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Urea; (NHzhCO, which is widely used in fertilizers and plastics is quite soluble in water: If you dissolve 6.32 2 of urea in 15.9 mL of water; what is the vapor pre...

Question

Urea; (NHzhCO, which is widely used in fertilizers and plastics is quite soluble in water: If you dissolve 6.32 2 of urea in 15.9 mL of water; what is the vapor pressure of the solution at 24 -C? Assume the density of water is [.00 g mL The vapor pressure of water at 24 -€ is 22.4 mmHg:mHg

Urea; (NHzhCO, which is widely used in fertilizers and plastics is quite soluble in water: If you dissolve 6.32 2 of urea in 15.9 mL of water; what is the vapor pressure of the solution at 24 -C? Assume the density of water is [.00 g mL The vapor pressure of water at 24 -€ is 22.4 mmHg: mHg



Answers

Urea, $\left(\mathrm{NH}_{2}\right)_{2} \mathrm{CO},$ which is widely used in fertilizers and plastics, is quite soluble in water. If you dissolve $9.00 \mathrm{g}$ of urea in $10.0 \mathrm{mL}$ of water, what is the vapor pressure of the solution at $24^{\circ} \mathrm{C} ?$ Assume the density of water is $1.00 \mathrm{g} / \mathrm{mL}.$

So let's start by using our vapor pressure lowering equation. Okay. Where the vapor pressure over a solution is the mole fraction of the solvent times of vapor pressure of the pure solvent. So, we've got some information given to us. We know the vapor pressure of the solution. We don't know the mole fraction of the solvent and we know the vapor pressure of the pure solvent. So we can solve for the mole fraction of our water, which gives us 0.8390 So the mole fraction of the salute, which is your area is simply one minus that. All right, The two more fractions have to add up to one. So that's 0.1610 So let's go ahead and assume that we have one mall of solution. Okay, You consume anything you want? That's just a little easier because then I can say that I have 0.16 10 malls of your area and I have 0.83 90 moles of our water. So let's go ahead and change this to grams. That will change malls two g. Here. He is 66 g per mole. So I would have 9.67 g mm. Do the same thing here for the water. And change moles to grams one malls 18 to So I'd have 15.12 g of water. We're gonna add those up to get our total massive solution. So I'll give us 24 0.79 g of solution. And I can use our density to change grams. two mL here. It was 1.6 g is one millimeter. So this gives us 23 0.4 mil leaders of our solution. Mhm. Well, if I had 9670 g of your area in 23 4 mL of solution. How much would I have in our 250 mL of solution. Okay. And I would have 103 g of iria. Similarly for the water, if I had 15.12 g of water in 23 4 millimeters, how much would that be in our 2 50? So that's going to be 162 g of water. Okay, So the answer to how to make the solution is we're going to go ahead and dissolve 103 g of your area in 162 g of water.

Hello, everyone. And thanks for joining me, Miss Hallstrom. Today we're gonna be talking about morality, determination, and we're going to be using vapor pressures. And this is a several part problems, so be ready. Okay. First of all, we're given that a solution containing the solvent area and the vapor pray in a quiz solution. I should write a quick solution. And our givens are the vapor pressure of pure water are solvent, and our vapor pressure appear. Water is 23.76 millimeters mercury. We're given the vapor pressure of our solution, and that will be a little less. And that is 22.97 millimeters of mercury. And we're told that this reaction is that this solution is at 27 degrees Celsius and we're not going to need that. Okay, so let's make a plan. Our step one is we're going to use Our solution equals our mole fraction of our solvent times p of our solvent in water to find our mole fraction. That's step one. And then we'll know our mole fraction over solvent. And remember, the mole fraction of the solvent, which is step two, is moles of water. over Moles of Water plus moles of our Salyut, which is Yuria. And then we're going to use this knowledge right here for step two and we're gonna take the mole fraction that we've calculated from Step One our answer from number one. And we're going to say, Let's dissolve some unknown number of bulls X of Yuria in one mole of water So we'll have one mole in one more and we'll solve for X that will give us moles of Yuria. Once we have that Step three will be finding morality using our answer from number two Moles of Yuria And we will also be dividing that by the kilogram mass of one mole of water are solvent. Okay, let's begin. Step one If you recall r p of our solution is let me find that here 22 0.97 Mmh g equals the mole fraction of her solvent times The pressure of our solvent was 23.76 Can't get my parentheses there anyway, solving for the mole fraction of our solvent. This is pretty easy. We get it all wrong Later zero point 9667 But and that has no units. Okay. And number two again, We're going to take our mole fraction. All right, this down. Both fraction equals one mole of water. We're gonna pretend we have a mole of water, and we need to divide that by our one mole of water plus X. However many moles of area we have. So we're going to sub 0.96675 equals one over one plus x in these or moles. I should have left room there. Okay. Solving for X in this equation, X equals 0.344 more of our solvent. So now I know moles of solvent, which is one of the things I need for morality before we do our morality calculation. Remember that we said we have one mole of our solve it, which is water and water is 18.2 um, grams per mall decided that backwards, and then we're going to convert our grams two kilograms. So our kilograms will be, um, zero point 018 zero a little bit more room here. 0.180 kilograms of solvent and morality equals moles of Salyut divided by kilograms of solvent. Easy peasy, lemon squeezy. 0.344 bowls divided by 0.180 kilograms. And the answer is let me look back. But my answers here, it looks like I can have three significant figures. 1.91 more. Well, this is the concentration of her solution. Not too bad. Thanks for joining me.

