4

(h) The function has no smallest value over any open interval S0 there no rolative minimum: Tne relallve maxlinum of the graph Is where f(x) =Fx) = 3 whiere X =(Use...

Question

(h) The function has no smallest value over any open interval S0 there no rolative minimum: Tne relallve maxlinum of the graph Is where f(x) =Fx) = 3 whiere X =(Use corima t0 separate answurs as needed )() Is {(2) posilive Or negalive?Posiliva Nagallve

(h) The function has no smallest value over any open interval S0 there no rolative minimum: Tne relallve maxlinum of the graph Is where f(x) = Fx) = 3 whiere X = (Use corima t0 separate answurs as needed ) () Is {(2) posilive Or negalive? Posiliva Nagallve



Answers

The linear function $f(x)=a x+b, a \neq 0,$ has no minimum value on any open interval.

For this video we're going to look at whether a functions graph attains an absolute men over an open interval for two different situations. So now for our first graph our Y equals F of X. In part A. It's an open interval. So I have open circles at both the left endpoint A. As well as the right end point B. And then as I look through from left to right I see that and then follow the curve. I see that's coming off the open circle and the function is decreasing until it gets to this output of um my function value where it's filled in. So that's a function value that's attained. And then the second piece of it has an open circle above which it has to because our graph has to follow the vertical line test. So I already have a wide output at an X value. I can't have more than one and then goes up to an open circle. So right at this place where the function values decreased to it and it attained that lowest y output. You scan your eyes from bottom to top. The lowest point you would hit. Is that building dot that the arrow is pointing to? That is your absolute men. Yeah, yeah. Of the function on that open interval. So this is yes. The function does F of X does have an absolute men. Mhm. Mhm. Over the open interval between A and B. Now let's look at the next curve. So here as I look from left to right and follow the curve. It goes down to an open circle. So the function is not defined there. I get lower and lower values but I don't have a lowest value that's obtained and then the place in which the function is a function value is higher in the curve then where the function values are approaching that open circle, so there's no lowest value for it. Remember lowest value is as you scan from bottom to top, there would be an attained lowest value that you would hit before you hit the rest of the grass. So this one is no um the function F of X does not have. Yeah. Uh huh. An absolute men? Okay. Yeah. For the open interval between A. And B.

In this video, we are going to discuss whether a function has an absolute min over an open interval if given the graphs of the function. So here I have two different graphs. Part A is the graph where we have our open circle at the function at the left end point come up what would be the function value And that's because it's an open interval. So the left endpoint is not included in the interval and then I also have the same sort of scenario at our right, which is our being. And then in the interval there is a place where the function looks like it's going to possibly attain an absolute men but the function is not defined at that bottoming out point. So this one in particular does not have an absolute men because while you can get closer and closer and closer and closer to the wide output of that open dot, you can never attain it. So there's not a specific lowest wide value that can be attained by running an X value in that open interval. Um So there is no absolute men um for our half of x in our open interval between A and B. How about part B will in part be the diagram looks very similar However, at this point in which the function, the graph of the function is at its lowest value. It actually is a filled and dot meaning the function is defined there. So there will actually be a lowest output for our function throughout that interval at that particularly defined point. Mhm Yeah. Mhm. Mhm. Mhm. So this is, yes. Um This function has an absolute men, yeah. Mhm. For that open inter bone between A and B.

Mhm. I hate it. In this video we are going to discuss whether a functions graph read um attains an absolute men over an open interval for two different graft functions. So here in part a. We have the graft function like well affects where it's the open interval again. So my function is not defined at A. So I have an open circle there. The function is not defined at B. So I have an open circle there. But then the output of the function values decrease as your X. Values go between A. Up to but not including B. And so while the function value outputs are getting smaller and smaller and smaller they're not attaining a smallest value. So for example let's just hypothetically say that this was approaching a Y output value of say one. As I look from left to right and follow the curve. It's why outputs would be getting closer and closer to that Y output of one but not attaining it. So like 1.1 1.01. 1. So I'd never get that value of an output of one. But it would be getting infinitely close to it but it never attains an um an absolute men over the interval. So this one is no absolute men for that function mm on that closed or on that open interval. Now let's look at the next one here. I have a very similar situation except in the interval there is a particular X. Value of C. Such that the function isn't defined in the span of it going across. The function actually is defined to be an output. That's the lower of all of the other graph for my wife will F. Of X. So actually for this one we have that the output why coordinate at that function at that input of. See that output function value is a smallest function value that attains throughout the entire interval. So this one does have an absolute man. Yeah on that open interval now if that would that would have been higher and been within the span of the output of um that it's approaching for B. And the um rest of the curve than we would not have had an absolute men. But this data is lower than the rest of the graph. So its output is the absolute mint of the function. And it occurs at our X. Value of C. So This one is yes it does attain. Mhm. Uh huh. And absolute men okay. On the open interval between A. And B.


