5

Question 4 (1 point) Notice the two large craters in image #3. Estimate the relative age of the three features from oldest to voungest:1) The crater Ais the oldest;...

Question

Question 4 (1 point) Notice the two large craters in image #3. Estimate the relative age of the three features from oldest to voungest:1) The crater Ais the oldest; the smooth maria and crater B is the youngest 2) The crater B is the oldest, the smooth maria and crater A is the youngest3) Crater A is the oldest; crater B and the smooth maria is the youngest4) One is unable to decide their relative agesQuestion 5 (1 point) Examine the 8 images of Mars Which of the following have been observed on

Question 4 (1 point) Notice the two large craters in image #3. Estimate the relative age of the three features from oldest to voungest: 1) The crater Ais the oldest; the smooth maria and crater B is the youngest 2) The crater B is the oldest, the smooth maria and crater A is the youngest 3) Crater A is the oldest; crater B and the smooth maria is the youngest 4) One is unable to decide their relative ages Question 5 (1 point) Examine the 8 images of Mars Which of the following have been observed on the Martian surface? 1) impact



Answers

The International Astronomical Union adopted a plan to have all features on Venus (with a few exceptions for large features discovered earlier) named after historical or mythological women. Categories of features are paired with specific subcategories of women; for example, large craters (greater than about $15 \mathrm{km}$ ) are named after famous women, smaller craters have female first names, mountains are named after goddesses, and so on. Go to the Venus Crater Database (http://lpi.usra.edu/resources/vc/vchome.html), click on "Craters by Image Map," click on a region to zoom in on, and then select a few craters. For each crater, consider these questions: What is the "morphologic" class of the crater? Is there another crater very close by? What is the crater's diameter? How high is the elevation? Who was the large crater named after (if you didn't get a large one, go back to the starting address and click on "Craters by Descending Diameter")

So we're talking about the crater formation on mars. Obviously we can see them because there's no tectonic or uh tectonic or atmosphere activity to kind of wipe them out so they stay and we can see them for a long time. Um And that's approximately. The theory says that suggests that the frequency of large craters should fall off as the square of the diameter. So then we're given some data but we have the diameter and we have also they give us one over the diameter squared. I'm not sure what the units were in that meters maybe. Anyway. Um and so then we have the frequency. So what this says is that these ones out here, bigger ones values out here are actually smaller, smaller craters. And so they occur more frequently than larger craters, which occur less frequently. So we could just count the number of craters that, you know of this size. The number of craters, the size, the size the size, and what I see is that they do in fact form a pretty, pretty good line here. And so what we're doing here is we're fitting were fitting um we're saying that it's linear, The frequency is linear in one over the square. So we basically take one over D. Squared as our X. And we can sum all the ones all these up. And we get 0.001863. Now we take all the frequency values that we have and we send them up, we get 91 And then we take we multiply each each this times this and this times this and add them up. And we get 0.065852. Um we sum up all of these values squared, which is the sum of the two, the fourth, one over due to the fourth. And we get, you know, 1.3-7 -6. And then we only have four data points here. So uh we don't have a lot, but again, enough to see if maybe there's a trend here. So what we do is we can find the slope just as we had before. Some of our X X values times some of the Y values minus the number of data points times uh some of the cross products divided by some of the X value squared minus the number of data points times the some of the he um the X value square. And that gives us uh 51576. So that's that's the slope. And it's set for you to be a pretty large number because obviously these are very small and these are, you know, in the tens and we could get the intercept, which would, I guess we would expect to be B zero if this was perfect. That we get the intercept two B -1 27 So we have we plan our fit, we have this line here and you can see that if we were to make a fit, I guess a linear fit. That seems like a pretty good guess. So we can see that in fact, there it does seem like, you know this, you know, as the diameter, um you know, the frequency falls off or is proportional to the one over the diameter square. So as the it was, you get smaller and smaller creators, which means smaller and smaller Meteors hit. They hit more and more and more and more likely to hit.

Somewhat Recently, the moon has gone through periods of partial resurfacing. The areas that have not been resurfaced are much more heavily cratered than the areas that have been resurfaced. This means that the cratering must have happened long ago, before the resurfacing ever took place, So that means that Option A is the correct option.

