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Titrabon50 000 04715Na CzO. required 39 25071assILMpemanganate solulian2MnO4 SHCz0.2Mnz-OCO? (9} 8H,0Calculate the molar concentration of tha KMnO: soltionSuppose I...

Question

Titrabon50 000 04715Na CzO. required 39 25071assILMpemanganate solulian2MnO4 SHCz0.2Mnz-OCO? (9} 8H,0Calculate the molar concentration of tha KMnO: soltionSuppose Ivera askeo deteinine nickel s cel sample using gravimetfic Tisinco analysis Stale the Drecidinatoc reagent tnat You would Jnd condilions Ihal Foud be suilable Iox the precipilalion Wvhat expeflmental vanables would yau cantral ensure (hal crystalline precipitale TonmnedtWrite the Nernst cquations tor the following hall-cell rcactions

Titrabon 50 00 0 04715 Na CzO. required 39 25 071assILM pemanganate solulian 2MnO4 SHCz0. 2Mnz- OCO? (9} 8H,0 Calculate the molar concentration of tha KMnO: soltion Suppose Ivera askeo deteinine nickel s cel sample using gravimetfic Tisinco analysis Stale the Drecidinatoc reagent tnat You would Jnd condilions Ihal Foud be suilable Iox the precipilalion Wvhat expeflmental vanables would yau cantral ensure (hal crystalline precipitale Tonmnedt Write the Nernst cquations tor the following hall-cell rcactions Ag CrOa(s) + 2e 2Ag(s) CrOs V(OH) * 2H" + Vo' 3HA0 [20]



Answers

Use the Nernst equation and data from Appendix D to calculate $E_{\text {rell for each of the following cells. }}$ (a) $\operatorname{Mn}(\mathrm{s}) | \mathrm{Mn}^{2+}(0.40 \mathrm{M}) \| \mathrm{Cr}^{3+}(0.35 \mathrm{M})$ $\mathrm{Cr}^{2+}(0.25 \mathrm{M}) | \mathrm{Pt}(\mathrm{s})$ (b) $\operatorname{Mg}\left(\text { s) } | \operatorname{Mg}^{2+}(0.016 \mathrm{M}) \|\left[\mathrm{Al}(\mathrm{OH})_{4}\right]^{-}(0.25 \mathrm{M})\right.$ $\mathrm{OH}^{-}(0.042 \mathrm{M}) | \mathrm{Al}(\mathrm{s})$

Going on with electric chemistry here where essentially just looking at the movements of electrons throughout our system. First thing we're doing is calculating in East Cell Valley, where we have the style is e cathode reduction. Subtract e honored oxidation s. I'll do not 0.446 bolts. Subtract 9.242 volts. Eso is equal to not 0.204 vaults into the relationship between some potential and the free energy change. Delta G equals negative on F E South, where n is two moles. F is 96385 Sl is not 963850.204 so we can solve a Delta G by plugging in. All our numbers were dealt cheese negative 3.93 times 10 to the four jewels. Following this, we can take a look at the general formula announced equation that it's Esau particular to me. No, the track no point No. 591 divided by and multiplied by log Cute. Thank you is C R for two minus divided by 80 plus We have our products over our reactant. So we have moles That is too sweet. Plug in our values. So we have now have SL was not 0.242 because you calculated Dino struck No point no. 591 find by two of log cute So we're giving concentrations to plug in for C R 04 to minus and 80 plus Then we can solve for ESA that is not 0.352 volts Now, to find the concentration we can use announced equation where we have a lot of known information here we're solving for the c r. 04 to minors. Concentration that is are unknown. And so what we have is not 25 several four volts equal to 9.242 volts. Subtract no point no 591 bye bye to log C R 04 to minus divided by 1.0 small pelita. We then solve this concentration that's missing that is equal to 1.36 times 10 to the minus nine miles Paletta. Lastly, we're calculating the solidarity product of 80 cr four. So given the announced equation again, we have the equilibrium easily call sero. So what we have is no point, no no faults. It's equal to not 0.0.242 vaults. Subtract no point No. 592 volts, divided by two Log A G plus squad CR four to minus divided by a G To see our of four, where we saw for a G Plus squad CR four to minus start is equal to 10 to 8.1895 That is equal to 1.55 times 10 to the eighth on 1.55 times 10 to the eight is Thesis on Ability product for a G two c r 04

