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What mass of CuClz is contained in 75.85 g of a 22.4% (by mass) solution of CuClz in water?5.89 833.98170311282958...

Question

What mass of CuClz is contained in 75.85 g of a 22.4% (by mass) solution of CuClz in water?5.89 833.98170311282958

What mass of CuClz is contained in 75.85 g of a 22.4% (by mass) solution of CuClz in water? 5.89 8 33.98 1703 1128 2958



Answers

Calculate the mass in grams of the following. $\begin{array}{ll}0.331 \mathrm{~mol} \mathrm{Fe} & 2.1 \mathrm{~mol} \mathrm{~F}\end{array}$ $$ 0.034 \mathrm{~mol} \mathrm{CO}_{2} $$ $1.89 \mathrm{~mol} \mathrm{~K}_{2} \mathrm{CrO}_{4}$

Question. Number 36 is another mass percent or percentage by mass, however you want to refer to it, it looks like in this textbook, the author is calling it wait percent or mass percent or percentage by mass, several different terms. This is defined as the grams of the salute divided by the grams of the solution. Times 100 in question 36. We know the percentage. That's 20.2% that we can set equal to the mass of the salute, which we don't know. Divided by the mass of the solution, which is to 19 multiplied by 100 rearrangement of this equation gives us the mass of the salute is equal to 20.2, multiplied by 2 19 divided by 100 or 44.2 g Salyut copper to sulfates.

I have even saw in this question. Thus that is what massive camera would contain 72 points this gram of manganese. So given data given went up manganese very tough. My anger needs. Mhm I think my good news That is 72.6 grand. Then you ask very tough. Came in a four. Now we know that wait up manganese divided by molar mass of manganese. That is equal to Went off camera 4th. Yeah, yeah. Mm mhm mhm Right, red dog uh manganese upon muller Mazz of mango needs. That is equal to the weight off. Came in 04 upon okay, Moeller Mazz of came into force and their forward. My top came in a four come on right of terminal four. That is equal to very top uh manganese into moller myself Came in a 4th. A bomb molar mass up Mangga needs. And that is equal to wait up A man 72.6 in two mother mass of camera for 1 58 point 034 upon 54 point 938 And therefore wait up. Came in a four. Mhm weight of Came in a four. Okay. Yeah. Yes. Mhm. So this is equal to 208.84 g. So therefore, Marcel came in a four in. Mhm. Yeah. Mas of came in four in 72.6 Grand of manganese 19 to 0. Ed point a deep fault graham.

Yeah. To calculate the mass in grams that correspond to each of these mole quantities, we simply need to know the molar mass. In the case of an element, we go to the periodic table and it's found just below the chemical symbol. The molar mass of iron is 55.845 g per mole. Multiplying this mass value by the moles, moles cancel and we get 11.4 g iron to the three significant figures we started with If we have .79 mold floor een on the periodic table, 18.998 g of Florina is one mole. Multiplying these two numbers together gives us to just two significant figures 15 g Florentine. And if we have 58 moles carbon dioxide multiplying that by the molar mass of carbon dioxide, which is the mass of one mole carbon plus the massive two moles, oxygen given us 44.1 g per mole Gives us to just two significant figures 260 g carbon dioxide. And for the last one we have 48.1 moles potassium chrome eight. The molar mass is going to be the massive two molds, potassium plus the mass of one mole chromium and four moles of oxygen. Given us a total mass of 194 19 g per mole. So 48.1 moles corresponds to to just three significant figures 9340g

