Okay, this is question 11.100 in chemistry. The science in context on and asks us to calculate I Okay, eyes our event. Hoff factor. Okay. On the experimental. That whole factor. Okay, given that the constant for water is 1.86 Celsius for morality. Okay, um, and then gives us a chart to these air are different compounds their concentrations, and then the change in the freezing temperature. Okay, The freezing point depression. Okay, um and so remember the equation for freezing point depression that is Delta t f equals I, which is our Vantaa factor times the constant for that solvent times mole ality for that soul ute. Okay, I mean, so we're already given the KF um and we can calculate morality. And that's how we're gonna be left with our fans all factor, because we're given Delta T f. Right. Okay, so let's calculate mole ality first. Okay, So another thing to note is that this is all in grams per kilogram, but this kilogram is in the kilogram of the solution. Okay? Those air kill your outlook solution because this was in a concentration. Okay, So the killer of a solution includes the grams of your Sol utes. OK, so that includes the five grams. Ok, but remember that morality morality is in moles per kilogram and it's specifically kilograms of solvent. Okay, Only this solve it. So this is in kilograms of solvent, plus the salyut. So we have to take, uh, take that into account and subtract out our grams. Thankfully, the grams are all the same. Actually, the concentration, they're all the same, so we can convert the concentration. Um uh, correcting for the grams of these valued. So what we need to do is that 50 are five points there of grams of per kilogram. Ok, means that we need to subtract. Subtract the mass of our soul ute. Okay, which is which is your, which is five grabs right, which is five grams or here's all we really need to do is get 1000 or 101 kilogram minus five gram. That's all we need to do. One kilogram again is 1000 grams. So it's just 1000 grams minus five brands which were left with 0.90 sorry. We do that in grants. First, that would be 995 grams, which is equivalent to zero point 995 kilograms. Because wherever we still need to keep it in kilograms, So we're gonna do is use this as our, um our grams of Saul Ute. Um uh, sorry grams of solvent rather than a full kilogram because we have to take into account the mass of the, uh of these salute. Okay, so this is what we're gonna use. So let's go ahead and calculate the Mulally for lithium chloride. Okay? I'm and so the we need to find the molecular weight, cause right now we've only got grabs. Okay, so let's write this as five men, zero grams of lithium chloride in 0.995 kilograms of water. Right. That was the corrected value. Okay. And so we need to find the molecular weights. A molecular weight of lithium chloride. Okay, is 6.94 plus 35.45 grams per mole. That's also in grams per mole. Right? I've been said this ends up being 42.39 grounds per mole, please. We're gonna use this to convert grams into, um, moles. Okay? I mean, so we would do the inverse we would do 42.3 39 grams over one mole. Right, cause we want grams to cancel out. So we're left with moles and kilograms at the bottom. Okay? And so this calculates out to be Let's see, here this ends up being 0.11 854 mola house. Right, Because that's in moles per kilogram of water. Okay, so let's keep this in mind, because we're going to use that now to calculate our our, um Van Paul Factor. So how do we do that? We just plug it into this equation, right? So delta T f for lithium chloride was 0.410 Okay, So it would be 0.410 equals I, which will Salling for, um, 1.86 degrees Celsius. Morality times the mill ality to 0.11 854 Moralities castle out. We're left with degrees. Uh, this is a degree Celsius. Okay, um and so the degree Celsius? Well, cats a lot when we divide at the OK, so let's give ourselves a little bit more space here. Calculate this out. So this ends up being 0.410 degrees Celsius equals I and I'm gonna multiply these two out first. That ends up being 0.22049 degrees Celsius and then we divide both sides by 0.224 line right on and wheat and the degrees Celsius Cancel out. Right. So we're left with just I And so I ends up being 1.8 59 equals I And that is the three. The experimental I for the lithium chloride. Okay, so that is our final answer. OK, so we're going to do the exact same process for hydrogen chloride HCL and then sodium chloride. Okay, that someone would go a little faster because basically, it's all gonna be the same process. Okay, so this one is for age CEO. Okay? So the molecular weight equals 1.0 through eight grams per hole plus 35.45 grounds for mole equals 36.458 grams. Permal. Okay. We started with 5.0 grams per 0.995 kilograms of water. And that's grams of HCL. Okay, 36 1458 grams per mole. okay. He goals. So the grams cancels out when we're left with moles of HCL over kilograms. Okay, this one wa 0.1378 Well, else. Okay. And then plugging that into our delta T equation. Remember, adult a t f equals I times k off times. Um, and KF is the same for every everything, cause it's an equi. A solution in case of this one gets set up a zero point for 86 degrees Celsius equals I times one point heat six degrees Celsius. Mullah house and then 0.1378 alleles. Okay, on. And we already saw the, um the units cancel out. So I'm just gonna calculate what I ends up being. I ends up being 1.8 96 Okay, so this one was for age CEO. Okay, um, and that's do the last. The last one, which is sodium chloride. So n a C l. The molecular weight for it is 22.99 grounds for mole plus 35 when 45 grams per mole k equals 5844 grounds for whole. Okay. And we have five grams of at a c l over 0.995 kilograms of water times our Moller Mass. And this is 0.859 Hate I'm allows. Okay. And then again with Delta t f equals I k f um, with the morality is so in this case, the delta T f was 0.299 degree Celsius equals I You're right. I hi was 1.86 degrees Celsius mullah and 0.8598 Okay. And this calculates out to be I equals 1.870 que And so that is the answer for, um, the sort of chloride on. Let's do not, so we can see everything a little bit. So those are the values. Okay, those are the answers. Um, for this problem.