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Cikzixi tc expxxted number of non-smokers with Iam cholesterol Enter your answer to 2 decimal ParesThe test statistic for this test isand the p-value...

Question

Cikzixi tc expxxted number of non-smokers with Iam cholesterol Enter your answer to 2 decimal ParesThe test statistic for this test isand the p-value

Cikzixi tc expxxted number of non-smokers with Iam cholesterol Enter your answer to 2 decimal Pares The test statistic for this test is and the p-value



Answers

For this data set, find the mean and standard deviation of the variable. The data represent the serum cholesterol levels of 30 individuals. Count the number of data values that fall within 2 standard deviations of the mean. Compare this with the number obtained from Chebyshev’s theorem. Comment on the answer. $\begin{array}{lllll}{211} & {240} & {255} & {219} & {204} \\ {200} & {212} & {193} & {187} & {205} \\ {256} & {203} & {210} & {221} & {249} \\ {231} & {212} & {236} & {204} & {187} \\ {201} & {247} & {206} & {187} & {200} \\ {237} & {227} & {221} & {192} & {196}\end{array}$

So in this question were given 10 numbers and we're asked to find the mean and the media. So for the mean, we basically take the sum of all the numbers divided by 10. So in this case are mean will be 136.4. Now for the median, let's arrange all of these numbers from smallest to largest. So we have 110 and then 113 1 to 7, 131 135 138 148 15 to 152 and 15 points. So we have seven here, three. So that's 10 numbers. So we take 1234 the fifth and the sixth. They basically take the average of 135 plus 138 divided by two. And for that hour Median is 136.5 we have the answer.

Sorry. So in this question were given on 234, father given 10 while he was here and we're asked to find the mean and the median. So let's arrange these values. So we have 132 from 33 139 145 on 47 148 on 50 on 53 1 61 62 So we have 123456789 10 values. And were asked to first find the mean. So the mean is the sum of the values divided by 10. And we have here The mean as one for 6.9 and the median is basically taking 234 123 4/5 and the sixth. The average of the fifth and the sixth values, which is 147 point Hi. So they have the means and the media.

All right, that's a good question. 34. So here were given a, um up a table computed by excel in the question so we can use the information from the table directly to, um make decision off whether we're going to reject no high positives or not. So first, I'm going to stay. The no hypothesis and the alternative deposits is it's going this question are on. No hypothesis is on. The difference meant me no difference. Sequel to zero and the alternative hypothesis says me no differences, um is positive. So which is greater than their own? I hear d is indicating the score for prey class my nose opposed to close All right. And our confidence level off Kulka is equal to zero point both five. So in the fulling table were given that if we look at the third last roll, we can know that our T star is equal to three point three night and P value iss. They're opined arrow there Oh 397 which is prayer? A very small and obviously it is smaller than the over here. So why does we're going? Teoh reject No high pauses is and we can also compare our T star with the tea critical value you hear, the degree of freedom is nigh Alfa a their own point of a fire and al Qaisi area for one toe. So this critical battle is equal to 1.833 So because our key star is greater than this 1.83 straight So which minty star fought into the rejected Rijn? So we're going to reject the no hypothesis as well.

Let an FAA denote the number of persons has elevated cholesterol, which are given to be 1 80 lead and no fest denote the total number of person which is given Toby for 50. We need to find operability off. A possum does not have elevated cholesterol so which is equal to P off a dish physical toe one minus b off it. We're p off a Did not die operability off. A person has elevated cholesterol so which is equal to one minus number of persons have elevated cholesterol divided by total number off persons. So which is equal to one minus two upon file, which is equal to three a bone file. This is a well.


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