5

For particular reaction at 129.3 %C,4G = -1273.19 KJlmol , and AS 826.69 J(mol Calculete 4G for this rcaction96.9 'C.LGUJlmolTOOLS X1o...

Question

For particular reaction at 129.3 %C,4G = -1273.19 KJlmol , and AS 826.69 J(mol Calculete 4G for this rcaction96.9 'C.LGUJlmolTOOLS X1o

For particular reaction at 129.3 %C,4G = -1273.19 KJlmol , and AS 826.69 J(mol Calculete 4G for this rcaction 96.9 'C. LG UJlmol TOOLS X1o



Answers

For the reaction $2 \mathrm{NO}_{2}(\mathrm{g}) \rightleftharpoons 2 \mathrm{NO}(\mathrm{g})+\mathrm{O}_{2}(\mathrm{g}), \quad 1$ $K_{c}=1.8 \times 10^{-6}$ at $184^{\circ} \mathrm{C} .$ At $184^{\circ} \mathrm{C},$ the value of $K_{c}$ for the reaction $\mathrm{NO}(\mathrm{g})+\frac{1}{2} \mathrm{O}_{2}(\mathrm{g}) \rightleftharpoons \mathrm{NO}_{2}(\mathrm{g})$ is (a) $0.9 \times 10^{6}$ (b) $7.5 \times 10^{2}$ (c) $5.6 \times 10^{5}$ (d) $2.8 \times 10^{5}$

Question 79 wants to know what the activation energy is. If the rate triples going from 25°C to 35°C, well if the rate has tripled, that's because the rate constant value tripled. So using this form of the Iranians equation, we can solve for activation energy, K two is going to be three times K one. So that's what I'm going to put in there. And then we'll divide that by K. One. Set that equal to the activation energy divided by R. which is 8.314, multiplied by one over T. Two. Which is the 35 degrees Celsius to which we add to 73 And then -1 over T. one, which is 25°C to which we had to 73. You'll notice that the K once will cancel and this just becomes natural log of three. Doing the rest of the Algebra. We get 83,800 jewels.

Rooms Welcome back in this question. They are given this reaction sequence and we need to find out what is it. Okay, so first of all we'll just follow uh the step by step, festival will draw the structure of glycerol. So this is glycerol. Ok, ch two ch O. H. And C H 20 H. Okay, this is glass roll. So we are reacting this with cages so forth. Okay. And then we are hitting it. So when glycerol is hated with care to support, it produces a compound known as acro lead. Okay, so this compound, the formula is compounded ch two ch ch and double bond. Oh, okay, so this compound is formed and it gives to hydrogen to our two molecules of water. Okay, so what the sketches of four do cages for just dehydrate, this compound and ketone is formed and this uh product is known as equally. Okay. And uh two molecules of hydrogen are produced. Now the this compound which is formed, this compound is reacted with Zedan H G. And the presence of and the presence of concentrated exhale, Okay, in the presence of concentrated at sale. So what does this jink amalgam do? It converts? This uh reduces this uh Etone born. Okay, so uh the reaction of LD heights of ketones with zinc amalgam and concentrated hydrochloric acid, It reduces the alley cats and kittens to hydrocarbons. Okay, and this reduction is known as Clements and reduction. Okay, so uh this compound will be the uh this compound which is formed, this will be reduced to a hydrocarbon. So double burn will not be the fact that it doesn't reduce the double bond. So uh the compound formed will be CH three. So ah this has this early hide has been converted to hydrocarbon. So this is the product. Now this product is being treated that and B. S. And CCL four. Okay now this product is being treated with NBS and CCL four. Now what does NBS and CCL four does it attach is a bra mean on the highly carbon. Okay so if you check this is a double born. So this one this carbon will be a wily carbon. So it will attach a brahmin over here. So our final compound will be CH two, double born Ch CH two and a brahmin over here. So if you check from the options, we can say it is uh three brahma protein. Okay, so if you know 123, this is a bombing or our third carbon. So if I name this, it is three brahma coffee. Okay so this is a answer. Thank you

