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Bonus qucstion (2 pts total):[. Draw an organic compound that is chiral but does NOT contain chiral carbons...

Question

Bonus qucstion (2 pts total):[. Draw an organic compound that is chiral but does NOT contain chiral carbons

Bonus qucstion (2 pts total): [. Draw an organic compound that is chiral but does NOT contain chiral carbons



Answers

Draw the structure of 2 -butanol. Identify the chiral carbon atom in this compound. Draw the mirror image of the structure you first drew. Are the two molecules superimposable?

For this question, we have to draw four compounds with molecular formula C five h 10 and we have to include a carbon to carbon double bond. But make sure that we do not have any system trans I summers. So to do this, generally, we will pick one of the carbons involved in a double bond and have both of substitution groups coming off of that carbon be the identical. So if we switch them around, we'll have the same all of you'll. And no assistant Trans i summers because there is no higher priority group on that carbon. So first we can start by carbon carbon double bond. Carbon on the left can be attached to a hydrogen, and also a ch three ch two ch two group Carbon on the right can be attached to two hydrogen. So this uses up 10 of our hydrogen ins. Five carbons, and we do not have this trance I summer because these two hydrogen czar the same group. So switching these around, um, won't change the molecule and we switched the side around. It also won't change it because there is no hype. There's no higher priority group between these two hydrogen is there the same. So we can't determine whether there is a higher priority group on the same side or the opposite side because there isn't a higher priority group. Next, you will have a carbon carbon double boned carbon on the left. We can have a metal group and also and I feel group. So this is used up our five carbons. And then we will Odd to hydrogen is attached this to this carbon. So the same reason as our first molecule thes this carbon on the right is attached to to hide regions, and they're the same group. Next we can do you in carbon to carbon double bond curved on the left. You can have a hydrogen and a three carbon group arranged like fists so that used up all our carbons and is different from her first molecule. Because the carbons airtouch differently in the no carbon on the right, you'll have to hide regions again. There is no higher priority group on this Carmen. Both this if issuance are identical, so we can't have any such insurance. I summers and lastly, we'll have a carbon to carbon double boned, and we will put to ruffle groups on carbon on the carbon on the left, you know, on the carbon on the right, but a hydrogen and methyl group. So this issue stuff are five carbons and 10 hydrogen, and he's to mother groups of the same. This is Sichuan's on carbon on the left about the double bond are the same. So we can't have any season trades, ice murder there.

This molecule can take several shapes. It's a to seal to are you is in the center of all of them. H 20 C. L minus and H three h 20 c minus And an H three. First option there. We've got this here. Notice instead of C l minus or got NH three and CR minus flipped waters in the same spot in hte three. Here. The water is swapping of chlorine and h three and then Corrine here. So chlorine in an H three swamp C l minus. So we've got water swap there and then our line. Honest one, uh, is actually Kyra molecule, Mr Chlorine Zehr both next to each other and which 20 three c minus c l minus So noticed. The C L minus has swapped with H 20 in this model.

Everyone today were doing Chapter twelve problems for Tina. Miss Prone gives us the structure Mosquito Tanamor and asked to draw two different Tada murs of this two mental cycle Axonal on DH also draws to constitutional icebergs that are not taught in here. So let's start with a so two toddlers. So in the previous question, Question twelve, Chapter eleven Question twelve We figured out how to go from a penal toe aikido. So the converse is true for the opposite. So in order to go from Kito to, you know, we need to look at the carbon is directly adjacent to this out toe are Kito. You have two different carbons directly adjacent to our kitto on. We have two protons are actually four protons coming out of the way both these carbon so we can actually go backwards, um, and actually pick up the proton using this carbon using this oxygen nucleus being electron rich, you can pick up one of these protons making you bombing you make upon your break up onto the bond breaks is gonna be a signal bond. Cinnamon will form your pie bond, making you Bonnie and make a bunny and break upon. So the carbon all bond will break going absorption and Chris. So this forms one possible, you know, with the alcohol here that will be on this side. But we have another adjacent carbon with a proton on this size. So alternatively, the auction can pick up this Hired out of making you bon, you make a bond, you break the bond to make the new double bond here. Then you keep the new pie bond here when you're making you buying your break a bond to break the carbon all bond connecting the oxygen. And then you form your second, you know, form with the pie bond here. Now, you see, we have two different in all Todd amours with one being the pie bond to left of the alcohol one mean pie bond, right alcohol. So for be joined to construction items that are not hard rumors, but contain your double carbon bond and your alcohol group. So remember a constitutional ice. Amar has the same chemical formula but differ in their bonding and connectivity. So we need to draw ice. Immers of this molecule has same chemical formula, but different in bonding. But have your alcohol and your Al King bond, so we can actually just use the two molecules that was generated here. So for B, we need same chemical formula. So and he's so have same number of atoms and higher. Jin's auctions and carbons is this, but need. They need different bonding. So the easiest thing you can do is just move over your pie bon so I could move or my pie bond down here, for example. So I'm moving your pie bond, you know, change the connective, it ease of the atom and therefore their Constitution listeners. Alternatively, I could move this one over here. Now I have two different constitutionalism. Er's a different connectivity, but with the same chemical formula, and they satisfied all the conditions. Ask the questions, Stan.

To draw both an anti murders for these two compounds, we need to find the stereo centers to start with. So this compound has a stereo center here with the meth Eliza, different from the Benz Il group, which is different from the mean, which is different from the hydrogen. So the two ways we can draw this are either putting the nitrogen on a witch shone with hydrogen on the dash. Or, if you invert the stereo center, you can put the nitrogen on the dash and the hydrogen on wedge. Since we flipped where the two groups were, those are in anti mers. Mysterious center in this compound is right here because this whole group is different from the methyl, which is different from a carb oxalic acid, which is not the same as the hydrogen. So we cannot to draw this methyl group coming straight out with the hydrogen going back. The other an antimatter has this flips. Blair. You could put the metal group going back and the hydrogen coming towards you on a wedge. You could do some rotations around any of these bonds. You could have put this method group on a wedge or a dash. Same with the car box look, acid. So practice drawing this multiple ways


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