5

2HgO(s) - 2Hgd) 0z(g)ZNa(s) - Hz(g) 2NaHi(s)C(s) 0-g1 C0-a2Cs6) Fyg) - 2CsF(s)ANH,(g) S0-(p = 4NOg Gt-O2)CHp) 50-4 3C0zg) 4HO(g)2H,0() 2Hz(g) 0.2Sg(s) 120,(g) 850,2...

Question

2HgO(s) - 2Hgd) 0z(g)ZNa(s) - Hz(g) 2NaHi(s)C(s) 0-g1 C0-a2Cs6) Fyg) - 2CsF(s)ANH,(g) S0-(p = 4NOg Gt-O2)CHp) 50-4 3C0zg) 4HO(g)2H,0() 2Hz(g) 0.2Sg(s) 120,(g) 850,2)Pats) 5C(g) POids}EEkI _ 4C5. Chapter = Chr nicz| Reac icns Ircie434} F13

2HgO(s) - 2Hgd) 0z(g) ZNa(s) - Hz(g) 2NaHi(s) C(s) 0-g1 C0-a 2Cs6) Fyg) - 2CsF(s) ANH,(g) S0-(p = 4NOg Gt-O2) CHp) 50-4 3C0zg) 4HO(g) 2H,0() 2Hz(g) 0.2 Sg(s) 120,(g) 850,2) Pats) 5C(g) POids} EEkI _ 4C5. Chapter = Chr nicz| Reac icns Ircie434} F13



Answers

$\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{COO} \underset{\text { red } \mathrm{P}}{\stackrel{\mathrm{Cl}_{2}}{\longrightarrow}} \mathrm{A} \stackrel{\mathrm{alc} \mathrm{KOH}}{\longrightarrow} \mathrm{B}$ What is $\mathrm{B} ?$ (a) $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CHO}$ (b) $\mathrm{ClCH}_{2} \mathrm{CH}_{2} \mathrm{COOH}$ (c) $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{COCl}$ (d) $\mathrm{CH}_{2}=\mathrm{CHCOOH}$

Yeah. To calculate the mass in grams that correspond to each of these mole quantities, we simply need to know the molar mass. In the case of an element, we go to the periodic table and it's found just below the chemical symbol. The molar mass of iron is 55.845 g per mole. Multiplying this mass value by the moles, moles cancel and we get 11.4 g iron to the three significant figures we started with If we have .79 mold floor een on the periodic table, 18.998 g of Florina is one mole. Multiplying these two numbers together gives us to just two significant figures 15 g Florentine. And if we have 58 moles carbon dioxide multiplying that by the molar mass of carbon dioxide, which is the mass of one mole carbon plus the massive two moles, oxygen given us 44.1 g per mole Gives us to just two significant figures 260 g carbon dioxide. And for the last one we have 48.1 moles potassium chrome eight. The molar mass is going to be the massive two molds, potassium plus the mass of one mole chromium and four moles of oxygen. Given us a total mass of 194 19 g per mole. So 48.1 moles corresponds to to just three significant figures 9340g

In this problem did yet then it happened something like this. CS three CH 2 C 00 quiet In presence of Sierra two. They fast for us at media reaction will take place and product for me. CS three CS SEAL c o H on further reaction with alcoholic a witch. It will give final product ID C. H to the well born c h c cocoa page according to the option Yes. Obscenity is correct answer option B. Each correct answer for this problem.

Okay, So for this one, we're told the s some encrypted messages that were encrypted using these cipher P plus 10 mod 26. Now, this was the encryption cipher. So to decrypt it, we need to undo that. Right? So we're going to use the decryption cipher P minus 10 mod 26. All right, so for a are given message is see e be be Oh, eggs an OBE, x y and G. OK, so first we need to convert that into numeric ce, where a call zero equals one Sequels to case of sea is going to ese for 11 14 23 13 14 and one, 23 24 and six. So now we could run it through our algorithm where we take the number. It's a track 10. And then take my 26. Right, So two months, 10 being negative. Eight mon 26 which is really 18. All right, so now well, cover into those numbers. So we get 18. Same thing here in native six month 26. That would be 20. Okay, then we get 17 17 four, 13 3 4 17 13 14 and 22. And then We just need to translate that back into the alphabet. So it's gonna be an S u R r e and D he r n o w spooky. It says surrender now it's probably how some of this homework makes you feel. Okay, So, onto part B here were given the phrase 00 W i p be s oh X. And so first, we want to translate this into the numbers numerals using the equal zero equals one Sequels too. Okay, so we get that Ella's 11. Oh, is 14 w is 22 eyes, eight p is 15 be is one s is 18 0 is 14 x is 23 it is 13 and I we're gonna use our cipher, right. Which recall is I'm going to be p minus 10 March 26. Yes. So when we take 11 minus 10 while 26 is could be the one 14 minus 10 is four 12 b negative. Tuesdays will be 24 five. That's negative. Nines. Women with 17 eighties gonna be 8 14 4 23 is 13 and 13 is three then Now we have to translate it back, and we do that we get Be? Yeah. And why f o r i e and d be my friend a little bit nicer than the last one. All right, so now we have the last one. Here we are, given the phrase d s. I should probably leave more space than this. A d s w Ow p Why be p e x? So again we translate it into the numbers using a zero beak Was one Sequels too? S o D is gonna be three s is 18 w is 22 0 is 14 a. P is 15. Why is 24 b is one? Why is 15 eat is four and X is 23. And then we put a cipher on it, which was P minus 10 mile 26 to get to the next stage. And when we do that. So this would be negative sevens that ends up giving us a 19. This will be an eight 12 four five, 14 1 becomes negative. Nine. That is a 17 five negative six is gonna be 20 and a 13. And then we translated back into letters, so ah, this time we get tea. I e f o r s u n time for fun

In this video, we will determine the values of the length you plus B and the angle alpha. Using these two diagrams and the information here in green. The first thing we can do is so for this angle which will call bait out data as you can see here is equal to 1 80 degrees minus data. So that is 180 -68 because we have the is 68° And so that is 1 12°. And now to find this length you possibly be, we can use the formula written here, which is that you plus feed. The magnitude of U. S B is equal to the square root of the magnitude of U squared plus the magnitude of v squared minus two times you times B times co sign beta. And so we can plug in the values we have into that And get that the magnitude of Yukos fee is 77 g. So finally we can use the law of sines to find alpha because we have this angle and this length and this length. So we know that sign beta over U plus V is equal to assign alpha over V, which means sign alpha equals B. Times. Sine beta over U plus V. And we can again plug in what we have, solve that sign Elvis is .26 and then Use our calculators to find that alpha is 15.4° and these are our two final answers.


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