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PareoMach 1. CH3-CHz-OH PCC 2. CHz-CHO CH; ' OH H;O+ 3. CHz-COOH CHzLi HaO+ 4. (CH3hCo NH,OH H+ 5.2 CHz-CHO + OH-(CHsh C-N-OHb. CHa-CHOc.CHz-CHz-COOHJ. CHa-CHO...

Question

PareoMach 1. CH3-CHz-OH PCC 2. CHz-CHO CH; ' OH H;O+ 3. CHz-COOH CHzLi HaO+ 4. (CH3hCo NH,OH H+ 5.2 CHz-CHO + OH-(CHsh C-N-OHb. CHa-CHOc.CHz-CHz-COOHJ. CHa-CHOH-CHz-COOHe: CeHs-CO-CH;6. CoH6CHz-CO-CI / AIClaf. CH;-CH(OCH3hz7. CHz-CHO +NaBHag. CHz-CHz-OH h. CH;-CO-CH38. CHz-CHOHzO+9. CHz-CHO + HCN / CN 10. CHz-CHO AgNO: NHaOH 11. CHz-CHz CHO {1. [O] 2. H;O+} 12. CHz-CO-CHz-COOH NaBHa / alci. CH;CH(OH) CNj. CHz-COO- k CHz-CH(OH)z I. CH3 ~CHOH-CHz-CHO

Pareo Mach 1. CH3-CHz-OH PCC 2. CHz-CHO CH; ' OH H;O+ 3. CHz-COOH CHzLi HaO+ 4. (CH3hCo NH,OH H+ 5.2 CHz-CHO + OH- (CHsh C-N-OH b. CHa-CHO c.CHz-CHz-COOH J. CHa-CHOH-CHz-COOH e: CeHs-CO-CH; 6. CoH6 CHz-CO-CI / AICla f. CH;-CH(OCH3hz 7. CHz-CHO +NaBHa g. CHz-CHz-OH h. CH;-CO-CH3 8. CHz-CHO HzO+ 9. CHz-CHO + HCN / CN 10. CHz-CHO AgNO: NHaOH 11. CHz-CHz CHO {1. [O] 2. H;O+} 12. CHz-CO-CHz-COOH NaBHa / alc i. CH;CH(OH) CN j. CHz-COO- k CHz-CH(OH)z I. CH3 ~CHOH-CHz-CHO



Answers

The product(s) obtained via oxymercuration $\left(\mathrm{HgSO}_{4}\right.$ $+\mathrm{H}_{2} \mathrm{SO}_{4}$ ) of but-1-yne would give (a) <smiles>CC(C)=O</smiles> (b) $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2}-\mathrm{CHO}$ (c) $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CHO}+\mathrm{HCHO}$ (d) $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{COOH}+\mathrm{HCOOH}$

In this problem, the reaction will happen. Something like this. Just look at it carefully. CS three Hold to see you in presence of and a CNN SCL. It will give C. S. T. D. Oil too C O. H, the end and ingredients of as 30 it will give the S. T. D. All too see to urge C O. H. So according to the option. In this problem, option C. Is correct answer for this problem.

In this problem, I can write a DDX and IT cht see CH three double burn oh, in pageants of NSCN at cl it will change into see college CN see http CH three and it is In Potenza as 30 plus it. It will change into C h t C oh, at C 00 H Ch three. So this is a B and according to the option, option C, option C eat correct and said option, seed, correct dancer for this problem.

Hi everyone. So in discussion they asked the product acting higher. Obscene regulation Jessica plus, additional support of beauty and one will give a B is A is CS three CH two C o C. S, three beads, CH three ch, two ch, two ch oh then seeds, CH three ch two ch chocolates that Cholo and the CS three CH two CH plus and sewage. So in this case option is correct. Option E. It's correct current. Yeah. Your time Ladies CS three CH 2 C2 Taliban. See edge built one in on reaction with Ngos corporations and so forth & c. s. L. four. It should be a self old. Yeah, gives Yes CH three CH two C double bond. Oh ch three. Okay.

In this problem, the reaction will happen. Something like this. Just look at it carefully. CST C O and CS three for two plus Ash too will react in purge Enzo at CNN to give CST going to and it's place CST she or batch. So according to the option in this problem. So according to the options, even in this problem, the correct answer. It, Option B, option D. H. Correct answer.


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