Hey, guys. So in this question, were given the decomposition reaction of die nitrogen pent oxide, which is first order were also given to temperatures and the given half lives at these temperatures. So right here I have those listed out and I've converted my temperatures to Kelvin by adding to 73 to my soc its values. Since this reaction is first order, I went ahead and used my half life equation for a first order reaction and calculated calculated my K values for each of these with these Aiken, like thes two K values, I can go ahead and calculate my activation energy, which is what the question is asking for for part a. So to do that, I'm going to use my arty gnaeus equation, which states that my natural log of K two over K one is going to be equal to my activation energy over my gas law. Constant times a quantity. You want over two to minus one over TV one with these. I'm gonna go ahead and plug in my case, my r and my tease, so I can easily solve for my activation energy. So for K to that 0.462 in verse hours over 0.308 In verse. Hours that's gonna be multiplied by my activation. Energy times negative one over My our value just 8.314 Jules per mole Kelvin. And this is going to be multiplied by the quantity 1/3. 13 Kelvin for temperature to over 1/2. 93 Kelvin 41 multiplying everything on both sides. I find that on the left I get 2.71 and this is equal to my activation energy times 2.62 times 10 to the negative. Five most radul solving. For my activation energy, I find that this is equal to 103,000 jewels from all. And to put this in a more useful unit, that's going to be equal to 103 killer jewels. Permal, this is my activation energy. And now that I have this, I can go ahead and calculate the que value for the, um, temperature of 30 degrees Celsius. So I'm gonna go ahead and use the artiness equation again. But this time since I'm given the ah constant a the artiness constant. I can go ahead and use the other form of this equation which states that the natural log off Mike A value is equal to negative of the activation energy over r T plus the natural log of my A value I can go ahead and ah sol for K my first exponentially ating both sides with E since the natural log has a base of E. And when I do that, my e and my natural law can't sell, Cancel out on the left and I'm left with an exponents on the right. So that's going to leave me with K being equal to e to the negative e a over rt plus the natural log of a Now, with this, I can go ahead and plug in my values. So my constant is going to be equal to e to the negative 103 times 10 to the third jewels per mole and converting to ah, Jules instead of killer jewels. Since my Gasol constant is ah has a jewell and a ah, not killer jewels in its units. So that's going to be 8.314 Jules formal Kelvin and our temperatures 30 degrees and this is and this is going to be equal to 303. Kelvin. With this, I'm gonna add the natural log of the ah artiness constant that was given to us, which is 2.5 times 10 to the 13th. And this has a unit of inver seconds. Plugging this expression into our calculator, we find that the K value at this given temperature is 3.6 times 10 to the negative five inverse seconds, and this is our final answer.

Were given this overall reaction, and we're told the equilibrium constant Casey, for this reaction in Parts A and B were given different forms of this chemical reaction that have been algebraic. We manipulated. And we want to change that given value of K accordingly, in order to determine what the K is for each reaction given in Parts A and B. One thing to keep in mind is that if we were to reverse this reaction and flip it the way that we would find the value of equilibrium, constant K for the reverse of that reaction would be the inverse of the forward reaction. Another thing to keep in mind is that if we were to multiply, be given reaction by a certain constant coefficient value so that all of the story key metric coefficients would change as a result of that constant that we multiplied the whenever that constant is then the resulting reaction as a K value raised to the power of that constant that we multiply so we can use those two sets of rules to help us work through part a part A. We noticed that we have n o plus h two. You going to end two plus h 20 which is the same forward reaction that were given. So we know that this is not a reverse of the given reaction. So that means that this rule does not apply. But if we look at the striking metric coefficients, we see that and no went from 2 to 1 and we examine end too. We see you went from one to 1/2 and when we compare those we can clear clearly see in order to go from the given reaction to the one given in part a that we multiplied each one of the striking metric coefficients by 1/2. So that means that 1/2 would be this constant value that we raise or the given value of K. So that means that K. C or the reaction part A is equal to given value of K raised to the power of 1/2 and that given value of K again was 6.5 times 10 squared. So that's 6.5 times 10 squared to the power of 1/2. And now when we calculate that out, we see that value of K for the reaction as it is written in part A is equal to about 25 0.5 in equilibrium. Constance do not have any units in part B. We see that we have end to plus H +20 going to U N o plus H two. We can see that that is the reverse of the given reaction. So we know that we need to at least take the inverse of the given k to account for that. But then when we look at this tricky metric coefficients, we see that they also changed so for or end to, for example, which had a stroke geometric coefficient of one. It now has a stroke geometric coefficient of to. So when we compare those, we can see that we multiplied given reaction by two. So we have to take K to the power of to after we also take the inverse of it to account for the fact that this is the reverse of the given reaction. So the expression that we can use to solve for que of the reaction per p is one over Ok, since this is a reverse reaction and that given K is raised to the power of to, since we multiplied the given reaction by a constant coefficient of to. So Casey is one over k squared where K is the given equilibrium constant in the problem which again was 6.5 times 10 squared. And again we square that when we solve out for K for the reaction written and party, we should get a final answer of about 2.37 times 10 to the power of negative six.


