limit of Z minus two as he approaches nine. Great. Now we can actually simplify this even further. Let's look at the numerator. First we can look toward another basically it law, which states that the limit of X to an exponents as X approaches a constant C is equivalent to that same constant C raised to that exponents p over Cuba. So if we want to apply this to our problem, we get it nine, which is our constant raised to the power of Z. So that would be rude. Nine. Right that read Route nine divided by and here we can actually split this limit into two further limits because the limit of one part's attracted from another part is equivalent to the limit of one part. So tracking from the limit another part. So we get the limit as she approaches nine of Z minus the limit as see approaches nine of two. Great! And now we can simplify this further. Route nine is equivalent to three, so that will be our value in the numerator. The limit of Z as he approaches nine is equal to nine, and the limit of two as he approaches nine is equal to two because he is not part of that function. So our final answer will be three sevens, and that is the value of the limit.


Similar Solved Questions

5 answers
Question 111 ptsIn testing Ho : p = 0.25 vs. Ha: p # 0.25 with sample proportion p^-0.30 based on sample of size 400. The observed significance (the p-value) of the test is closest to:2.310.0250.050.0104
Question 11 1 pts In testing Ho : p = 0.25 vs. Ha: p # 0.25 with sample proportion p^-0.30 based on sample of size 400. The observed significance (the p-value) of the test is closest to: 2.31 0.025 0.05 0.0104...
5 answers
Fiane id - 3 QTsC3Cltoh > koatoC#]out3Question 41 ptsSee Figure 10-3. The product(s) of a ring expansion in the methanol solvolysis of Compound would beOcl3
Fiane id - 3 QTs C3 Cltoh > koat oC#] out3 Question 4 1 pts See Figure 10-3. The product(s) of a ring expansion in the methanol solvolysis of Compound would be Ocl3...
5 answers
Ii multipliers express each measurement without 2.34X any 2 exponentsTE L 0| Classify oceans 1 contain L arWc jups approximately60[ km'water. Calculate NCh the volume
Ii multipliers express each measurement without 2.34X any 2 exponents TE L 0| Classify oceans 1 contain L arWc jups approximately 60[ km' water. Calculate NCh the volume...
5 answers
A(1+1)-3 I > 0 otherwise
a(1+1)-3 I > 0 otherwise...
5 answers
Question 13Describe what usually happens to a hot solution that is saturated with solid as it cools Q The solid that Is dissolved comes out of the solution completely: The " solid stays in the solution Some of the solid comes out of the solution The solution freezes OHThe solution solidifiesRUESTONWhat is the compound that forms If you react potassium ana sulfur? 0KzsPS2 SkPovestioh/6
Question 13 Describe what usually happens to a hot solution that is saturated with solid as it cools Q The solid that Is dissolved comes out of the solution completely: The " solid stays in the solution Some of the solid comes out of the solution The solution freezes OHThe solution solidifies...
5 answers
In an experiment,23.5 gof metal was heated to 98.0'C and then quickly transferred to 150.0 gof water in a calorimeter: The initial temperature of the water was 21.58C,and the final temperature after the addition of the metal was 32.58C. Assume the calorimeter behaves ideally and does not absorb or release heat:Ist attempt See Periodic TableSee HintWhat is the value of the specific heat capacity (in Jlg "C) of the metal? Jlg'"€
In an experiment,23.5 gof metal was heated to 98.0'C and then quickly transferred to 150.0 gof water in a calorimeter: The initial temperature of the water was 21.58C,and the final temperature after the addition of the metal was 32.58C. Assume the calorimeter behaves ideally and does not absorb...
5 answers
Use lhe change-of-base formula and calculator t0 evaluale the loganthm. Round your answer to three decimal places 1091/5Icg1/5 6 = (Do not round until Ihe final answer Then round t0 Ihree decimal places 05 necded
Use lhe change-of-base formula and calculator t0 evaluale the loganthm. Round your answer to three decimal places 1091/5 Icg1/5 6 = (Do not round until Ihe final answer Then round t0 Ihree decimal places 05 necded...
5 answers
Factors affecting community diversity. ( with explanations on each)
factors affecting community diversity. ( with explanations on each)...
5 answers
Explain what contributed to the bridging of the gap between chemical evolution and biological evolution
Explain what contributed to the bridging of the gap between chemical evolution and biological evolution...
3 answers
In a study of the effects of stress on behavior in rats, 71 ratswere randomly assigned to either a stressful environment or acontrol (non-stressful) environment. After 21 days, the change inweight (in grams) was determined for each rat. The table belowsummarizes data on weight gain. (The study report gave thestandarderror of the mean sn , abbreviated as SEM, rather thanthe standard deviation s.)Group. n. mean. SEM Stress. 20. 26. 3No Stre
In a study of the effects of stress on behavior in rats, 71 rats were randomly assigned to either a stressful environment or a control (non-stressful) environment. After 21 days, the change in weight (in grams) was determined for each rat. The table below summarizes data on weight gain. (The study r...
5 answers
Name and describe 5 ways in which antibodies help fightinfection.
Name and describe 5 ways in which antibodies help fight infection....
5 answers
M Ulzo VL Wolcon [email protected] 11 W
M Ul zo VL Wolcon [email protected] 6r 1 1 W...
5 answers
A planet rotates on an axis through its poles and 1 revolutiontakes 1 day (1 day is 24 hours). The distance from the axis to alocation on the planet 30 degrees north latitude is about 3687.5miles. Therefore, a location on the planet at 30 degrees northlatitude is spinning on a circle of radius 3687.5 miles. Computethe linear speed on the surface of the planet at 30 degrees northlatitude.
A planet rotates on an axis through its poles and 1 revolution takes 1 day (1 day is 24 hours). The distance from the axis to a location on the planet 30 degrees north latitude is about 3687.5 miles. Therefore, a location on the planet at 30 degrees north latitude is spinning on a circle of radius 3...
5 answers
199 205 196 200 218 220 215 223 23 234 235 230 250 248 253 24616 . 0 16 16 16 24 24 24 24 32 32 32 32 40 40 40 40
199 205 196 200 218 220 215 223 23 234 235 230 250 248 253 246 16 . 0 16 16 16 24 24 24 24 32 32 32 32 40 40 40 40...
5 answers
(a) Find the domain of function f (z) = Vz+3+V4-: (b) Explain why it is continous at every number in its domain.TrueFalseQuestion 210 ptsDetermine whether f (x) = 1'_ 313+7 is eve., odd, Or neither:
(a) Find the domain of function f (z) = Vz+3+V4-: (b) Explain why it is continous at every number in its domain. True False Question 2 10 pts Determine whether f (x) = 1'_ 313+7 is eve., odd, Or neither:...
5 answers
84o. flx,y) = sin(Sx - 10y) Find Vf (x,y) (5 points)Find the derivative of f in the direction of the vector (3,_4}. (4 points)
84o. flx,y) = sin(Sx - 10y) Find Vf (x,y) (5 points) Find the derivative of f in the direction of the vector (3,_4}. (4 points)...

-- 0.069423--