Question
Title = q3a5 For which of the following reactions is the ASsystem positive?Agt(aq) + CI(aq) = AgCI (s)2SO3lg) == 2SOz(g) Ozlg)COz (g) + CaO(s) CaCOz(s)Nzlg) 3Hz(g) == 2NH3(g)HzO() ~ HzO(s)
title = q3a5 For which of the following reactions is the ASsystem positive? Agt(aq) + CI(aq) = AgCI (s) 2SO3lg) == 2SOz(g) Ozlg) COz (g) + CaO(s) CaCOz(s) Nzlg) 3Hz(g) == 2NH3(g) HzO() ~ HzO(s)


Answers
Classify the following elementary reactions as unimolecular, bimolecular, or termolecular: (a) $2 \mathrm{NO}+\mathrm{Br}_{2} \longrightarrow 2 \mathrm{NOBr}$ (b) $\mathrm{CH}_{3} \mathrm{NC} \longrightarrow \mathrm{CH}_{3} \mathrm{CN}$ (c) $\mathrm{SO}+\mathrm{O}_{2} \longrightarrow \mathrm{SO}_{2}+\mathrm{O}$
All right, so we have to predict the products of these reactions. If they happen, right, you'll give the activity. Siri's nearby for some of these. But some of these more obvious phones, like a right, um, you have a hydrocarbon, and you have oxygen. So we're gonna call this a combustion reaction, right? And, uh, like your stereotypical combustion reaction, we're gonna form a CO two in water as products, and then you just have to balance the equation, right, So we could start with carbon. So two carbons of both sides will get six hundreds of both sides, but we have to oxygen's. And after we balance, it looks like we have seven options on this side. So the one thing you can do right is put seven over to as the coefficient. Or then once you figure that out and you put the seven over to that, you could multiply the entire every coefficient in the equation by too. So you'll get to see 286702 will give you four co two and six h 20 both of those air acceptable answers. Um, whichever, uh, your teacher prefers, right? So, um, the hydrogen that I've drawn a narrow, um, each edged us all four is also on the activity Siri's. And you'll notice that aluminum is higher on the activity. Serious? It's more active. Um, so you're going to get a, um, a single displacement reaction or just displacing reaction. Um, so call that disk. Right. So you're gonna form Ah, hydrogen gas. The hydrants are gonna leave its hydrogen guests, and you're gonna form aluminum sulfate. Um, So here's the thing, though. Right? You have to You have to have charge balance. So aluminum is in group 13. Aluminum gets a positive three charge, and sulfate is a poly atomic eye on with a two minus. So how do we balance the charge of this molecule? So, um, when it comes to these guys, you're gonna have to find a common multiple, right? So the common multiple of the charge, uh, looks like it's gonna be six. So you'll need to aluminum's toe have positive six. And it looks like you'll need three sulfates tohave minus six. That gives the overall compound zero write. Zero charged a neutral compounds. So you're gonna have to aluminums and three sulfates. Then we have to balance the equation. So if we're gonna have to aluminum is, we could put it to hear three sulfates for the three here, um, so that those aluminums and sulfates or balanced the Hodgins now unbalanced so that that was the last thing you have to do. So we have six here. Um, so you could put a three here. Um, and it looks like we're all We're all set now, so that's a displacement reaction. Um, this one. This one's kind of tricky. So, um, nice green gas, plus magnesium metal. Right. So there's nothing in the textbook that says this reaction, um, wouldn't happen. Um, there were no exceptions. Right? So under really high heat, you could actually get magnesium metal to react with nitrogen gas, and it forms what's called the night. Tried. So one of the poly atomic guy and you might have learned about is any three minus. Um, So any three minus is a minus three charge, right? Magnesium has a plus to charge. It's in group two, so they all have positive two charges, so it looks like we're gonna have to have to charge balance again. Right? So the common multiple does the exact same math we just did. That's a mistake. Um, exact same math we just did on the last, uh, the last white board for the last part. Right. So we're gonna have to have minus six charge, and that will be three mag museums to cancel that charge out. So we get zero. Right, So you'll have magnesium nitride. Um, and we have to balance the magnesium sze that trends look Okay, so once you put a three in front of magnesium, it looks like you're good. This is a synthesis reaction, right? Because we have to react. It's two elements that are forming one product a new compounds. If I could suppose that this is right. Uh huh. Get to say this this reaction, um, so sodium carbonate. Right. So we have sodium any to s 03 So the book describes the heating of carbonates on the wine writing, writing and red. But the heating of carbonates gives you the release of CO two gas. Um, and you form metal