Question
How many mL ofa 0.10 M NaOH solution are needed to neutralize 15 mL ofa 0.20 M H PO,solution? 3 NaOH(aq) + H,PO (aq) Na,PO (aq) + 3 H,O()Assuming H,PO, is triprotic, how many moles of H* ion are present in 15 mLsof 0.20 M H,PO?How many moles of NaOH are needed to neutralize the H,PO;?How many mLs ofa 0.10 M NaOH solution will neutralize 15 mLs ofa 0.20 M H,PO, solution?
How many mL ofa 0.10 M NaOH solution are needed to neutralize 15 mL ofa 0.20 M H PO,solution? 3 NaOH(aq) + H,PO (aq) Na,PO (aq) + 3 H,O() Assuming H,PO, is triprotic, how many moles of H* ion are present in 15 mLsof 0.20 M H,PO? How many moles of NaOH are needed to neutralize the H,PO;? How many mLs ofa 0.10 M NaOH solution will neutralize 15 mLs ofa 0.20 M H,PO, solution?
Answers
What volume of a $0.3300-M$ solution of sodium hydroxide would be required to titrate 15.00 $\mathrm{mL}$ of 0.1500 $\mathrm{M}$
oxalic acid?
$\mathrm{C}_{2} \mathrm{O}_{4} \mathrm{H}_{2}(a q)+2 \mathrm{NaOH}(a q) \longrightarrow \mathrm{Na}_{2} \mathrm{C}_{2} \mathrm{O}_{4}(a q)+2 \mathrm{H}_{2} \mathrm{O}(l)$
This question reviews acid base reactions where you need to predict the stock geometry associated with the strong acid, strong base reactions and then use that stoy geometry for a unit conversion as if it were a tight trey shin problem. Hi. Trading the acid with the strong based sodium hydroxide for the first one, we have HCL reacting with N a. O. H. And the stock geometry is just one toe one, as shown in this chemical reaction because there's just one hydrogen on H c l and N a o H can accept just one hydrogen, so we'll convert our 10 mil. Leaders of HCL toe leaders convert the leaders of HCL two moles HCL using the molar ity of HCL, then moles HCL two moles n a o. H. Choosing the stock geometry of the reaction one toe one than moles N a. O. H. Two leaders, anyway choosing the molar ity of N a. O. H. 00.1 Moeller and then leaders n a O h two mil leaders and we get 5.0 mill leaders n a o h For the next one. We have 25 mil leaders of a 0.1 to 6. Mohler Nitric Acid solution Nitric acid just has one hydrogen, so the stoy geometry is one toe. One, just like HCL, will convert the 25 million leaders. Two leaders the leaders than two moles of nitric acid, using the polarity of nitric acid and then moles. Nitric acid two moles, sodium hydroxide. Recognizing the stoy geometry is one toe one as I described, and then moles sodium hydroxide to leader sodium hydroxide solution. Knowing that it's polarity is 0.1, Moeller and then leaders sodium hydroxide solution to Miller leaders by multiplying by 1000 31.5 mil. Leaders N a o. H for the last one. The only difference is the stoy geometry. So sulfuric acid has two hydrogen for every one h two s 04 So the stoy geometric relationship is two Moles of sodium hydroxide are going to be required for one mole of sulfuric acid because sodium one mole of sulfuric acid could only neutralize one mole of hydrogen. But one mole of sulfuric acid has two moles of hydrogen, so we'll convert are 50 million leaders, two leaders, our leaders than two moles of sulfuric acid using the stock geometry of sulfuric acid and then mold sulfuric acid. Two moles any. Oh, wait. Recognizing the 2 to 1 relationship and then moles N a O H two leaders N a O. H. Using the polarity of any O. H. 00.1 Moeller and then leaders to mill leaders 215 mL N a O. H.
