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Sketch the structure of the major the product which would be afforded by the following reaction H LDA(2) Cl...

Question

Sketch the structure of the major the product which would be afforded by the following reaction H LDA(2) Cl

Sketch the structure of the major the product which would be afforded by the following reaction H LDA (2) Cl



Answers

Draw the stereoisomers of the major monobromination products obtained from the following reaction.

This question asked us to draw all the stereo I summaries of the major modern termination products from this reaction. So it don't notice. We have to Bethel groups taking off of this ring right here in here. So we're going to get the grooming of both of those positions because they both have tertiary hydrogen is and, as we know, burning a super super specific. So if we put the bro mean, um, on this top carbon first we have the bro me down and leave the Michael up, or we can put the metal down and have the broom eaten up. So there are two and Nance humors from this abomination position, or we can put it next to the other methyl group down here. Um, and then again, we can put the broom in either up or down. We're not going to touch the other methyl group because that is not reacting in this case. But there are also two and anti MERS from this position. So there is a total of four stereo. I simmers for this reaction

This question asked us to drop the structures of the products obtained from this reaction. So here we have a tertiary leaving group with iodine right here and a weak base. Weak nuclear file with the method. Also, we're gonna have an S and one or e one reaction eso for sn one products. I'm going to copy the structure. It was really hard to draw. We have two different possibilities here since s and one goes through a cargo cat. I and we can either have the stereo chemistry, stay the same. Which would look like this where we just replaced the the iodine in the same position with the meth Oxy group. Or we have hysteria, chemistry, flip which would look like this so that we have to an anti MERS possible for this s and one product. And then for e one, I'm gonna draw like this cause it's just a little bit more accurate. We also have two possible products for the E one reaction. So we can either have the iodine eliminate this direction or to this direction. Um, either one is going to we'll get we'll get about the same amount for either one because they're both equally substituted. We will not hell over go up onto the method, the muffled group. Because that will not be very substituted. So are medical group is right here on this structure. So we can either have the double bond up here or down here. There are two e one products.

Most rejected Al Qaeda light and strong basic reaction condition favor elimination reaction. There is less of shooting l clear light with the strong nuclear file. Priefer substitution Reaction Question sixty A From Chapter eight, The substrate is to serious alight and the reaction medium is highly basic with a bulky peas this favor elimination over substitution. So this product other than this product elimination product will be favored. Maser product would be the most suspicious and more substituted hell king the sub status family Helen and then and direction condition is strongly nuclear. Filic primary alight with strong clear feli condition Favors sento over l ignition reaction so the product would be a suspicion Productive, not the ignition. This is a tertiary, Helen. Yeah, under strong basic condition. So it will favor elimination over any substitution Porter, But Mr Product would be most shooted Elke Okay, most ofthe uses a cane. Our prudent, technically more unstable this favor part substrate. In this question, it's second relayed. Secondly, her light can undergo either elimination reaction or substitution reaction depending upon reaction condition. In this case, I would die in negative is a weakness. But ah very could nuclear file this this reaction will favor substitution over elimination. So any animation production, I wouldn't be a minor product and Mr products her the substitution product.

Hi audience. So in this question they asked consider the following reaction, identify the structure of the major product X. So at all, in this case, option B is correct. Option We is correct according. Yeah. So CH three CH B, Ch CH three, CH three plus. We are about giving CH three C h b. Then see CH three CH three plus. It should be. Uh This is because because there is still a carbon free medical, tertiary carbon free radical B is more stable, more stable and is the major block and it's the major product, thanks.


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