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Determine the volume (in L) of 0.0766 M NaOH required to neutralize 5524 mLof0339 NaOH MH3PO4...

Question

Determine the volume (in L) of 0.0766 M NaOH required to neutralize 5524 mLof0339 NaOH MH3PO4

Determine the volume (in L) of 0.0766 M NaOH required to neutralize 5524 mLof0339 NaOH MH3PO4



Answers

What mass of $\mathrm{NaOH}$ is needed to neutralize $34.50 \mathrm{~mL}$ of $0.1036 M \mathrm{HCl}$ ? If the $\mathrm{NaOH}$ is available as a $0.1533 \mathrm{M}$ aqueous solution, what volume will be required?

If we're trying to reach a target ph of 4.7 and we have a solution that contains hydrogen oxide late and we're adding sodium hydroxide. We need to convert some of the hydrogen. Um, well, I guess the hydrogen aqsa late to just pure aqsa late to see 204 tu minus. So that means will be working with the PK A to because we will have stripped off all of the hydrogen is and will have some concentration of just Oxlade present. So our target ph is 4.7. We're gonna use K two. So the negative log of K two in order to get p K two will still have a buffer solution. So we're using the Henderson hassle Baulch equation and the moles of the base. The base being the completely, uh, um deep throat nated form of oxalic acid or just the Oxlade itself. Um, we need to because we're just starting with h c 204 minus than when we add the any o. H. We're making the Aqsa late so we don't have any aqsa late to begin with. And every mole of sodium hydroxide that we add will make a mole of the ox late. So we have an unknown amount of sodium hydroxide that we need to add, multiplied by the concentration of sodium hydroxide to get the mold sodium hydroxide, which will then correspond to the moles of Oxlade formed. But we already have some H c 204 minus, which we can calculate by taking the volume and multiplied by the molar ity. And for every mole of sodium hydroxide we add, we will decrease the moles of the H C 204 minus by that same amount. So the rest is just algae breath will do some rearrangement. Collect are like terms after collecting are like terms. Well, then solve for X. So the first step I did here was I simply took the negative log of this and then moved it over and then took the anti laudable sides. And I got this that I multiplied both sides by this denominator down here and 10 to the 100.56 is 3.21 than the Multiply it by the denominator will still have this over here is our numerator and we get this equal 2.12 times are 0.1 to 0 x. Well, then collect are like terms. I'll, um, ad 0.385 x double sides and then divide herbal sides by 0.505 may get 0.635 leaders or converted to mill leaders is 63.5 milliliters.

So we have 25.0 g of any O. H. Or given the polarity. So we need to convert to moles in order to work with it. Using molar mass. We know that one mole contains 40 point programs of n a O H. And then the polarity says that there's 00.123 moles in one leader. We want the result in millimeters. We could put 1000 mL instead of a leader. So 1000 mL contains point 123 Yes. And then grams cancels out with grams. Most cancels out with moles. And we'll get the associated number of metal leaders 25 divided by 40 times 1000 divided by 0.123 Cool. Is equal to 5000 and 80 millimeters or over five liters.

In this question, I will solve the eighth step by step. First of all, we must calculate the H A post a formal Give us that bee etch equal to boy warm, fine. So the concentration off each postive to gives his be EJ is equal seven points a times. Might EMB or negative three which we calculated eight from the laws of the concentration off each postive is equality. Our negative is that value off the edge. So the concentration off he's a chip postive is represent. Then concentration off each a postive come from C h E C L Times, boys, The initial volume off a cheesy and blast. Is that concentration off Richie negatives that come from in In which times of ivy, too divided buys of Iwan blasts V two. So here we have the concentration is all going to end. The volume is 100 and a concentration. He's 115 times by Tim Bauer. Negative too, and a veto is require. So here stories is fine. So here's a V one is 500 and, uh, Vito is on. So now we have a question on Lee containing one which we want so we can solve it on the phone with. We will times his value by all value it. So when we times his number by 500 the result will be 3.54 lost 7.8 times fighting born negative three for Vito, which is equal open two times 55 hundred's equal 100 plus year. One boy in five times by timber. Negative to V two. So now to continue solving, we will move these here by negative sign and moving these year. Boy. Negative sign. So here, I'll certainly we have here. So you're here is negative? No Positive. So here is negative. So we will move these to this direction by negative and move these year toe other The election by negative. So now we have a full week. Negative, Monty. Six point for sexy Zeke won't negative 22 points here. Way times fighting born negative three v two. So now we were goes is in other direction to come, please. A veto which will equal 3 4006 a 40060.66 Milli leader. Thank you

Here, we're using the following equation. V one. M one is equal to B two and two where V one is the volume of the original concentrated solution and one is the polarity of the original concentrated solution. The two is the volume of the dilute solution. M two is the modularity of the dilute solution. What we'd like to solve for his be too, Which is equal to be one. I am one the end to you simply need to move on to to the other side of the equation here. That's all we do is plug in our valley's 100 mil, multiplied by 12 Mola Divided by 5.2 Molar. We get a volume of 231 millilitres. Final volume of sodium hydroxide is 231 mm.


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