We have a tie, Trey Shin problem when we have a massive based filtration. So it takes 10 milliliters to tie trade 23.31 milliliters of second line drugs that we know the concentration of asset. But we don't know the concentration of the base and we're gonna try and figure out when you're doing a NASA debates. I Trey Shin, you can lose a common tree, which should be the easiest way to do this one way to do it. But there's an equation that works with the asset base situations that works faster than moon stick. It is just like in an equation. So that is M E V A, which is the majority of asset times. The volume of acid divided by the moles of acid is equal to MB vb the bottle by nb which is the malaria base times the volume of the base divided by the moles of the base. Those end means the coefficients doesn't mean little messages means coefficients. So M is Marty. V is volume and end will be our core efficient. So we have the volume of the asset. The wire you have acid. The number of coefficients for That's it is just one. We have the willing with the base. We're looking for the Malalai ity of the base. And then the coefficient of the base is a two. So we plug it in em a this 0.10 12 more volume over the asset ist sind milliliters. Cliff vision of as it is one and then And bees were looking for something to leave it. Is that so? You know, I'm looking for similar to the base volume of aces 23.31 milliliters and the corporation of the base is too. So then we're gonna multiply. I want to buy right to divide by 23.31 to get MB and then you get 0.8 and we need 46646 rates everything to be supported. Fix so 86 83 Moeller is similarity of your base
This question is a tie, Trey Shin problem where you need to understand this, like geometry between a strong acid and a strong base. And then also recognize what conversions air involved when you're going from milliliters of a based solution to milliliters of an acid solution. So for the first part of this problem, part A, we have 45 million leaders of K o. H, which we can convert toe leaders. Then, knowing the mole arat e of K o h, we can convert leaders two moles K o. H. And then this is where we need to recognize the stoy geometry between K o H and H N 03 One mole of K o. H reacts with one mole of h N 03 because K o. H can take on one hydrogen because it has 10 h and H and 03 can donate one hydrogen because it just has one hydrogen. So the stoy geometries oneto one. Then, when we know the moles of H n 03 we can use the mill arat e of h n 3.1 Mueller to get leaders h n 03 solution and then convert leaders to mill leaders. 300 mL. Nitric acid. For the next one, we have 58.5 mil. Leaders of a 0.1 Moeller aluminum hydroxide solution will convert the mill leaders, two leaders and then the leaders. Two moles by multiplying by the molar ity. 20.100 molds aluminum hydroxide per leader. Then, when we know the molds aluminum hydroxide, we recognize that the stoy geometry is 3 to 1. Hydrogen could only donate are in sorry. Nitric acid could only donate one hydrogen, but each aluminum hydroxide has three hydroxide so it can accept three hydrogen. So for every one mole of aluminum hydroxide, we need three moles of nitric acid. Then, when we have moles nitric acid, we can convert to leaders nitric acid solution. Using the polarity of the nitric acid. 0.1. Mueller and then leaders to Miller leaders. 17.6 million liters. Nitric acid. For the last one, we have 34.7 mil. Leaders of a 0.775 Mueller sodium hydroxide solution will convert the mill leaders two leaders and then leaders two moles by multiplying by theme Olara Ity of sodium hydroxide. We recognize the stoy geometry between sodium hydroxide and nitric acid is one toe. One when we have moles, nitric acid. Then we can convert toe leaders nitric acid solution by dividing by the molar ity 0.1, and then go from leaders to mill leaders by multiplying by 1269 mil leaders nitric acid.
When calculating polarity of sulfuric acid by knowing smalls and dividing it by its leaders. So polarity sulfuric acid is simply most sulfuric acid divided by leaders. We can calculate the most sulfuric acid by taking the volume of sodium hydroxide that was required to react with sulfuric acid, converting its leaders and then converting the volume, or the leaders of sodium hydroxide to moulds, sodium hydroxide using the polarity of sodium hydroxide. Then we recognize the story. Geometry of the reaction has given to one to mull sodium hydroxide required for everyone. Mold that sulfuric acid that then gives a small sulfuric acid in our numerator and the denominator. The volume that was tight traded was 20 milliliters. Sulfuric acid will convert that to leaders by dividing by 1000 that then gives us similarity of 0.234 molar sulfuric acid