Greater activity on planets and moons depend on how active the surface is of the planet or the moon. Everything gets hit by rocks, get hit by Meteors and meteorites and asteroids and all kinds of debris so forth. All throughout solar system. It is a cosmic pool table. Things hit each other all the time. The evidence lies in reference to how active or inactive, the surfaces. Earth has very active service, whether erosion, all kinds of things. So the earth has been hit and there are craters, but they wear away over time. So to rank these objects, these moons of in terms off creator activity well, say Callisto its first, because it does have heavy amount of craters and there's an inactive moon. So it's when inactive, there will be results off craters from all kinds of impacts to millions and millions of years. Ganymede would be the next because it is a formerly active moon. So did have some activity to road the craters. But no more Titan will be next. Because it is possibly an act of surface, it does have some weather patterns. It does have some cloud formations in an atmosphere, so those systems can erode. Her craters were impacts than I o. We'll have the least amount of prayers because it is an act of surface. You have all kinds of volcanoes and lava spewing all over the place, so that is completely going to change the surface on regular basis. So two ranking them from most dense craters, toe least dense amount. Creators. You go from Callisto to Ganymede to tighten toe Iowa.

Here for party. We know the period is equaling 27 hours times 3600 seconds. So, essentially, who you can say 97,200 seconds. So a little bit over a day. And we were asked to assume that the orbit is circular with a radius of 100,000 meters. And so we can then say we continues Kepler's law periods. Ah, which provides us with approximation to the asteroid's mass. So we can say that 97,200 this would be squared, that this would be equal to four pi squared, divided by the gravitational constant times the mass of the asteroid multiplied by the asteroids radius 100,000. Uh, and this would be quantity cubed. And we're essentially solving for M, and we find that the asteroid's mass is essentially rather approximately 6.3 times 10 to these 16 kilograms. This would be our answer for part A for part B. Now, um, we're going to divide the mass m by the given volume so we can say that the density is gonna be equal to the mass of the asteroid 6.3 times 10 to the 16 kilograms. The calculation the result that we just found in part A and then this would be divided by the volume of 1.41 times 10 to the 13th meters cubed. And the density is going to be equal to 4.4 times 10 to the third kilograms per cubic meter. Um, this is essentially, uh, 20 percent. Unless approximately 20% less dense then earth, This would be our final answer. That is the end of the solution. Thank you for watching.


