Okay, so in this problem, we have a box. So I sports here. Arbaugh are books. This is a really bad books. Let's do it again. Okay. Ah, what else? And we want to calculate in the first part What is the volume? The density volume charge at the position that's put here in green of the position. Uh, 0.3. That is correct. Little 0.3 meters. Okay, so So we know that the electric field is describe here. This is the electric field line and here is entering in one side of the box, Um, leaving on the other side of the box. The IV area vector off the surface off the letter of the boxes is going to be one pointing here and the order pointing in here. Okay. Therefore, to calculate the charge density charge that we want, we must look, we must remember about the electric flux, and we know that the electric flux is described us the electric shoot multiply by the area motor vibrate because sign off teeter, which is also equal the charge inside divided by absolute zero. OK, but the charge inside in this problem is going to be the density that we want to calculate. That multiplies the volume off the box divided by absolute zero. No, we can calculate what we want. So let's look to desecration. Here we have that the electric feud there multiplies the area multiplies because sign off, Teeter is going to be equal hope feet divided by absolute zero. But there is only one problem here. We want the net electric flux. And this year is not in that electric flux. This is the flux from one of the surface. So the natural electric flux is going to be something like this. Ah, is going to be the electric flux through the first face Miners, the electric flux through the second face. Okay, not minus plus. Sorry. So the net flux is the flux. True, the face one. We lost the flux through the face to, and then we can use desecration. So the equation that we must so is going to be simply fight to just the electric future. Um, electric fields there multiplies the area. One the multiplies because sign off 1 80 plus the electric field, the multiplies the area to they're multiplies the core sign off zero degrees and that is equal. Ho v divided by absolute zero. Okay, so now miscalculate what we actually want. So we know that the electric field is constant. Electric feud is constant. And let me see what is the area off. Okay, so we know that the electric field is express us six times 10 to the tree or to simplify is just 600 multiplies the area, the multiplies, the ex the first X. Let's call the X one is square. Go sign off 1 80 which is negative. So that's what Here. Uh, negative. X one square, los X two square, Go side of zero. Richest one. This is equal to Hope V absolute zero. Okay, so who is the position? X one is 0.3, as we can see in the initiate of the problem. So this is just 600. A de multiplies negative. Um, zero point three square. Tell us 0.3. Pull us the X square. This is a product that we must. So So this is going to be zero point three square loss to actually, uh, plus zero point six g x. Tell us DX is square. Okay, which is equal to hold V absolute zero. So if we neglect the D X Square because it's too small is a differential so small that we can neglect We only have 0.3 bless 0.6 d x. So as we can see, we have negative 0.3 plus 0.3 can cross this one and we can simply five or equation to just 600. Hey, they're multiplies 0.6 dx, which is equal to hope. Who is the volume? The volume is just a d x, the area times the differential element divided by absolute zero. Then we can see that we can cross the area we can cross the D X and our density charge that we want to calculate is going to be just ho equals, uh, 600. That multiplies 0.6 that multiplies absolute zero. So this is just actually now that I see, I forgot the zero here. This is not 600. We have six to the power, but six times tend to the tree. This is 6000. Sorry, guys. I forgot to zero here a zero here and a zero here. Because of that, we also forgot a zero in here. 6000 and Knox is a 600. Okay, now that is correct. If remote supply all this, we know that absolute zero is going to be equal eight point 85 for two times tented a minus 12. Therefore, we have density. Charge off three points. 18. 19. Sorry. Group or 19 times tend to the miners. Eight cool apps per meters. Q Bix, That's the answer to the first part and the second bart way. We must answer if this region ah, could be inside a conductor and well, the answer is no, because the field will have to be zero. Because it's so small, it have to be zero. Therefore, bestie, final answer. Thanks for watching, Okay?