Similar Solved Questions

5 answers
8 quanttative I' data Eetnas Jnnan and 1 dovlalion1 1 0usunvutiont Duttuun
8 quanttative I' data Eetnas Jnnan and 1 dovlalion 1 1 0usunvutiont Duttuun...
5 answers
Sis part Of the paraboloid 2=x2+v cut Off by the plane % = 1. Find te area Qf the sunace $.
Sis part Of the paraboloid 2=x2+v cut Off by the plane % = 1. Find te area Qf the sunace $....
5 answers
Jewely maker sells 25 bracelets per Wcck It costs $15 In matetals to make each bracelet For every $1 decredse matana cost, ta jeweliy muker sells udditlonal bracelel. whch equaton can bo used to find the numbei Inatenal Cost decreases that WII result wcckly mutcnt cost $8757(15x)(25875(15X(25 (15 *(25 (19 4(475875HZ
jewely maker sells 25 bracelets per Wcck It costs $15 In matetals to make each bracelet For every $1 decredse matana cost, ta jeweliy muker sells udditlonal bracelel. whch equaton can bo used to find the numbei Inatenal Cost decreases that WII result wcckly mutcnt cost $8757 (15 x)(25 875 (15 X(25 (...
4 answers
3. Find the work done by the vector field F(T,y,2) = 2yi+e"j -2k moving particle along the curve given by 7() = (02,02 +2,0), 0 <t<1.
3. Find the work done by the vector field F(T,y,2) = 2yi+e"j -2k moving particle along the curve given by 7() = (02,02 +2,0), 0 <t<1....
5 answers
Perform the row operations on the matrix and wte the , resulbing mabiuReplace Ra by zR, + Rz3 00 A
Perform the row operations on the matrix and wte the , resulbing mabiu Replace Ra by zR, + Rz 3 00 A...
5 answers
Drag and drop Ihe correcl delinilions ol Type and Type Il errors In control charls Typa OIOr (a}:Type Il error (81:rejecting that the process is in confrol whonit is really oul of controlrejecting that the process is in control when it is redlly in controlfalling to reject Ihal Ihe process is in control when itis really in controltaling to reject Ihat the process is in control whon il is really ouf of control
Drag and drop Ihe correcl delinilions ol Type and Type Il errors In control charls Typa OIOr (a}: Type Il error (81: rejecting that the process is in confrol whonit is really oul of control rejecting that the process is in control when it is redlly in control falling to reject Ihal Ihe process is in...
5 answers
Oneucieprouucea by thyroid Blard; stirnuates contraction of the myometriumFudunge? auucuoe pilubialy' Blanbd; umulolce contraction Ihc Iy Oinictii4iW[Vullea OunIlulalciconiuun cteanMuiMatri conllchonIn 'QMIcuIunFudurMatunirto
Oneucie prouucea by thyroid Blard; stirnuates contraction of the myometrium Fudunge? auucuoe pilubialy' Blanbd; umulolce contraction Ihc Iy Oinictii4iW [Vullea Oun Ilulalciconiuun ctea nMui Matri conllchon In 'QMIcuIun Fudur Matunirto...
5 answers
A 1.74 L aqueous solution of KOH contains [79 g of KOH. The solution has density of 1.29 gmL. Calculate the molarity (M) , molality (m) , and mass percent concentration of the solution,molarity: 2244.6molality: 569,663643mass percent: 79.746948
A 1.74 L aqueous solution of KOH contains [79 g of KOH. The solution has density of 1.29 gmL. Calculate the molarity (M) , molality (m) , and mass percent concentration of the solution, molarity: 2244.6 molality: 569,663643 mass percent: 79.746948...
