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The emfs in the figure below are € 4,00 and €2 18.0 V Thc resistances 59,0 @, Find the magnitude of the current ore R1 = 17.0 0, Rz = 30,5 0, Rz = 47,50...

Question

The emfs in the figure below are € 4,00 and €2 18.0 V Thc resistances 59,0 @, Find the magnitude of the current ore R1 = 17.0 0, Rz = 30,5 0, Rz = 47,50 arid each resistor when the switch Is in the following states,opan10947 Gnnan4a44tclosed

The emfs in the figure below are € 4,00 and €2 18.0 V Thc resistances 59,0 @, Find the magnitude of the current ore R1 = 17.0 0, Rz = 30,5 0, Rz = 47,50 arid each resistor when the switch Is in the following states, opan 10947 Gnnan 4a44t closed



Answers

For the circuit shown in the figure, find the magnitude and the direction of the current through each resistor and the power supplied by each battery, using the following values: $R_{1}=4.00 \Omega$,
$R_{2}=6.00 \Omega, R_{3}=8.00 \Omega, R_{4}=6.00 \Omega, R_{5}=5.00 \Omega, R_{6}=10.0 \Omega$ $R_{7}=3.0 \Omega, V_{\mathrm{emf}, 1}=6.00 \mathrm{~V},$ and $V_{\mathrm{emf} .2}=12.0 \mathrm{~V}$

No problem. We'll use the following diagram in order to find the resistance currents. And Walt is we have opposed to hear a native here potential differences. 24 walls, Um that this one is connected with to resistors, which are connected in a Siri's. We have a five for home, then we have a 10 or home. The current will flow in the conventional direction and we call this current to be I won. We have another brunch resistor connected here. Six all home. Then we have another resistance, which is four or homes here. The current, which flows from six armory. So we call this I one minus I to where I to flows, um, through four home resistance. Then using a kid your floor, we write questions. So first equation between the four worlds, minus six times I to sixties day the resistance minus four times I to musical 20 This recall this equation one in the equation of to 24 minus five into I one minus I to ah minus 10 into. I want minus I to physical to zero. We call this equation number to you just school up. We call this a questionable to and requested. Number one will give us. Ah, I do A which we call 2.5 times from from one one. Sorry, this will be I two is equal to 2.52 point four EMS, then from equation number two. We get I one minus I to to be 24 divided by 15. Ah, then playing a value for I two we get I want to be four times for a potential difference we use, um your question ir and the resistor. Here we have a resistor here we have a current and here we're Walt Egx for a 54 home. We have 1.6 EMS and Walters. We have eight. Ah, wolves 10. Or for general homes, we have 1.6 times 16 walls. Then for resistor. Six homes, 2.4. Ems will have altered or 14.4 worlds for a photo home. We have ah current off 2.4 am's the voltage off for 9.6 worlds

In this question we are given that yeah given this uh circuit. Okay. Battery with three resistance. And then uh given that the E. M. F. is 9.0 votes. R. One is 150 homes. R. Two is 250 homes. Our tree is 1000 homes want to find a current in each resistor. Okay so to solve this question first we want to find our equivalent resistance in the circuit. So we see that to an artery in parallel So we can buy our 2. 3 is one of our two plus one of archery and the recipe book of it. Okay and then our equivalent resistance is one plus R. Two tree. Okay so uh of our fast one of our two plus one of archery. The reciprocal substitute the numbers one of 1 15 plus 1/2 50 plus one over 1000. The reciprocal of it and the Cuban resistance you calculate you get 250 once. Okay? And then the current in the circuit current supplied by Petry. If you go to the mm, do I buy the equivalent resistance? So nine by Try and 50 and you get 0.0257 MPS. He then um I won is going to be 0.0257 MPS. Because uh is in series with the battery and then I too Is equal to be to divide by our two and B two is e minus. We won then be one is uh I one or 1 developed by our two. So you can substitute nine minus. So I want 0.257 R one is 115 and then divide by 215. Okay, So you get 0.0206 Mps. And then I three is equal to 1 -2 T. And the answer is 5.14 times 10 to the negative three mps. Okay, so here are the answers for this question and that's all

For the given problem. First we draw a circuit diagram. That is, the batteries connected with the resistor year. Then, um, that is connected with another sister. And this was the story is connected in the series with two resistor which are in a battler to each other. Oh, then a negative terminal off the batteries connected here. Oh, Then we have another branch here. I ate a home. Resistor is connected, which is a home. We level following currents. So, um, here we have is the current off a battery Ivy League college Recall this current which is flowing through a forearm resistor to be I won where we call to the current that flows through Ah, 80 home resistor where we call i three current their clothes through a 600 sister and we call four to be a current that is flowing through Ah, 12 home resistor. Here we have a tour home resistor. We first find I be which is your lefty, right by equal interest distance article. And so we find that all equal interest er for the Cuban circuit which we found to be a six home. We use a peddler and serious condition Finally coolant. So Tony form walls despues us four times. So I desire for EMS. Then we find I won, which is simply 24 minus. Um I Kurt off the battery times two, which is a four times two, divided by eight. That using situations. Similarly, the to Walter 32 is simply a 24 minus, uh, two times four. That gives us it. So this will be a 16. Sorry. 16 wounds. Where we see from the diagram, I one is equal. Teoh too, which is to EMS. Then we can find I before before will be, then I one times are, which is two times afore That gives us a two worlds. Then the next step we find i three So I three will be done by three is equal to two words three times off to which uses for over two years, Walter. Six will be. Then I three terms are which is four over three times six. Which year? State walls. When I four then will be 1/2 times two. This will give us a two or three. Um so this will give us two or three done so to so this guy for real, but then one over third off terms to so one over third times two, which will give us simply to Arthur off two or three games. Then a voltage across a resistor off 12 bombs will be I four times the resistor, which is two or three times 12 home. Then we'll US state worlds if we list them all off. Liza. The values for resistor Walter End current. So here we have home Walt Egx and then current ampere for two. Home. We have eight walls and four in peer. For the follow home. We have eight, Walls two and Pierre, then for six. Home. We have eight walls in 1.33 EMS for 12 or home year eight walls. Then we have 0.66 amps for eight. Home. We have 16 rules. Then we have a current off two ends

For a falling problem. We have ah, following Circle 12 rules country is connected in a serious first to read the three or home resistor which is then connected with the forearm resistor. This four alarm resistor is connected with 48 0 Homer in history, um which is then again connected with another resistor which is Ah, 16 arm. We have to find the current in each minister. So let's call the current which goes from the Petrie Teoh three ohm resistor. We call this a current. I'll be I turned off the the veteran current we call I won for the current that flows through the resistor for a home by two for flowing through for the entrance to Rome where we call I tree for the current flowing through 16 or ministers. Then a total we first find. I be in order to find out we find equal and resistance would you get six home and from there we can just divide 12 by six. So I these Walters divided by resistance that is 12 balls off the Petrie Divide by six which will give us to AM's Now we right, I want to be 12 minus three times off there. The battery which we found to be to appear divided by four home, uh, resistance. That will give us three or two as similarly for I to let me just scroll up for I to This will be 12 minus three into two, derided by resistance, which is 48. This will give us one or two days for I tree. Ah, this will be 12. My mystery into two do is there. The Patrick turned to divide by 16 0 ho mutual G was three or eight am's from the diagram we see the voltage. Everyone is a quarto t two and logistical to between. Ah, that is actually 12 minus three times to who? Just six walls.


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