Hello, everyone. My name is Ahmed Ali and in this question that have the same assort. So I went solve the Bharti A by the tail and the similar. You will solve eight for a party in party. First, you must try the Bulls Humphrey action at Donald and over actions appearing at Catholic with and a note. What having is manganese is converting to manganese, postive toe and realize to elect wrong and from the index's people, we've only the value off the North. Reduction potential is evil. Negative one point money. Vero and Gasol see our post. If Serie accepting one electoral and converting a to C are posted to, and the value of reduction potential and the standard the condition is equal. Negative open 4 to 4. So now we can live the needy question by times's equation by two. So it will be ever full way to see our both different. Three postive mag unease is for to see our postive two. Plus I am Ana boasted to. So now we can like the in earnest equation. E cell is equal in not so negative to your point or find mine too divided by the total number transfer electron Look see our postive to a lion in a product or two times Boy mingle is posted toe and divided point C and avoided by sea are posted three power to so now you not said is equal negative or point for 24 negative to negative 1.180 which is equal the North Castle Negative two in on Anna The total number transfer electron or to the concentration off CR postive too is open to five. Magan is postive to is opening before see are posted three is open 35 So all of them are knowing So we can calculate the value off SL which is equal all 350.78 role similar toe the party. You will solve a party which is a similar. You must try the to offer action right? The Natick questions in right nervousness which we found that the value off the cell must be equal Open tomorrow Mine six which you will found that the value off, you know, off the cell is equal or 0.4 six vote. The total number off transfer electron is safe and no earnest equation will be ever for way he so equal, You know, so negative toe. All point or five Mine too. Divided by the number of transfer electron. Long magnesium. Well, stiff to power. Three times. Boy or H Negative. Power eight and avoiding the boy Alum Union. Oh, Agent, get there. Story or 84 may get there. And these Bauer one is wrong. OK, so this is the answer off these questions. Thank you.

In these questions we have some part and we have to write in a nest equation and we have to find out the pieces and they are given in order of distance. Okay so first of all for the first reaction easily sorry why not? Will be equal to 0.34 -237. Right, so this will be quite a 4.71 board. So now I have to find E. So the formula E is in a uh minus 0.059. The end and logos The concentration of MG two plus they were by the concentration of steel to place. Okay, so now just putting out the values what the way that is 2.71 -0.059 Divided by two. and logo of tend to depart minus two. They were invited to the part minus street. So he would come out to be quite well, 2.6805 ports. Similarly we can find out for the remaining parts. So first of all in order will be zero minus minus of 0.44 world. So this will be easy to find support for Born And even we were 2 0.44 -0.059 x two. And global Their concentration started into the R -3 the 1st 1. So this will be it will be one square Right? So this will be 4-0.5-85 ports. Calling on the card. Yes it is in order the quarter zero minus 0.14 0.14. Even the quarter zero appointment, both minus 0.59. And by two Logo, And 0.020 whole square Sportswear. Okay, so this will give us 0.0 airports. Why under the last option for adoption In what will be equal to 0 -1.08? That is -1 point the way once. So evil. We will do In order that is -1.08 -0.05952. And and the law we will have. Okay. And the law enumerators. We have one and then tina minute that we have into the par minus to the square And 0.03 to the back. Oh, Okay. So this will be 4-1.288. So these are thank you.

Hello over more. My name is on my money. In this question, we will solve with the Bharti a completely. Then it will be similar party and about C. So in birth a furs you must know the reactions that occur at a node and reaction that joker and gather, which is a reaction of Karen Allen, is Alamin. You is oxidized toe alleman in posted three plus three electron and the value off the not for these reaction is negative. 1.662 in Gasol Iron boasted to is accepting to electron 24 iron and the value off reduction potential is equal Negative Open for 40 So now drive the Knittig question We were time, these equation by two and these intensive properties it will be similar. But I will time these equation So I will write it here and the times's boy three. So we were removed. This two don't confuse goes in or is intensive value. So now that next question is to Willem immune plus re honorable stiff too, which, in form it toe Allah 1,000,000 posted three last three ire from this total with under the value off the not sell is equals negative off the north castle. Negative to the value off, you know. And don't forget that. So the value is equal negative or 0.4 fours, you know, negative to negative. 1.662 And the total transfer Electric is equal sex. So now we can either. The value off the search is equal According to Ner nous, enough off cell negative toe open toe Over 592 divided by the number off transfer electron law The concentration off I'm in, brother between aluminium posted three Bauer two divided by the concentration off iron impulsive to power three and he gives off that concentration off element in postive street is oh point money and off turn impulsive to which is your 0.85 So now the value off Eisel is equal. 1.24 mine vote so similar to the proceed er a which we can cleave that being empty which similar we found the value off Esa will be equal or Perrin sinks history a and no see So Onley b 12 b s er equal this value which first you mosque found the fall way first, right, The Hoff reaction Zan right. Need equation. And finally, right. Nervousness for med equation. So we solving involved with this mess up. Thank you.


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