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Particular fruits wcights are normally distributed , grams with mean of 618 grams and standard devatlon of If you plck one fruit at random, what the probability tha...

Question

Particular fruits wcights are normally distributed , grams with mean of 618 grams and standard devatlon of If you plck one fruit at random, what the probability that It will weigh betwcen 622 grams and 636 grams

Particular fruits wcights are normally distributed , grams with mean of 618 grams and standard devatlon of If you plck one fruit at random, what the probability that It will weigh betwcen 622 grams and 636 grams



Answers

The weights of jam bottled by Snyder \& Sons are normally distributed with a mean of 16 oz and a standard deviation of 0.2 oz. If a bottle of this jam is selected at random from a shipment of this jam, what is the probability that it weighs: a. More than 16.1 oz? b. Less than 15.8 oz?

97. We're looking at a normal CVS 5.11 one, five point 291 a mean of 5.2 euro one and a standard deviation. Uh, boy 065 Thank you. US 28 three. The ring. A probability of acceptance. One minus that one minus boy 8338 gives us a point 1662 or rejection, so that proportion will be rejected. If we have 280 coin, I would multiply that by that kinds. 280 gives me 46.5. So that's about 40 seven oil that will be rejected.

In this question here will recall that it will have the X follows the normal arm, the meal and standard division small square. Then we will have X minus mu on the Sigma. You will follow the standard normal Z zone one Here, in this question, were given the X here it will be the amount of milk. So we'll be amount of me. Okay. And then it follows the no more where were given that the meal equal to the 1 28.2 And, uh uh, standard division Sigma ico to this upon to and now want to fight in discussion The probability that the amount on the milk we will stand exhale we will list. And 1 28 here. And the first time we were converted them into the standard division the standard no more by taking the minus meal over sigma. So on the right hand side, we have the 1 28 minus the muna equity 1 28.2 over the Standard Division encroaches upon to then we get this one we decode you Probability doesn't becomes distended no more Now, doesn't Gondola's open to minus seven to over two equal to minus one. Now on the table, this one will equal to the probably it will equal to the 0.5 minus that I after one here. And then we get the coaches upon five minus a one in a timber. We have ICO to jump on 3413 and then we get equal Jew upon five. Minister upon 3413 we can negative upon 1587 on. That's gonna be the answer.

So in this question, 17 were basically told that a golf ball may not weigh more than 1.62 oz. And we're told that the weights are normally distributed with the mean off 1.361 ounces and the standard deviation of point or nine ounces. And were asked for the property that a court ball will meet the weight standards. So that's the probability that the cold fall will not weigh more than 1.62 ounces. So it should be less than 1.62 Converting this to a standard normal random variable, we have the less than 1.6 to minus the mean over the standard deviation, Which is the probability to Z is less than 2.88. And if we look at our table, the value that we get here is .9980. Yeah.

Okay, So machine that and fills court size bottles the avenues average is expected value thirty two points ounces. And the standard deviation is one play. One counts. Okay, so I guess. And we're assuming a normal distribution. Okay, So we really want to look at see values and Okay, first of all ways probably know that one court is thirty two ounces. That's going to be very hopeful Is the first question for a says, find the probability that, uh, the machine fills up in less than thirty two thousand. Well, this is just going to be okay. I need to find it. This's a Z value to remember that our Z value forgiven axe is going to be X minus new over seema. So what I'm going to do here is subtract mu and then divide by signa on both sides of this Inequality says thirty two minus mu. Whoever Seema. And this is really just the probability ze less than how seem negative. Zero point seven three. And this is something we can look up in honor. See, score. Table your point two three to stuff. So, for being you want the probability that X is bigger than thirty three one else more than a quart. And I'm gonna do the same trick. So this is X minus mu over. Cigna Creator Lan in thirty three, minus mu over. Said muff plug in my values for commun signal. Well, this is the faker than Sierra point one eight. And now my Z score values there first for ZIS Less than certain point. So this is the problem. This is one minus the probability that Z is less than or equal to zero point one eight and this is one minus that we look up this p A Z U S and equal to zero point one eight. It's your point five seven one four, which is your point for two eight six.


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