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Pant TanApCalcBr10 22.050 Fndlandi rels foll-rlna Fur te funLon M)-1 AAAliia...

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Pant TanApCalcBr10 22.050 Fndlandi rels foll-rlna Fur te funLon M)-1 AAAliia

pant TanApCalcBr10 22.050 Fndlandi rels foll-rlna Fur te funLon M)-1 AAAliia



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(A) $\mathrm{M}^{0} \mathrm{~L}^{-1} \mathrm{~T}^{-1}$ (B) $\mathrm{M}^{0} \mathrm{~L}^{1} \mathrm{~T}^{-1}$ (C) $\mathrm{M}^{0} \mathrm{~L}^{2} \mathrm{~T}^{-2}$ (D) $\mathrm{M}^{0} \mathrm{~L}^{0} \mathrm{~T}^{0}$

This question asked us to take a look at comparing some salts and the Civic Cat ions that can come from the salts in general. Wasn't really clear entirely what this question was asking for, but I believe we're being um as to determine which is the more acidic solution based on the salts and their concentrations here. So that means the lower ph solution that's going to be more acidic and it's gonna have a higher K. A value associated with it. And so we take a look at this. Um In the first set of examples we have nickel two plus chloride um at the same concentration of sodium chloride, sodium chloride with the sodium cat iron we should know is a neutral cat eye on. So it's not going to contribute any acidic properties at all to the solution. But Nicol two plus can I on has a K. A. Value associated with It's pretty small but nonetheless um will furnish some acidic properties to the solution. And so as a result here, The more acidic solution is going to come from the Nickel two plus here. And that would have um the lower ph overall for the solution as well. In the second set of examples, we have a tin two plus solution be compared to the same concentration of a cobalt two plus solutions. Were comparing tin and cobalt here. So the K value for 10 2 plus is four times channel the negative four for cobalt two plus, it's much lower, It's two times 10 on the negative 10. It's the higher K. A value that's going to give me a more acidic solution or a lower ph. So therefore the Tin two plus with the higher K value will furnish the more acidic solution. In this set of examples.

In this problem. We asked our ass to find the center of mass of this two dimensional system with the masses. 2 8 to 1 and four in the positions. Negative three negative. 100 And negative one, too. In order to find the center of mass, we first need to calculate the center mass in the ex direction, which we will do by calculating the moment in the UAE direction divided by the total mass. Once you've done that, we will calculate the, um, center of mass in the wind direction. Just calculate the moment in the ex direction of over the center of mess. Okay, So calculating Expert, um, the moment of wise calculating by multiplying the masses by the X coordinates. So we have eight times negative. Three plus one time, zero plus four times negative. One all over. The total mass, which is given by eight plus one is nine plus four gives us 13 doing some arithmetic. We can find out that eight times negative three is negative. 24 0 minus forgives us negative. 28 over 13. Now, to find the center of mass in the UAE direction, we're going to take the moment of X, which is the masses times there. Why Coordinates? So we're going to have eight times negative. One plus one time, zero plus four times two all over the total mass, which is still 13 here. Only two are particularly. Get negative 80 plus h, which gives us zero over 13 for our center of mass. Explore why BAR is given by the coordinate point. Negative 28 over 13 from a zero.

In this problem, we were asked to find the center of mass of the two dimensional system with masses 2 34 to 1 in six in the positions. Negative too negative. Three 55755100 and negative 30 In order to do this, we'll need to calculate both this center of mass in the extraction, which is given by the moment of why, over the total mass and then the center of mass in the UAE direction, which is given by the moment of action over to the trouble of mass First calculating X bar, the moment of wise given by each of the masses. Times there X coordinates allotted together so we can find that by three times negative too, plus four times five plus to turn someone plus 1 10 1 zero plus six times negative three all over the total mass is going to be three plus for someone close to his nine plus one is 10. Post six gives you 16. So doing some arithmetic we get three times a year to is negative. Six plus 20 is 14 plus 14 is 28 poses zero post negative 18 is going to give you 10 over 16 or 1.6 now to find the center mass in the wind direction, we're going to find Calculate the moment of X, which is given by the masses times there y components. So we have three times negative. One negative, three plus four times fine, but two times one plus one time zero was six times zero all over the total mess, which is still 16 now doing our athletic three times three makes nines with negative nine plus 20 which is this 11 plus two gives his 13 and both of these terms to goto zeros. We get 13 over 16. So are finally answer is export y bar it wa ce 10 over 16 comma 13 over 16.

In this problem, just look at it carefully. BB I too, will react in pageants of BSE here, too. ECU was to give compound Are we change which aid 80 cl here, which it A d c L. Here? So this is white PPT. They said white PPT. Therefore, according to the option option, age, correct and said for this problem, A d c l a will be the white PPT in this problem.


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