Similar Solved Questions

5 answers
(2 points)Expand the function f(z)in a power series with center =0 41anz where an((-1)*n)((1/4)^(n41What is the interval of convergence? Give your answer using interval notation: If you need to use O , type INF . If there is only one point in the interval of convergence; the interval notation is [a]: For example; if 0 is the only point in the interval of convergence, you would answer with [0].The interval of convergence is (-1/4,1/4)
(2 points) Expand the function f(z) in a power series with center =0 41 anz where an ((-1)*n)((1/4)^(n 41 What is the interval of convergence? Give your answer using interval notation: If you need to use O , type INF . If there is only one point in the interval of convergence; the interval notation ...
5 answers
Vatkeai 1 { 21 1 Joti;( 2J= Sda,2tl Traned 1 1orul(51usionginSae1
Vatkeai 1 { 21 1 Joti;( 2 J= Sda,2tl Traned 1 1 orul (51usi ongin Sae 1...
4 answers
Question 210 ptsAplant biologist studies the heizht of sunflowers He measures large sample of sunflowers and creutes probability distribution The distribution normz shane with mean I12cm and standard deviation 16 cm; What is the probability {approximatelv} that sunflaw"cr less than 136cm tall?0.930.69Question 37pts
Question 2 10 pts Aplant biologist studies the heizht of sunflowers He measures large sample of sunflowers and creutes probability distribution The distribution normz shane with mean I12cm and standard deviation 16 cm; What is the probability {approximatelv} that sunflaw"cr less than 136cm tall...
5 answers
Two charges are located in the X-Y plane. If q1 3.05 nC and is located at (x = 0.00 m,y = 0.680 m), and the second charge has magnitude of 42 3.20 nC and is located at (x = 1.50 m,y = 0.550 m) , calculate the x and y components, Ex and Ey, of the electric field, E, in component form at the origin, (0,0). The Coulomb force constant is 1(4tco) 8.99 X 109 N m2/c2 _ExNICEyNIC
Two charges are located in the X-Y plane. If q1 3.05 nC and is located at (x = 0.00 m,y = 0.680 m), and the second charge has magnitude of 42 3.20 nC and is located at (x = 1.50 m,y = 0.550 m) , calculate the x and y components, Ex and Ey, of the electric field, E, in component form at the origin, (...
5 answers
What are the traits that differentiate leaders from their followers? Give a brief sketch of your favorite leader from your country.
What are the traits that differentiate leaders from their followers? Give a brief sketch of your favorite leader from your country....
5 answers
Give an example of a converging series of strictly positive terms $sum_{n=1}^{+infty} a_{n}$ such that $sum_{n=1}^{+infty}left(a_{n}ight)^{1 / n}$ diverges.
Give an example of a converging series of strictly positive terms $sum_{n=1}^{+infty} a_{n}$ such that $sum_{n=1}^{+infty}left(a_{n} ight)^{1 / n}$ diverges....
1 answers
A $12.0$ -g bullet is accelerated from rest to a speed of $700 \mathrm{~m} / \mathrm{s}$ as it travels $20.0 \mathrm{~cm}$ in a gun barrel. Assuming the acceleration to be constant, how large was the accelerating force? [Hint: Be careful with units.
A $12.0$ -g bullet is accelerated from rest to a speed of $700 \mathrm{~m} / \mathrm{s}$ as it travels $20.0 \mathrm{~cm}$ in a gun barrel. Assuming the acceleration to be constant, how large was the accelerating force? [Hint: Be careful with units....
5 answers
The Corey-Posner; Whiteside-House treatment of a [:1 ratio of lithium dibenzylcuprate and neopentyl bromide yields primarilyLithium dibenzylcuprate Corcy-Posner; Whiteside-HouseNeopentyl bromidemajor product
The Corey-Posner; Whiteside-House treatment of a [:1 ratio of lithium dibenzylcuprate and neopentyl bromide yields primarily Lithium dibenzylcuprate Corcy-Posner; Whiteside-House Neopentyl bromide major product...
5 answers
6. The characteristic that gives an element its distinctive properties is its number of__________.a. protonsb. neutronsc. electronsd. atoms
6. The characteristic that gives an element its distinctive properties is its number of__________. a. protons b. neutrons c. electrons d. atoms...
5 answers
Calculate the pH when 50.0 mL of0.100 M KOH is added to 100.0 mLof 0.050 M HCLPH =Mark for Review What"s This?
Calculate the pH when 50.0 mL of0.100 M KOH is added to 100.0 mLof 0.050 M HCL PH = Mark for Review What"s This?...
5 answers
Solve. Use the proportion method.7.4 is what percent of $50 ?$
Solve. Use the proportion method. 7.4 is what percent of $50 ?$...
5 answers
Provide an example that uses discrete probability?
Provide an example that uses discrete probability?...
5 answers
57 66) V3X 46h(x)asymptotes are X: 3 Vectic le X; 3 horizenta | asynp4 otes are ) 3 X-intercents ar X: 9 X " 3 Fiod Qation Al Fwoct;o^)"76 ) ( 6+36
57 66) V 3X 46 h(x) asymptotes are X: 3 Vectic le X; 3 horizenta | asynp4 otes are ) 3 X-intercents ar X: 9 X " 3 Fiod Qation Al Fwoct;o^) "76 ) ( 6+36...
5 answers
1) (10 points)The tangent plane and Y =[ for bx + Cy. Find the constants a,b,€f(xy) = 'ino) sinx) is of the form6 4
1) (10 points) The tangent plane and Y =[ for bx + Cy. Find the constants a,b,€ f(xy) = 'ino) sinx) is of the form 6 4...
5 answers
Find the volume of the solid generated in the following situation:The region R bounded by the graphs of x = 0,y = 4Vx, andy = 20 is revolved about the line y = 20.The volume of the solid described above is (Type an exact answer; using T as needed.)cubic units_
Find the volume of the solid generated in the following situation: The region R bounded by the graphs of x = 0,y = 4Vx, andy = 20 is revolved about the line y = 20. The volume of the solid described above is (Type an exact answer; using T as needed.) cubic units_...
5 answers
U uncharged circuit 48ft0r shown W B4i 8446 capacitor sNulon switch the has tatal J energy (in J) tha potential copacitance 0 20 pF Z i capocior'Select 350
U uncharged circuit 48ft0r shown W B4i 8446 capacitor sNulon switch the has tatal J energy (in J) tha potential copacitance 0 20 pF Z i capocior' Select 3 50...

-- 0.061615--