This question has two parts. In the first part of the question, we need to determine the modularity of hydrogen, phosphate or phosphoric acid Um when the mass of the phosphoric acid is given as 3.978 g and this is part of a solution Which has a volume of 185 mm. Now we know that similarity is always the unit of polarity is most per liter. So we need to determine the number of moles of phosphoric acid here and then divided by the volume in terms of liters. Right? So the number of moles of phosphoric acids, it's easy to calculate from the mass because it's just the mass divided by the molar mass. So it's going to be 0.978 crams. And then instead of the multiplying by the, sorry, dividing by the molar mass. I'm going to multiply by the reciprocal. So the monomers is 98.0 grams per mole. I'm just going to multiply them by the reciprocal. And then, so this is the number of moles of phosphoric acid. And then I need to divide that by the volume of the solution. The volume of the solution is given in terms of milliliters but similarities in terms of moles per liter. So I'm going to convert the milliliters two liter. That's a 0.185 L. And the answer here with 10 b 0.0539 mola. Right, So that's the first part of the question. In the second part of the question, they tell us that um There is um uh study my drug side solution with a concentration of 0.454 moller. And we have 11.58 mm of the solution. Question is if we use this salute solution and we neutralize the phosphoric acid, what is the volume of the phosphoric acid? That is necessary for this neutralization. So here I have written down the reaction equation but it's not balanced yet. So I need to balance it first because we will need to make use of the story geometry from this reaction equation. So I've got three sodium is on the right hand side. So I put three in front of the sodium hydroxide on the left hand side to balance this and then well that's left to is to put three year in front of the water. All right now I have my balanced equation. Question is what is the volume here? This is really awful neutralization. So what I'm going to do is um remember that we can calculate the number of moles of sodium hydroxide here from the clarity and the volume. And we know that once we have the number of moles of sodium hydroxide, we can use this together with this to a geometrical efficient uh started geometric gracia in order to calculate the number of moles off. First of all, like acid. And then it's easy to go and calculate the volume because we already have the modularity of the first forecasted according to what we calculated bus. Right? So let's go and calculate the number of moles of city of my drug site sitting my drug side number of malls zero point Because you know, 1 1 5, 8 leaders times The more clarity in terms of multiple latest 0.454 moles per liter. So this is why um I've converted the volume of sierra madre oxide to leaders so that the leaders can cancel out and I'm left with moles. Right. I'm going to do the calculation a bit later on. Next on. I need to calculate the number of malls of phosphoric assets because I need to use that in order to determine the volume. Right? So yeah, I'm gonna make use of this Tokyo metric ratio according to the psychometric coefficients in the balanced equation. Um for phosphoric acid phosphoric acid, it's 14 sodium hydroxide, it is three. So I've got a ratio year of one over three. All right now I can determine the number of moles of phosphoric acid in terms of the number of moles of Salima drug side. The number of moles off phosphoric asset. Yeah, he's equal tooth a third of the number of moles of sodium hydroxide. All right. And I know how to calculate the number of moles of sodium hydroxide. So that's easy. And then I know that the volume of phosphoric acid is equal to the ones I have. The number of moles of phosphoric acid. I can just divide by the more clarity of phosphoric acid. Right. So let's do that because I have the clarity. I've calculated it earlier on in the first step. Right? Yes. I've shown that the number of moles of Phosphoric acid is equal to a 3rd times the volume of the. What was that? Sorry? My truck side in terms of liters, 0.01158 l times the polarity Which is 0.454 moles per one liter. And that I divide by the polarity of phosphoric acid. So I can multiply by the reciprocal. So this is 0.0539 moles per liter. So, I'm just going to use the reciprocal. Yemen. I multiply Because of the division. Okay, this is equal 0.03-5 L. And if I need to give in terms of mm, it's just Multiplied by thousands. So that's three, All right, let's quickly recap here. The first part of the question asked to calculate the molar itty of phosphoric acid of a given mass in a specific volume of a solution. So I just had to go and calculate the number of moles of phosphoric acid because I already have the volume of the solution. I can then just divide the number of moles of phosphoric acid by the volume of the solution. But the volume of the solution needs to be in terms of liters. Second part of the question is about a neutralization reaction where I have the phosphoric acid with the clarity that are calculated which reacts with sodium hydroxide, the polarity and the volume of this sodium hydroxide is given. So I can calculate the number of moles of this and then use um this is to geometric ratio of sodium hydroxide too, Or phosphoric acid to 30 my drug side to calculate the number of moles of phosphoric acid in terms of the number of moles of Sunni my drug side. And from the calculate the volume of the phosphoric acid. It's just um taking the number of moles of phosphoric acid and divide that by the polarity that I've calculated in the first step of this question. And then um in the end I converted the volume in terms of leaders two ml.


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