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(Ch 10Problem 10.47Using the values for the heat of fusion, specific heat of water; andlor heat of vaporization, calculate the amount of heat energy in each of the ...

Question

(Ch 10Problem 10.47Using the values for the heat of fusion, specific heat of water; andlor heat of vaporization, calculate the amount of heat energy in each of the following:

(Ch 10 Problem 10.47 Using the values for the heat of fusion, specific heat of water; andlor heat of vaporization, calculate the amount of heat energy in each of the following:



Answers

Given that the heat of fusion of water is $-6.02 \mathrm{kJ} / \mathrm{mol}$ , the heat capacity
of $\mathrm{H}_{2} \mathrm{O}(l)$ is 75.2 $\mathrm{J} / \mathrm{mol} \cdot \mathrm{K}$ , and the heat capacity of $\mathrm{H}_{2} \mathrm{O}(s)$ is
37.7 $\mathrm{J} / \mathrm{mol} \cdot \mathrm{K}$ , calculate the heat of fusion of water at $-10^{\circ} \mathrm{C} .$

Okay This course should be a little long. The heat required to release can be calculated by using heat of condensation. Heat of condensation for one g of water Is equal to 2000 260 jules. The condensation or steam will be, he Equals to 1 25g of water, Multiplied with 2200 and 60. The answer heat released by steam to condense is two 80 Dude. Now we need to find the heat released to lower the temperature of condensed steam To 15°C.. So in condensation there will be change in temperature which is 100° -15°C.. And the change will be 85°.. We have already provided with the specific heat of water. So using the formula heat equals mass, which is 125. Multiplied with change in temperature 85° And multiplied with specific heat which is 4.18 for june's. So the heat required or heat released by water to lower its temperature to 15°,, C will be 44 1000 jules. No next part The total heat energy the least to be calculated by addition of amount of heat released In the above two steps. So total he will be plus 44 123. Total heat will be 10 days to powerful jones. Moving on to part B heat released, moving on to part B. Heat released by steam to condense will be 525g of water, multiplied with 80 calories, which is 42,000 calories. Now we need to find out the heat absorbed. Today's the temperature of liquid to 15°.. So Change of temperature will be 15°.. Using the formula heat equals mass, which is 5 25 g. Multiplied with change in the age of 15° And the heat required will be 7000 800 calories. Total heat will be 42,000 plus 7800 18. And the total heat will be 49,000 900. Now we need to calculate the amount of heat released in kilocalories. So converting 49,000 kilocalories and 49,900 calories into pillow calorie will be one kg calorie is equal to 1000 calories which goes us 49 900. Multiply Red one killer calorie divided by 1000 calories. You go with us 49.9 kilocalories for part C heat will be 85g of water, multiplied with 2260 jewels of energy. Total heat required will be and now we have to find out the heat released to lower the temperature of condensed team 20 So from steam to 0°C,, the change in temperature that is still 30 Is 100°.. It will be 85g of water, Multiplied with 100°C of change in temperature Multiplied with specific heat or 4.184 Heat required will be 36,000 jules. Lastly for the ice. But deal heat will be 85 g of water, multiplied with 334 jewels. And the total heat will 28,000. The heat. The total heat energy needed to be calculated will be The summer of previous three. So total hm is equal to plus 36, 123 plus 28. And the total heat will be 250,000 jules, Converting this 250,000 jewels into killer jewels. Remember that one killer jules is equal to 1000 jones. Heat equals multiplied with one kill a jewel divided by 1000 jewels.

With the data provided for the entropy of fusion and in therapy of vaporization. And in addition, the specific heat of liquid water. You should be able to answer the three questions. The first question I ask, What quantity of energy is required to melt 25 g of ice at zero degrees Celsius if it's already at zero degrees Celsius than any heat that is added, will not change the temperature but simply melt the substance so we'll use the Mohler heats of the molar heat of fusion, which is melting. To answer this question. If we have 25 g of water, we can cover the grams to moles by dividing by the molar mass of water. Once we have moles of water, we can then multiply by the molar heat of fusion of water, and you'll notice that all units will cancel except the energy of killer jewels, and we get 8.36 killer jewels Next. If we have 37.5 g of liquid water at 100 degrees Celsius, any energy will we add will convert it from liquid into a gas. So we need to use the solar heat of vaporization 40.6 killer jewels per mole. To calculate the energy with 37.5 g, we can cover two moles by dividing by the molar mass of water and then multiply by the molar heat of vaporization to convert the moles of water to kill the jewels and we get 84.5 killer jewels. Next, we'll use the heat equation. Q is equal to S M Delta T or the specific heat multiplied by mass multiplied by change in temperature. The mass is 55.2 g of liquid water, which we're going to warm up from 0 to 100 degrees Celsius, so the change in temperature will be 100 degrees Celsius. So we'll take the specific heat multiplied by the mass multiplied by the change in temperature. And we get 23,096 jewels or 23.1 kill the jewels

