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Construct cumulative frequency distribution table for Iethal Uranium for fishes (grass concentration of carp Ctenopl haryngodon idella):Concentration of Uranium (mV...

Question

Construct cumulative frequency distribution table for Iethal Uranium for fishes (grass concentration of carp Ctenopl haryngodon idella):Concentration of Uranium (mVI)Frequency0 - 1920 _ 39 40 _ 5960 _ 7980 _ 99Construct graphs plots:Stem plot of weight of female patients having Obesity: 61,63.64,68 70,72,72,74,77,77, 79 81,83,83,85,88, 88, 88,89 90, 90,91,92,93,93,98 101, 103, 105Pareto graph & Pie chart of Blood donors:Blood Type DonorsAB

Construct cumulative frequency distribution table for Iethal Uranium for fishes (grass concentration of carp Ctenopl haryngodon idella): Concentration of Uranium (mVI) Frequency 0 - 19 20 _ 39 40 _ 59 60 _ 79 80 _ 99 Construct graphs plots: Stem plot of weight of female patients having Obesity: 61,63.64,68 70,72,72,74,77,77, 79 81,83,83,85,88, 88, 88,89 90, 90,91,92,93,93,98 101, 103, 105 Pareto graph & Pie chart of Blood donors: Blood Type Donors AB



Answers

Construct a cumulative frequency distribution and an ogive for the data set using six classes. Then describe the location of the greatest increase in frequency. Data set: Daily saturated fat intakes (in grams) of 20 people $\begin{array}{llllllllll}38 & 32 & 34 & 39 & 40 & 54 & 32 & 17 & 29 & 33 \\ 57 & 40 & 25 & 36 & 33 & 24 & 42 & 16 & 31 & 33\end{array}$

