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Horizontally polarized light of intensity lo is passed through two filters: the first angled 452 and the second vertical filter. Draw visual representation of the l...

Question

Horizontally polarized light of intensity lo is passed through two filters: the first angled 452 and the second vertical filter. Draw visual representation of the light as it is passing through these filtersWhat = fraction of the Original light is left after passing through both filters?

Horizontally polarized light of intensity lo is passed through two filters: the first angled 452 and the second vertical filter. Draw visual representation of the light as it is passing through these filters What = fraction of the Original light is left after passing through both filters?



Answers

Vertically polarized light passes through two polarizes, the first at $60^{\circ}$ to the vertical and the second at $90^{\circ}$ to the vertical. What fraction of the light gets through?

Hi in this given problem. First of all there is a vertically polarized light. So this is supposed this is representing a vertically polarized light. Then there is a polarizing filter. The first polarizing filter whose axis is inclined at an angle of 30° with the vertical. Then another polarizing filter. The second polarizing filter whose access is inclined at an angle of 75° with the vertical. Here this is 30 degree and this is 75 degree. So we can say the axis of second polarizing filter. This is inclined at an angle of Nearly 45° from the axis of the second polaroid or second polarizing filter Here, this is Stephen and here this is P two. So most of all in density of vertically polarized light That is I not is equal to 400. What parameter is square? Mhm angle between the first and the second on rising filters that will be suppose it is to tattoo that theater will be 75 degree minus 30 degree. Since this is a 45 degree and angle off the first filter from vertical. This is theta one is equal to 30 degree. Now using the law of malice intensity of light coming out of the first polaroid polaroid or polarizing filter that will be given as Ivan is equal to I not course square T. Dublin and debt coming out of second filter. That will be given us I too is equal to are one course squared heat too. Or we can say if he plays if he put the value of Ivan also here, that is not Causes Square 2-1 causes square T. Tattoo. So finally plugging in all the known values here Or I not. This is 400. What parameter is square then courses square 30 degree And then cause a Square 45°. So here it is 400 watt per meter square. The first bracket is square, of course 30 degree means rule three. Why to having a square of it? Second bracket cost 45 degree one. By route to I've got square of it. And finally it will come out to be. I do is equal to 150 What perimeter is square. This is the intensity of the finally emerged light coming out of the second polarizing filter, which is one of the answer for this given problem. And this light is polarized At an angle of 70 Dick, 75° from vertical, which is another answer for the same given problem. Thank you.

This problem. We have a picture off all rice and a polarized light. So let's call the intensity off. All rights part of the light I zero and the, um, polarized light. It's one of our more minus half idea such that they initial intensity off the being has a somewhat notorious zero is the number of between zero where well, and this being a flight he toe toe Aah! Polarization sheet and the intensity transmitted by the shit intensive d'oh for the polarized light with the pain of the angle between them. So it will be asked, I zero call sign square Peter, that I am gonna be pinned down. And for the employees like to just be half of the intensity so half off war minus f I do. I will say that the when we rotate the future while keeping preclinical to the being the transmitting intensity varies by a factor of five. So, in any point in the in the rotation doff this angle tear the intensive devised by a factor of fine. So because co sign of terror square varies between so co sign Data square various beating zero at what? So the minimal off this function here. So that's right. The minimal Manimal will be when this guy zero. So this will be 1/2. Well, nice f I zero and the matter more of this function will be wearing co sign squared goes one Max iss, huh? I do. Plus 1/2. Well, my f zero. This is well, 1/2 Wow. Plus, yes. Zero. Now we say that the racial between the maximum on the minimal is five. So let's does this ratio. So the ratio between Max a minimal it is a bit of five. And if you write, the racial will be one plus f but by one minus f hoping these we get the Is there a 0.67? So we know the portion off polarized and, um, polarized light associating tow this big

Everyone, This is the problem based on concept. Off my loose look that transmitted intensity off transmitted light through the Polaroid is called toe intensity off incident light into causes square theater. In this problem, it is given there are two Paul writes. One is vertical people and then there is horrid gentle That s p two when transmitted and when incident light to top even is unpolished, right? Then pulled a slight troop Evenness I not but transmitted light through p two is zero if a third polar right it placed between the two so that it makes 45 degrees with vertical Be through that we have to fight. What is the transmitted Instant intensity. Now let us see it. Transmitted intensity through B three will be I P one transmitted in tow causes square future. That is I not causes squared off 45 That is I not by two not transmitted light through p two Bilby i Petri a and tow causes square off 45. So I'm not quite too and tow one way route to square. So it becomes I not wait for that's all. Thanks for watching it

In this question we have been more partially polarized light. Mhm. So actually on the bright lights nothing to polarize that. Okay. And then transmit the light is Yeah then so we are going to treat them partially polarized like this. Uh Yeah some Mhm. And polarized light. Yes. Uh Some partially polarized liked some uh polarized elect. He. So um and so there's some fraction of um polarized light and some fraction and the rest the remaining will be authorized. So in the intensity original intensity we can uh let's say we have one minus F. I know they have. I know because this question we want to find the fraction of the intensity of the original being associated to polarize. Like. Yeah. Which is why we put F onto the Alright slate. Right? So um we are given that uh uh I am ex good bye bye. I mean okay when the polar zero taste by 260 degrees. This ratio of this factor five. Okay so uh we need to first find a transmitter intensity. Okay, so for the un polarized line is just going to be half okay. Uh or did you know him of the intensity? And then for the polarized one half times I know besides square data key. So the cause I square data. Yes. Uh huh. Range from 0 to 1. So this gives us our I mean mx So I mix is equal to half times one minus F. I know. Class F. Not so get. Uh huh. Times one plus F. I know. Okay. And then I mean because I inscribe data is equal to zero. There we have half times one minus F. I know. Okay. So I'm actually I mean he would then be one plus ft by by one minus F. And this is equal to five. Okay, so just so for F. Yeah. Okay. Your 0.67 Right, so this is the answer for this question and that's all.


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