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Question

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Answers

(A) $\mathrm{M}^{0} \mathrm{~L}^{-1} \mathrm{~T}^{-1}$ (B) $\mathrm{M}^{0} \mathrm{~L}^{1} \mathrm{~T}^{-1}$ (C) $\mathrm{M}^{0} \mathrm{~L}^{2} \mathrm{~T}^{-2}$ (D) $\mathrm{M}^{0} \mathrm{~L}^{0} \mathrm{~T}^{0}$

In this problem, I'm writing the reactions. So just look at it carefully. OK. FECN six came food, FT CN six plus six. He S CN k s c N will react to form, get to the f e SCN six and now I'm going to write the second reaction. They just look at it carefully Or FECL three. That's pretty careful. F E CN six, then it will give 54 F e CN six plus two old KCL. So option age correct here.

Okay. Final set of candidates in this section 15 m squared minus eight N. To the power for 15 m squared plus 8. 10 to the power for same pan same formula. Okay. First, guys squared minus second Guy squared. The first guy is 15 m square. Second Guy is eight and to the four. Okay, we're gonna square both pieces of Armando meal. So 15 squared, multiply exponents to give us em to the powerful eight squared And to the power eight coming from motor plan, those exponents again, 15 square will be 225 empty. The power for eight square will be 64 And to the Power eight. There's our solution.

So in this problem we're given this matrix which Is a diagonal, right, only has entries on the main diagonal. Everything else is zero and were asked to define the determinant. We can use a matrix calculator to do this with. So what you desmond dot com went to math tools matrix calculator and got this one. So I need a new matrix now and I got five rows and five columns. And the first entry up here Is a -2 And then the entry here is a three And the entry here is a -1 man. She just working my way down the main diagonal here, This is a two And the last entry down here is a -4. There's all my entries now to do the determinant. I go d E t of a and We get -48 for the answer. So there you go. Which by the way, if you multiply the entries on the diagonal there. Look what happens When one is 2 times three is -6. I was in -1 is plus six times two is 12 Times of -4 is -48. Gave us the determinant, didn't it?

For the given reaction I can write the value of Q is equal to um oh plus mn minus M C minus M G. Multiplication 9 3 1.5 M E p per you. Just putting the value in this expression, I can write 15.994 plus one point Dear. Oh dear. 08 -13.0033 -4.0026 whole multiplication. You multiplication 931.5 M. Maybe per you simplifying it further. Finally I get the value of Q at minus 2.215 M E P. So going forward and I think the value of U. K minimum. So the formula is given by one plus one plus. Amen. Bye. Ammo. Whole multiplication mode of Q. Model Q is albeit projective. So just putting the value one plus 1.8665 by 15.9949 multiplication 2.215. Which is equal to 2.35 MEP. As our


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