Similar Solved Questions

1 answers
(a) 2 points possible (graded)Let X1, Xn be i.i.d. Bernoulli random variables, with unknown parameter p e (0, 1) The aim of this exercise is to estimate the common variance of the XiFirst; recall what Var (Xi) is for Bernoulli random variables.Var ( Xi)Let Xn be the sample average of the Xi ,seiZx; i=l
(a) 2 points possible (graded) Let X1, Xn be i.i.d. Bernoulli random variables, with unknown parameter p e (0, 1) The aim of this exercise is to estimate the common variance of the Xi First; recall what Var (Xi) is for Bernoulli random variables. Var ( Xi) Let Xn be the sample average of the Xi , se...
5 answers
Let V = R3 be equipped with the usual dot product, V1 = (1,1,1)_ U2 = (1,2,3) , U3 = (1,0,0) , and B = {v1, U2, Us}-(a) Show that B is a basis for R3 (b) Consider the operator T € L(R?) given byT(x,y, 2) = (3x 5y + 32, -y + 22, ~ -3y + 42) .Compute the matrix M(T,B). Apply the Gram-Schmidt orthogonalisation procedure to B to produce an orthonormal basis B' for R3_ (d) Compute the matrix M(T,B')-
Let V = R3 be equipped with the usual dot product, V1 = (1,1,1)_ U2 = (1,2,3) , U3 = (1,0,0) , and B = {v1, U2, Us}- (a) Show that B is a basis for R3 (b) Consider the operator T € L(R?) given by T(x,y, 2) = (3x 5y + 32, -y + 22, ~ -3y + 42) . Compute the matrix M(T,B). Apply the Gram-Schmidt ...
5 answers
Homework: HW 11 (10.1,10.2) Score: 0 of 1 pt 10.2.7Test the hypothesis using the P-value approach. Be sure t0 verify the requirements of the test. Ho: p= 0.3 versus Hy: P>0.3 n=200; * = 65; a =0. Click here_to view_page_ of the table Click here_to_view_page 2 ofthe_table; Calculate the test statistic, Zo'(Round to two decimal places as needed )
Homework: HW 11 (10.1,10.2) Score: 0 of 1 pt 10.2.7 Test the hypothesis using the P-value approach. Be sure t0 verify the requirements of the test. Ho: p= 0.3 versus Hy: P>0.3 n=200; * = 65; a =0. Click here_to view_page_ of the table Click here_to_view_page 2 ofthe_table; Calculate the test stat...
5 answers
What is the pH of an aqueous solution with hydroxide ion concentration of [OH-] = 3.3 x 10-6 M?pH =
What is the pH of an aqueous solution with hydroxide ion concentration of [OH-] = 3.3 x 10-6 M? pH =...
5 answers
16.3.32-Setup & SolveFind the volume of the following solid The solid bounded by the paraboloid z =28 - 6x7 6y2 and the plane z=22Set up the double integral, in polar coordinates, that is used to find the volume.drdu(Type exact answers_
16.3.32-Setup & Solve Find the volume of the following solid The solid bounded by the paraboloid z =28 - 6x7 6y2 and the plane z=22 Set up the double integral, in polar coordinates, that is used to find the volume. drdu (Type exact answers_...
5 answers
Mnc sgment has endpoints A(7 - Iand B(-3,J) Whal E are the coordinales of the midpoint of TD" (1,21 B) (2.10 0-5.2) D) (5.2)
Mnc sgment has endpoints A(7 - Iand B(-3,J) Whal E are the coordinales of the midpoint of TD" (1,21 B) (2.10 0-5.2) D) (5.2)...
5 answers
Afrm wants t0 estimare thc rate orfertve Ktr: prooured02no ozjJnJIcrel 0r9"
Afrm wants t0 estimare thc rate orfertve Ktr: prooured 02no ozjJnJ Icrel 0r9"...
4 answers
Which question statement best describes the aim of Event Tree Analysis? How could this failure happen? What are the consequences of a given failure? What aspects of the system should be focused on to improve safetylreliability? What are the different sets of events which cause the system to fail in a specified manner? What can be done to reduce the likelihood of an undesired event? None of the above