oxides. Right? So oxide has minus two charge sodium missing group Wanna has a positive one charge right to the common denominator here. Um, was common denominator. The kind of multiple here is minus two. So we're gonna keep one oxide, but we're gonna need to sew diems to cancel out the charge. So you're gonna have to put it to there. And I think we're all balanced. We don't have to touch anything here. Um, and because we have one reacted and we have two products, this is gonna be a decomposition reaction. So finally we get to e. Right. So we have magnesium nitrate. Equus was all nitrates or acquiesce according to the side ability rule. And we have sodium sulfates. Um, and also, faiths are soluble, except for group two, and silver ends lead. Those are the rules. Um, so with that being said right with these double displacement reactions in order to get, um, but let's write the theoretical products first. Right, So you're gonna get a swap of the metals, so you're going to get, ah, sodium, nitrates and all nitrates are soluble, so that's gonna be that's gonna be fine, right? And you're gonna form one of equivalent of magnesium sulfate. So this is gonna be a quiz, because all nitrates or soluble in water and according to the rule. All sulfates except those of group to silver and lead are soluble. So magnesium is in group two g too, Right? Um so according to the text book, um, group to sulfates are insoluble, so this is gonna be a solid. So that would mean that this reaction does occur because we form a solid in the process. Um, and I'm getting these rules from page to 88 in chapter eight under the writing dynamics equations, right. So with the help of displacement reactions in the products, you have to form something that's a solid a gas or some kind of molecular compounds like water formation would be a product that would make these reactions happen. But if everything is a quiz, when you write about the an equation, everything's gonna cancel out. You're gonna have the same number of ions in the products, and you're gonna have the same number of each eye on in the reactions. Everything's gonna cancel out. You're not gonna get a single reaction, right? So but in this case, it looks like you have the formation of magnesium sulfate. Is your net ionic equation? Um, because magnesium sulfate, according to the text book, is not soluble in water
In this problem, the characteristics in our I'm writing here, So just look at it carefully. The first one age, R CH and double one CH two plus SCN will give uh C h C L. Cst and another reaction will be this uh c h double bone CH two plus I had to be uh in Potenza. But outside will give this component are CH two, CH two, The Yeah, So according to the option, option A and option C. Are correct answer.
What is the major product off the foreign reactions? Okay, attitude, Furin and nitric acid. This reaction is net creation and for pure rings, its preferred to the off position Boom Reformation off lateral self in. Also preferred to there off the position. Yeah, but insulation over there in midfield. I mean period in there too. Graphic examples. However, this new graphic center is significantly deactivated by the Eltron Well drawn. Expect off nativism so the period of nitrogen will be insulated, preferential and after information these natural will be given more exaggerated. So information off this position is much less likely. Caliban is a total media toe Drugs period in and looking after ex substitution with force for a strike, right will substitute social group with Gran here Everyone we're throwing interfered with This group will make the first group much more acidic than usual. So Okay, the base will give you demented And then the generated nuclear file will nuclear physical attack from other heart causing outdoor compensation and after but the nation You have this alcohol which is very likely to be dehydrated toe the double bunk because off stabilizing effect off the conjugation between double bank and the eloquent regrowing put amounted period um, green. Here, the granular election work will act as a strong base. It will depart on age nitrogen off viral nitrogen off viral with hydrogen hydrogen has a much higher acidity because the deeper automatic form is aromatic, the six electrons so deep resignation will occur and that's all group with the put alleged toe insane.
In this problem, I can write the reaction edge. Just look at it carefully. This compound is treatable 10 NH two in pageants of we are to any which will give this compound. Here it is NH two and this component pigeons off c s t d c o c L will give this compound as the product. Here it is energy. See you CST. So according to the option, option B, correct answer. I hope you understand the solution of this problem as how are you? Right the reaction of this problem.