Once again welcome to a new problem. This time we're gonna be dealing with to us Off 50 is actually one aspect for are just of two branches it has on the churches. Oh, think on but not quantity to so descript to and inferential under descriptive, you can always present, um, visual off your data through tables. Our numbers and who are and the numbers include measures off central tendency and also mergers with read measures Nations central pending and nations off. Read these to us. You banged up so measures of central tendency and measures of spread on. Then also, when it comes to your gruff, do you have quantitative graph and alternative grass? These are two types of growth to become a cross for quantitative grass. These in America and the numerical would include things like his 2 g, which kind of looks like Bagwell's. We also have frequency polygons, bond. We also have really old jeans. So the O. G. S is the oji is the The O. J. Is the cumulative cumulative equals Oh, jog accumulates one seed, right? So in our new problem were presented with data. The data has club limit and it also has confused naming that between 60 and well on. These are our glucose levels in milligrams glucose levels in milligrams. So induction you have 16 or two 52 Ryan, one patient. So the frequency represents the number of patients a medical emergency, the number of patients and medical. So we have 65 to 69. We have 70 to 74. We have five and then job so decides to of engineering 82 34. We have 18, 85 to 89. We have 90 94 we have one and then 95 to 99. We have one in total. Listen patients. And so in this problem, we want you to grow up the program frequency Pol agree. And also the old guys hope of dark. You want to tell us the range grupos level for the patient? Those are the pictures of information that you're looking at. We're gonna identify this problem by having bounds. So, you know, taking the class limits and then introducing boundaries to the club limit wondering for these buns plus minutes we need the midpoint was without the midpoint to determine the exact point where the graphing is going to take place. And of course, finally, just like any other piece of data you need. So just like before, wanna have all these off limits that we mentioned earlier? Um, and we have to highlight the result off the boundaries. And there's a formula to that example. Want to get the lower bounds was simply going to say, the lower limit, which in the first case, and then you subtract on five. And if you want to get the upper bone, we wanted to the upper minutes off the class glucose levels and then you wanna had 0.5 and community Story go from 59.5 on side, uh, 4.5, the 9.5 way 9.5 to 74.5. And the reason why we're doing this so that way don't have bound. Don't wanna have bound. We don't wanna have gaps between the Houston runs. So 79.5 85. Now we still have to extend this 90 to 94 95 to 99 84.52 89 25. You also have 89.5 to 94.5 we have 94.5 to 99.5. The league points is computed by taking the law and limit, plus the upper limit, and then you want to divide that by two. So in that process, you can see why the midpoint is a zone. Example. You take 60 off 64 divided by two. That's 1 24 divided by two. And that gives you 62. So we have all these made points coming up. Just leave off the results of the data. No, and the frequently still stay the same, like you mentioned before. We need all this data to make sure that for Instagram, our accumulated frequently graph or or jive, is making all the terms that we need. So once we have that, now we can draw history room dual history. So we do have the X axis and the Y Axis history. One. You could divide it into different portions. We don't have to start up zero. As you can see, if you go back to the data, it's stuff from 59.5 so we can divide our affections into relevant pieces of information. Mm. 1234 five six and then seven and eight. They need to pretend that to make sure that our graphics sense. So in the x axis, we have the blood glucose levels on, and hmm, each of these points he divided, you know, into subsection. So 59.5 to 64 um, 0.5. So this is 54.5 mhm, then 69.5. You know, 74.5 mm. 79.5 in 84.5. 89.5 many before on five. And then 99.5. Then we have five. Those are the frequencies. 5, 10, 16. Then we're gonna have 20. This is just the frequency. Now we can have a grass. It's fast one, you know to then we have one, and we have five. Then you have 12, then we have 18, and then we have six, and then we have five. So then we have one, not give us a total of 50 for all the history ones. They, uh, touch each other just to make sure that we don't have cases. Where way have gaps in between the suspect, the rectangular teaching standing so that gives us the heat to Guam that you're looking for there. And so from the Chittagong, the trend that we a kind off pick up and it just so happened but the left side off the instagram. So we'll say, uh, the instagram is slightly, uh, left skewed. They used to grind like best queued. Mm. The left for you is stretched relative relative to the right, uh, tail. So that's what you have right there? Um, from time, uh, left. Q is also the same of negative. Cute west kidded fame of negative execute. I also wanna have the cumulative frequency. Mm. Graphs. And, you know, you talked about that, but we wanted to have, uh, frequency polygon. So to compute the frequently polygon, we are going to use the midpoint from this sense. The saying, uh, you know, frequently. Polygram, you need to meet points. So you still have, you know, x axes and we have the y axis. You still have the petition before? Yeah. Also, one too. 3456 seven in and then eight. Time to we still have the frequency on oxygen. 5, 10, 15, 20 into the sequences that you have um, neither midpoint numbers. There are 62 uh, 67 72 77 82 87 92. Hmm. So 18, 87 19 in 97. So at 62 way have to Yeah. And then one, 275 um, 12 on 18. Then we have six. Then you have five when we have one. So those are the numbers we have, and so we're just gonna start all the way down and connecting these dogs the vehicles up? Uh huh. This is all the way up to the attack. So it was all the way up. And so this is our frequency holiday and and accumulated frequency. So this is uh huh. So we're looking at frequency results off the stable. Yeah. We can have population off humility. Uh, frequency population of cumulative frequency. In this sense, we have less than 59.5. You're not gonna have generated to Quincy. We have, um, go is to graph the old guys. I think we're gonna have to. I'm doing a movie below. I'm gonna have to do Maybe, you know, on. So the population off the cumulative frequency grass coming back here we're saying? Well, we need a table for that. So we have access to action. This is Baxter. That's another one. Accumulate too. Frequency. And don't forget that on this axis, these are the blood sugar levels. So we have the blood sugar levels on this one. We have left time. 59.5. Lesson 64.52 left than 69.53 Less than 74.58 Less than 79 on five. We have 20. Uh, that's been 84 15 You know, 38 uh, and then we have less than from H 9 25. We have 44 less than 94.5, you know, 49 then less than and 95. You know, if so, the graphing simply means that we're going to take all these numbers and make sure that we represent how a cumulative frequency graph, which is the old jive on. So on this action, we have, uh, from, you know, maybe we could do it below. You don't have to meet, talk about a friend. Um hmm. To do this right here in the arteries. So you have blood glucose levels And we have accumulated frequency you have accumulated. Keep my feet, he goes zero can. 20 30 40 50 60 70 baby. So on and so forth society 59.5, 64.5, 69 5. 74.5 and you know kind of. So the 9.5 84 25 89. 25 um, 4. 25 names of 1995. Then you have the cumulation. We have, uh, to 64.5 year, too. 59. 25. We could start at the beginning. I'll have to appear then. They have three at 69.5. Well, you know, they're so close to each other. Then you have h you know, 20. You have 38. We had 44 and then we have 49. It was changed. Yeah, for the floor here when you're going through me. And I'm so sorry. His 50 something that. Okay, So it's the grassing process where you have to be careful for using soft looks easier, but that's accumulated, frequent equals. Hmm. And then we're gonna see the frequency for 75 to 79 is 12. Um, and the frequency. So 80 to 84 is 18 when you mhm. So most patients have glucose level that typically range from 75 to 84. So once again, we had a problem. And in this particular problem, we had were given a class limit for, uh, glucose levels for different patients. We have 50 patients, uh, built up boundaries lower and Alfa Bond with midpoint from the frequency tables used to get our history grumble to left cute. And then we build our frequently Taliban using the midpoint. But you can see, uh, this is it. Be building, uh, frequency. We built a frequency Taliban. Come on. Using a good point, Then off course, we, um besides the frequent polygon, we built a cumulative frequency table from using the table. We bilton on object. You know, I determine the range to between 75 to 84 for most of the patients, so I hope you enjoy the problems. You for you to find any questions or comments and have a wonderful day

