Hi, intelligent problem. There is our solenoid and that solidarity is having two layers first of all the in earlier your disease in earlier, which is scaring the current in clockwise direction you've seen from the right hand. Now there is And outer coil also wound in the similar fashion like this. And this outer coil is carrying the current in counter clockwise direction again, as seen from the right end of this solid night. No, it has given that number of terms. Our unit land in the in earlier is anyone is equal to 200 turns per centimeter. Or we can say this is 200,000 means to lack turns birth nita. Similarly, that in the outer layer is either 180 per centimeter or they will come out to be one like 80,000 for me to then current in inner coil is I even is equal to 10 ampere. And that in outer coil That is I two is equal to 15 years as the currents are in opposite direction. So the magnetic field produced at the center of the solenoid will also be in opposite directions. Now, in the first part of the problem, we have to find the direction of net magnetic field here in this solid noi. So to find it as the direction due to the outer coy is towards right, because here this outer coil means which is shown in red, the current is passing in counter clockwise direction. So this counterclockwise direction will make it uh north pole. And we know the magnetic will always comes out of the north pole. And that is because of the outer coil means the secondary coil. So this is B2, which will be coming out similarly the direction of current due to this inner coil that is clockwise here, this is clockwise. So it will make a south fall and we know magnetic enters into the south pole. So the magnetic field here will be entering into this right end towards left. Even no the direction of magnetic field due to outer coil is towards right and that due to inner coil is towards left. We have discussed about it in the background. Now using the expression for this magnetic field is equal to you note and into I. Where N is the number of transporting plant. It is clear that this magnetic field depends directly on the number of terms multiplied by the number of transporting length multiplied by the current passing through the call. Therefore, for Beavan, This N one into I wan will be given by you lack multiplied by 10. So it comes out to be 20 left ampere And this end to I two for B2, this will be one like 80,000, multiplied by 15. So it comes out to be To like 70,000. So It is clear that be too will be greater than be one And the direction of B two is towards right. So net magnetic field also worse. Right? And this is the answer for the first part of the problem. Now, in the second part of the problem we have to find that net magnetic field Which will be given by B 2 -71. So here, this is new not and to I two minus knew not and won I won taking this mu not as a common out this is end to I two minus and one I want. So Using four pi into 10 days par -7 Tesla meter per ampere for this mu note then and two I two is two 70000 -200 00 zero. So finally, this answer for the net magnetic field here comes out to be 8.8 into tended bar -2 S. La, which is the answer For the 2nd part of the problem. Thank you.