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Detenine tne functicn represented by tne graph cf tne line % = Ix} in ine figure.10TX)Fnter vour Answerin the answer box and then click Check newer...

Question

Detenine tne functicn represented by tne graph cf tne line % = Ix} in ine figure.10TX)Fnter vour Answerin the answer box and then click Check newer

Detenine tne functicn represented by tne graph cf tne line % = Ix} in ine figure. 10 TX) Fnter vour Answerin the answer box and then click Check newer



Answers

Answers are given at the end of these exercises. If you get a wrong answer, read the pages listed in red. Use a graphing utility to find the line of best fit for the following data: $\begin{array}{|c|cccccc|}\hline x & {3} & {5} & {5} & {6} & {7} & {8} \\ {y} & {10} & {13} & {12} & {15} & {16} & {19} \\ \hline\end{array}$

So we're asked to find a line of best fit. We need to start by entering our data, which will do by creating a new table and entering our data like this, for example, in x of three on a Y of 10. And we can see our data point on the screen over here when we finished recording will have a chart that looks like this and a graph that looks like this in order to find our line of best fit. Will he say why one is related to M for our slope x one plus B and we'll get the parameters. M equals 1.78261 and B equals 4.65 to 2. Just to confirm that is our line of best fit will take that in Why equals 1.78 261 x plus 4.6522 and turn off. That does fit beautifully for our data and a line exactly with our regressed line of best fit. So there is our equation

So uh for example 10, we want to change the negative to a positive. So this is going to be two x. Mhm plus three Y equal six. And we want to find its intercepts and um one checkpoint. So the intercepts we can find using a graphing tool, We're going to change these y coordinates because they're making things a little bit more difficult to see. So I go from negative 10 to positive 10 Museum square. That's what we have now. We see that the intercepts are located here and here. So our intercepts are 0 to And 30 for the x intercept. And then we want a single checkpoint So we can just hover over anywhere and see that at 1.5 for example, We have the coordinates of one. So that would be a good checkpoint. 1.5 and one. And we can confirm that by plugging it in here.

For this problem, we want to use the graph to find the equation of the line in slope intercept form. So I like to write this out first, so y equals mx plus B. You know that B. Is the y intercept and m is the slope. So the white intercepts the easiest thing to find. We see that's going to be a negative 123 so we have minus three. And then the slope, we see that in order to move, we move up 123 units, so it's going to be a rise of three and a run of two. So because we have a rise of three And a run of two, we see that's going to be our slope 3/2. So this is the final line, then doing the same thing. Uh Y equals mx plus B. For the second one. We see it goes to the origin. So the y intercept zero and the slope is going to be um About a -1. Um so we end up getting that's actually going to be a -3/4. That's our final line equation

For this first equation, we have Y equals mx plus B. And we're gonna have the same thing for the second equation. But first we see that for the first picture, the y intercept is clearly a positive two. So now we just need to find the slope. If we go down one and over one we're down to and over two we see that we're on the line. So this is going to be a slope of negative one. So we can just write Y equals negative X plus two. And then we want to find this other line. We see it goes to the origin. So the y intercept is era. And then the slope if we go up three are up two units and over three units we get to another point on the graph. So what that tells us is that we have a rise of two and a run of three. So y equals two thirds X. Is the equation for the second picture show. So these right here would be our final answers um for the lines and this is our ending result.


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