Okay. So we're creating any relative frequency, hissed a gram. Um the way we're going to find the relative frequency is by dividing the frequencies by the sample size home Excel. We can do this by dividing that first frequency by 300. Which is our sample size. Men spreading that out like this and now we can do this. I like that role. I like that role and insert a bar graph. Bar graph is simpler in Excel. So we're just gonna go here. Oh where is? It? Must have lost my bar graph. It's hissed a gram. That's line. Mhm. Okay we'll just do this and there we go. That's her relative frequency. Just imagine that these bars are stuck together.

Okay, So in this problem, when we look at the blood platelets count for male and example. And instead of computing the mean using the raw data for every man in that sample, we're gonna use, um, the frequency table. So this problem is very similar to example, seven from this section of the books. Remember, when using a frequency table that mean is the sum of the frequency times the class midpoint divided by the total frequencies of the total amount of observations in a sample. So first, we're gonna figure out what are our classes? Mid points off classes, midpoint. So what's the in between zero in 99? Well, you can simply do zero plus 1995 divided by two, and you'll get 49.5 same thing for 100 100 99 you will get 100 and 49.5 and then so on. So you simply add 100 every time. So 249.5, 314 9 0.5, 449.5 549 0.5 and 649.5 Now we're going to compute it off, uh, number of men in our simple So by adding up every value in that column so one plus 51 plus 90 plus 10 plus zero plus zero plus one, which gives us 153 there were 153 males in that sample. And now we're gonna simply compute f times eggs for the frequency in each class multiplied by the class midpoint. So one times 49.5 is 49.5, 51 times 149.5 is 7000 624.5. 90 times 249.5 is 20 2455 10 times uh, for 10 times 349.5 is 3000 495 0 times 449.500 time 549.50 And one time, 649.5 is 649.5. And now we're gonna add up every value in the frequency times classman point column. So we have 49.5 plus 7624 0.5 plus 22,455 plus, uh, 3495 plus 649.5, which gives us 34,000 273 0.5. So we have everything we need to compute the main using the frequency table. So we simply divide 34,000 273.5 by 153 which gives us 224 0.1 So this is quite close to what we would have found had we used the raw data. So if we used, um mhm the blood pressure, the blood platelets count for every single male in that simple and added every different, uh, and every different single blood place that's constant, divided by 153 would have gotten 224 so extremely similar. So another case we're using a frequency table proved quite useful and, uh, easier to represent visualize while giving it's still very accurate results

So in this problem, which is problem 32. We look at the blood platelets, count and females you want to see the average the mean a blood platelets count for females in a certain sample of the population. So we need to find to information. There's some of the frequency times the men make a point for each class that we have and the total amount of divided by the total frequency. So the total amount of women or females to be more care to tell my females in that sample. So what's the total amount? Uh, it's the total frequency of female with you simply add every value in that column. We take inspiration from that table from example seven in your book. So 25 plus 92 plus 28 plus Hero Plus two. And we have 147. So we know that whatever we get on top, we're going to divide by 147 women. Uh huh. What's the class midpoint? So what's in the middle of 101 199 when you simply take 100? That's 199 divided by two, so you get 149.5 was the middle between the middle point between 202 119 90. Simply take 200 plus 299 divided by two, and you do the same for all the other class. It's because every class increases by 100. You can simply ah at 100 to every midway point. So 449 plus five now we're gonna multiply the frequency by the class midpoint for every class. So 25 times 149.5 is 3700 37 0.5, 92 times 229.5 is Ah, 22,000 954 28 times 349 points. Five is 9786 zero times whatever is zero and two times 449 549.5 is 1099. So if we have every value in that column, we will get 3000. Um, 3700 37 0.5 plus 22,954 plus 9786 plus 1000 and 99 which gives us 30 37,000 576 0.5. So here you have it. 37,000, 576.5. We divide that value by 147 and we get 255.62. So that's the mean. And if we had taken the raw data and the appendix table, we would have found that the blood pressure is 255 so it's, uh, slightly different. So this isn't the same as the me. So the frequent seemed Let me write it this way. The frequency mean isn't the same as the mean frequency isn't the same as the mean, which is 255 but 255 and 255.62 are are close enough. Uh, so it's not a big deal that we have a small difference, and it makes it's much easier to use a frequency table to visualize everything instead of imagine having a table of 147 many of them being 100 of a total of 147. So for visualization purposes, it's very useful to use this frequency table to find the me.


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