Yeah. Okay. So this is a question about he. The Furin. So it actually gives the heat of Furin is water and it didn't give the temperature. But we already know that for water actually melt at 0°C. So I actually can write down that 0°C. The heat of the furans. They're actually basically the water which is a solid face, ads zero degrees C. And forms the water as a liquid phase, But also at 0°C. And we know that heat of urine given here where you H. F. One to indicate equals two miners. This is not minus rights actually six .02 kg job more. I don't think there's a minor sign because for water to become liquid water actually is uh uh and or thermic reaction. So hey Furin should be a positive sign. And also this question asks us to calculate the heat of Furin of water and minus degree city. So we can also write down the reactions solid face. The minus dick. We see and converts into the water liquid face And the -10°C. And actually wants us to calculate the heat of urine. Okay, how can we do that? Yeah. So you can see for both states the water soil face, the quest, the temperature and liquid phase also decreased temperature. So then we can actually make two artificial equipments. So let's just write down this as the queen one queen too. How about the questions three, right. When we have water From s equal to 0° C. Becomes a solid water but becomes minus. Did we see what the energy this part of energy, it's three is actually simply equals to the heat capacity of the solid. Because this is a perm or so. We don't have to use mass or more times change of temperature Which is a -10. Did we see? So we can just do the calculation The heat capacity is 30 7.7 Jill for more. Okay. In times the minus key. This equals two 377 Joe for more and it's minus sign. And force. Aquarian is basically the liquid zero degrees C. Went when cool down the temperature it becomes liquid phase. Do but because minus degree C. 10 degrees C. What's the energy involved actually? Is he capacity times a change of temperature. So the heat capacity here is 75.2 Joe for more. Okay, Sometimes -10K. And this equals two 7, 500 & 7. 752 Joe for more and has a minus sign and look at here, you will find actually the equation too is simply equals to the aquarium one over minus aquarium three and minus and a plus the aquarium four. So, you know the equation to which was what we want equals two. Equation 1- Question three Plus Equipment four. So delta age to which F two simple equals two delta H. F. One minus delta age three plus delta H. Four. So wanting to do it just plug in the numbers here. So one is six km open more so 6000 chill and minus gallery H three minus -377 an A plus -752. And we can actually do the calculations now. Mhm. It's around 5.6-7 killed Joe for more. And this is a heater Furin for the water at minus degree C. And this is the answer.

For this question, but a We have to determine the amount of heat energy needed in jewels To melt 50g of ice and Warm the water to 60°C.. So starting with part A one g of water requires 334 jewels of energy. So according to the provided information, he equals mass, which is 50 g. multiplied with 334 jewels program, Which goes to total heat required as 16,000 700 jewels. This is the heat required by ice to melt. Now to raise the temperature until 65°C.. The difference in temperature from the melting point of ice 0° to 65° is 65°.. So the heat required will be equal to mass, which is 50 g. Change in temperature 65°C multiplied with specific heat of 4.184. Heat required will be 13,000 500 98 jewels. This is the heat required to raise The temperature till 65°.. So the total heat required will be 16,700 plus 13,000. Total heat equals 30,000 298 jewels. Or you can say 30,300 jewels too. For part B. The amount of heat energy released in kilocalories To condense 50g of team And to cool the liquid to 0°C.. So one calorie. Sorry, one kg calorie Is equal 2000 calories. The heat provided will be the heat heat needed by steam to condense will be 15g, Multiplied with 540 galleries Divided by one g of water, Multiplied with one kg calorie Divided by a 1000 calories. The heat required will be eight 0.10 kilocalories. No, The Heat released to lower the temperature of liquid to 0°C from steam from steam too liquid at zero degrees Celsius, the difference in temperature delta. T. Will be 100 degrees. So heat equals Mass of 15g, Multiplied with difference of temperature 100°C will be one calorie divided by 1000 calories. One killer gallery. The heat required would be 1.50 kilocalories. Now the total heat required in Kilocalories will be 8.10 plus 1.50. Total heat equals 9.60. Hello calories he'd released will be 100 calories. Moving on to option scene the heat required, we have to determine the amount of heat energy needed in Kayla Jewels to melt 24g of ice And warm the water 200°C can vote again into steam. So heat required will be equal to 24g of water, Multiplied with 334 jewels of energy for one g of water multiplied with one kill a jew divided by 1000 joints. The heat required will be 8.02 Killian jones. And now we need to determine the heat required to raise the temperature of melted ice 10°C Heat equals 24g of water, Multiplied with difference in temperature from melted ice to steam will be 100°.. Multiplied with 4.184 jewels of specific heat, one kg jule Dubai, that by a 1000 utes it goes as then kayla jewels. Now the heat required to change the state of water from liquid to gas can be determined as Multiplied with 2000 260 one kill a jewel provincials 54.2 killer jewels. So the total heat required will be Will be the sum of last three, which is 8.02. Last 10 Plus 54.2 jones. This has been killed jules, kayla jones and kelly jones. It goes as 72.2 killer jewels


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