5

114 h(I,0) = # 31y...

Question

114 h(I,0) = # 31y

114 h(I,0) = # 31y



Answers

Divide. $$-114 \div(-6)$$

Again dealing with parentheses. First three point follow multiplied by minus two is going to be equal to minus 6.8, but we take a positive value. This and get 6.8 on the minus 9.8 stays the same, so 6.8 minus 9.8 is equal to minus three.

So we got 11.9 minus 1.2. So nine minus two here is seven one minus one is zero, and then one just comes down is one. So our final answer is 10.7.

To simplify are given expression. We're going to use order of operations or Pim Dis notice. In this expression, we don't have any parentheses, exponents or multiplication to compute. But we do have division. We're going to compute the division in the order that it shows up when reading the expression from left to right. So the first thing to compute is 112 divided by 28 112. Divided by 28 is four. So we'll bring everything else down for next. Step again. We have another set of division to compute. 112 divided by 28 which again it's for We bring down the rest of our expression for our last step and four minus for equal zero. So we're simplifying are given expression. We're left with zero as our answer

In this problem. I'm being asked us. Attract 1 12 minus 49 in 9 30 seconds. I need a fractional part in order to be able to do this attraction here. So I'm going to borrow one from the 112 and make that 111 and 30 to 30 seconds. Now, I have a fractional part that I can work with when I have 32 30 seconds minus 9 30 seconds. That will result in 23 30 seconds. Borrowing one. I'm gonna leave that with zero, which makes that 11 11 minus nine is to borrowing. One. Makes that zero makes that 10 10 minus four is 6 62 23/32


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