Which question statement best describes the aim of Event Tree Analysis? How could this failure happen? What are the consequences of a given failure? What aspects of the system should be focused on to improve safetylreliability? What are the different sets of events which cause the system to fail in ...
5 answers
(a) Let {Si C R} be nonempty collection of subrings of R_ Show that (i Si is subring of R (b) Suppose S is subring of R, and R is a subring of T Show that S is a subring of T.
(a) Let {Si C R} be nonempty collection of subrings of R_ Show that (i Si is subring of R (b) Suppose S is subring of R, and R is a subring of T Show that S is a subring of T....
5 answers
QUESTION 13Which sample(s) gave positive result for the 2,4 DNP test? pay spedal attention when the copper solution first added. tert-butanolformaldehyde cyclohexanoneacetoneTne unknown
QUESTION 13 Which sample(s) gave positive result for the 2,4 DNP test? pay spedal attention when the copper solution first added. tert-butanol formaldehyde cyclohexanone acetone Tne unknown...
5 answers
The solubility of magnesium fluoride; MgFz: in water is 1.5 10-2 g L. What 13 the solubility (in grams per liter) of magnesium fluoride in 0.11 Mof sodium fluoride; NaFSolubilityg L
The solubility of magnesium fluoride; MgFz: in water is 1.5 10-2 g L. What 13 the solubility (in grams per liter) of magnesium fluoride in 0.11 Mof sodium fluoride; NaF Solubility g L...
1 answers
A rocket consists of a right circular cylinder of height $20 \mathrm{m}$ surmounted by a cone whose height and diameter are equal and whose radius is the same as that of the cylindrical section. What should this radius be (rounded to two decimal places) if the total volume is to be $500 \pi / 3 \mathrm{m}^{3} ?$
A rocket consists of a right circular cylinder of height $20 \mathrm{m}$ surmounted by a cone whose height and diameter are equal and whose radius is the same as that of the cylindrical section. What should this radius be (rounded to two decimal places) if the total volume is to be $500 \pi / 3 \mat...
1 answers
3). (Grifliths 3.23) The Hamiltonian for a certain two-level system isH = e(le1) (e1/ = le2} (e2l + le1) (e2l + le2) (el)where |e1) and |ez} are the orthonormal basis vectors and € is a number with the dimen- sion of energy: Find the matrix H as well as its eigenvalues and eigenvectors as a linear combination of |e1) and |e2)
3). (Grifliths 3.23) The Hamiltonian for a certain two-level system is H = e(le1) (e1/ = le2} (e2l + le1) (e2l + le2) (el) where |e1) and |ez} are the orthonormal basis vectors and € is a number with the dimen- sion of energy: Find the matrix H as well as its eigenvalues and eigenvectors as a ...
3 answers
Df Ak 0 Aloas_bulo4 hhich CAlssts 5nJtos UGid Ptodadl To deckask ?A 64sttl Klascd_{am 6_Cells_ BlocKiw) VASLnUv{ b+k_StuL Lauu PHL j #ch
Df Ak 0 Aloas_bulo4 hhich CAlssts 5nJtos UGid Ptodadl To deckask ? A 64sttl Klascd_{am 6_Cells_ BlocKiw) VASLnUv{ b+k_StuL Lauu PHL j #ch...
5 answers
Usc the mcthod cylindrical shells = find thc volume V of tne solid ootaincd 1272rotatino che reqion coundedthe alven cunves about the X-arls
Usc the mcthod cylindrical shells = find thc volume V of tne solid ootaincd 1272 rotatino che reqion counded the alven cunves about the X-arls...
5 answers
The sum of two numbers is 104 Their = 'difference is 6. Find the numbers: Provide your answer below
The sum of two numbers is 104 Their = 'difference is 6. Find the numbers: Provide your answer below...
5 answers
Nare the following reaction type:CHa (s) + 2 02 (g) ~ COz (g) + 2H2O (g)combustionMore than one of the abovecombinationdecompositionncutralization
Nare the following reaction type: CHa (s) + 2 02 (g) ~ COz (g) + 2H2O (g) combustion More than one of the above combination decomposition ncutralization...

-- 0.021646--