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Water flows through a 13.0-cm-diameter fire hose at a rate of 4.53 m/s (a) What is the rate of flow through the hosc in Llmin?HTML Editong BI " 4 - A - I = 33 ...

Question

Water flows through a 13.0-cm-diameter fire hose at a rate of 4.53 m/s (a) What is the rate of flow through the hosc in Llmin?HTML Editong BI " 4 - A - I = 33 2 1 X X € = 0 - 8 8 D I0 T Font Sizes Paragraph

Water flows through a 13.0-cm-diameter fire hose at a rate of 4.53 m/s (a) What is the rate of flow through the hosc in Llmin? HTML Editong BI " 4 - A - I = 33 2 1 X X € = 0 - 8 8 D I0 T Font Sizes Paragraph



Answers

(a) What is the fluid speed in a fire hose with a 9.00-cm diameter carrying 80.0 L of water per second? (b) What is the flow rate in cubic meters per second? (c) Would your answers be different if salt water replaced the fresh water in the fire hose?

In this question that tree parts are in part a. We asked to find a fluid speak. Okay, so we've been using huge goes to a B. Okay, so he goes to to you over a So the flow rate it's given to be 80 years put second. So you need to convert two meters Q. So you do not apply by 10 to the ministry. In this area is a cylindrical hose so need to derive its power square. So we need to be right the diameter like to So the diameter is nice. Yem coming to meet us. Your written square conflict you should be getting show quite six euros per second. So this is the answer for a Then be we want to find a slow rate, uh, right to the floor, it in meet askew per second. So it is given to be 80 years, cause second to convert into neither cubes for a second. We just want Justin to divide by 1000. So you get your point. You're eat, uh, cute for a second ski. So this is the answer and proxy with the uncertainty difference. Using salt water, sea water starts water here, so, yes, there is no difference. Okay, so, uh, floor it and velocity, that's not depend on density, so the answer is no difference.

This problem covers the concept of florid and from that concept, the florida equals the speed into the Kazakhstan area. And to solve this problem, fascinated to convert The speed into cm for second and the street given is four 53 meters for a second. And to convert this into centimeters permit we need to multiply it 100 cm four m into 67 seconds, four minutes are the flow speed equals Uh 2.72 into and that's full 70 m four minutes. Now the cross sectional area is buy into the square upon for if we substitute the value, the cross expel area Is by into 13 cm square upon four. So the cross experience area is 133. Send him we just square. Now the floor ID equals The speed. That is 2.72 in. To tenders full centimetres four minutes into the cross extra area. That is 1:33 cm sq and kill equals 3.62 into. Then there's six cm Q4. Mhm. To convert this into meter, we need into leader, we need to multiply with the Lincoln, wasn't factor That is one leader upon uh 1000 centimetres killed for part A. The floor ID equals 3.62 into and there's three leaders for minute. No party. The volume of flow equals the flow rate into the time. T Or the volume equals the floated. That is 6 3.62 In to Tenders three L 4 minutes Into the time and the time is 25 minutes. So the volume of the water lawyers, 9 90,500 leaders. So in 25 minutes the volume flow is 90,500 L.

Hello. So, in this problem, we have a fire. Hodes, Um with a diameter of 6.85 centimeters, that ends with a diameter. Uh uh, 2.2 centimeters and the flow rate through the fire hose Z equal to 0.12 m cube for second. And we were asked to find out the velocity at which the water exits this hose. So what is that? Well, it turns out, since we're just finding out the velocity of it of the water exiting the hose, we don't need to know anything about the diameter of the hose in the beginning because we already know the flow rate, because the flow rate is going to equal to the velocity that exits the hose times the area exits the hose. And what's the area of the exiting part of the hose? Well, it's going to be equal to pi r squared, right? But we writing that in terms of our diameter, we have the 2/2 squared and this rewriting that once more. We have the two pi over for the two squared. So that is equal. Sorry, we're not done yet. We're trying to figure out the velocity. Right? So no solving this for velocity. We should get four over pie D two square times. Que That's right. Right. Ah, Service should be true. Should be on the bottom. Yeah, so for over pi B two squared times. Cute. There you go. And that's our expression. And now let's try plugging in the numbers. We have four over pie times 2.2 centimeters so that 0.0 to 2 m squared times airflow rate which is zero point 012 m cube per second and once you do the computation, you should get 31.6 meters per second.

Solving party of this problem. The total volume is equal to area multiplication velocity. So we a multiplication. A. B. Is equal to be on solving it further. I can write for multiplication 10 to the power managed to multiplication and B is equal to one centimeter and the value of V A. Is equal to 25 centimetres per second. Now, solving part B of this problem. So here I can write the well the city on in the to be let it be VB for a steady flow I can ride a value and be a multiplication. A. Is equal to baby multiplication A. B On further simplification. I can write 25 multiplication, 10 to the Power -2. Multiplication for is equal to we be multiplication to multiplication 10 to the power -2. Going forward and simplifying it. I get the value of baby edge to present a meter purse. Again. Now for party I will use the Bernoulli's equation. So being plus one by two or O V a square is equal to P B plus one by +20 We be square on simplifying it further, I can write P m minus P B is equal to one by two Peru. We b squared minus B a square, Which is equal to one x 2, multiplication, 1000 multiplication .5 sq minus 0.25 p square, which is equal to 94 newton per meter squared as the answer.


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