5 answers
9. (20) Prove or disprove: Choose one_ (1) A map defined by T is linear transformation: x + 2y (2) Aset defined by W = {(x,y) € R?Ix-y=3, x+Zy = 0 } isa subspace of the Euclidean space R2
9. (20) Prove or disprove: Choose one_ (1) A map defined by T is linear transformation: x + 2y (2) Aset defined by W = {(x,y) € R?Ix-y=3, x+Zy = 0 } isa subspace of the Euclidean space R2...
5 answers
In each part, use the given information to find the nullity of the linear transformation $T$.(a) $T: R^{5} ightarrow R^{7}$ has rank 3(b) $T: P_{4} ightarrow P_{3}$ has rank 1(c) The range of $T: R^{6} ightarrow R^{3}$ is $R^{3}$.(d) $T: M_{22} ightarrow M_{22}$ has rank 3
In each part, use the given information to find the nullity of the linear transformation $T$. (a) $T: R^{5} \rightarrow R^{7}$ has rank 3 (b) $T: P_{4} \rightarrow P_{3}$ has rank 1 (c) The range of $T: R^{6} \rightarrow R^{3}$ is $R^{3}$. (d) $T: M_{22} \rightarrow M_{22}$ has rank 3...
5 answers
Describe the level surfaces of the functions specified.$$f(x, y, z)=|x|+|y|+|z|$$
Describe the level surfaces of the functions specified. $$f(x, y, z)=|x|+|y|+|z|$$...
5 answers
Differentiate y = sin -1(2/5): y'
Differentiate y = sin -1(2/5): y'...
5 answers
Solve and check.$$6 x=-54$$
Solve and check. $$6 x=-54$$...
5 answers
Uso Ilc Fourier (rauslorm (o solve M"(r) 1 2r'() | f(c) = g(r) for * € R, expressing Uhc solution ns # convolution.
Uso Ilc Fourier (rauslorm (o solve M"(r) 1 2r'() | f(c) = g(r) for * € R, expressing Uhc solution ns # convolution....
5 answers
Two forces are shown in the figure. Force A has magnitude 7units and angle α is 40 degrees. Force B has magnitude 19units and angle β is 44 degrees. Calculate the directionof the sum of the two forces. Write your answer in degrees from thepositive X-axis. (note: the lengths and angles of forces inthe figure are not to proper scale).
Two forces are shown in the figure. Force A has magnitude 7 units and angle α is 40 degrees. Force B has magnitude 19 units and angle β is 44 degrees. Calculate the direction of the sum of the two forces. Write your answer in degrees from the positive X-axis. (note: the lengths and angles of ...
4 answers
You Define prograrice aempato to the to soiveah JH the the You problem programming are assignment required problem 8 1 for through the the furnished application information of the OCT/NOV Do 1 OPR371S [25] (13) not (12}
You Define prograrice aempato to the to soiveah JH the the You problem programming are assignment required problem 8 1 for through the the furnished application information of the OCT/NOV Do 1 OPR371S [25] (13) not (12}...
4 answers
Sketch the region R of integration and switch the order of integration LJ f(x, Y) dy dxLIS fx, Y) dy dx =f(x, Y) dx dy
Sketch the region R of integration and switch the order of integration LJ f(x, Y) dy dx LIS fx, Y) dy dx = f(x, Y) dx dy...
5 answers
Use integration by parts to find the integral.fx In 3x dx0A 1 3 +2 In 3x - 9 +2 +C 0 B. 3 2 In 3x + 3 *+c 0 c: 3 X in3x-12*+c 0 D. In 3x - 1 x+C 3
Use integration by parts to find the integral. fx In 3x dx 0A 1 3 +2 In 3x - 9 +2 +C 0 B. 3 2 In 3x + 3 *+c 0 c: 3 X in3x-12*+c 0 D. In 3x - 1 x+C 3...

-- 0.019803--