Professor solution to solve for the malaria morality off the solution. We need the malls off salute That is Yuria and the kilograms off soul went It is water. If we assume that we have one more off water we know the mass off water using the change in Weber pressure we can solve for the mall Fraction off Furia and then the malls off Yuria now sold for the mole fraction off Yuria. We have the occasional delta equal toe even note minus P even is called toe xto. Your note here even note, is the partial pressure off a soul went over solution Everyone is given, by the way per pressure off the pure soul When that is, Delta equal to 23.7 six mm h g minus 22.98 am MSG which is equal to 0.78 AM MSG. Now we have the equation that delta equal to X curia multiplied by P water so exactly equal to Delta P by P. Voter here substituting the values and solving, we get the value 0.33 Now as you we have one mole off water now solve form also Furia. So exterior Equal tome also Furia, divided by moles off Yuria place malls off water here by substituting the value we get them. Also, Furia is 0.34 more now one more off water has a mass off 18.2 g or 0.1802 kg. We now know the malls off salute Yuria and the kilograms off solvent water so we can solve for the morality off the solution. So we know the formula for morality is equal to malls Off salute divided by malls, off solvent in kilogram. Here we put in the values and solving we get. The final value is 1.9 mole. So the morality is equal to 1.9 am So this is the complete solution Step by step in detail. Please go through this

Hello, everyone. Thanks for joining me, Miss Hallstrom, As we do a problem using rolled slaw roads. Law is as follows. The vapor pressure of a solution is equal to the mole. Fraction of the solvent multiplied to the pressure paper pressure of the pure solvent. Okay, for the problem that we're going to consider today, and I'm gonna I think I have room on this page. We're going to be using Yuria as our Salyut in areas. Chemical formula is an H. She put that and each to CEO, and we're given that we have 600 58 grams of water, which, of course, is our solvent. We're told that the vapour pressure appear water at our system temperature of 30 degrees Celsius is equal to 31.8 millimeters mercury and were asked to So for are unknown. Is grams of Yuria required for a solution with a vapor pressure 2.50 I'm gonna move that to the next line. 2.50 mm HD less then are 31.8 mm h g. So you might want to back up. I'll try to summarize this a little bit more as we're going through the problem set up. Okay, Number one, we need to find our mole fraction of our solvent. We were given 658 grams of water and we know the molar mass of water is Excuse me is 18.2 grams per mole. So 6 58 divided by 18.2 Not going around till a little later. That's how many moles of water I have. And for more fraction, we need moles of our solvent divided by moles of our entire solution. So we're going to have 36.515 Moles of solvent divided by 36.515 plus some unknown number X and X at this point are lower Case X is bowls of our Salyut, which it was Yuria R p for our solution is going to be Let me look at those numbers again. It's going to be 31 0.8 minus 2.50 both of these air millimeters mercury. And when we do this math, we get 29.3 millimeters mercury and our people are water was given as this that this is our people are solvent Okay, I'm going to write the equation right here. The whole equation. 29.3 mm. H g equals 36.515 Moles over 36.515 bulls plus x times 31.8. Mm. H g. Okay. And I wanted you to just get that one down. I'm gonna very quickly right this again. I'm gonna leave units off this times just to save a little time. Okay? First thing. Oh, divide each side by 31.8. That gives us 0.9214 equals 36.515 over 36.515 plus X. Next, we're going to multiply Each side by this term were to multiply each side by this term, which gives me 0.9214 times 36.515 plus X equals 36.515 Take a moment. Make sure you know I multiplied each side by that, that I'm going to distribute this and I end up with 33.644 plus 0.9214 x equals 36.515 Subtract this from each side so I'm going Teoh minus 33.644 minus 33.644 This crosses off. I get 0.9214 X equals 2.871 Divide each side by divide each side By this term or excuse me, this we get X equals 3.1159 balls. That's how many moles of you really need. We were as for grams. So let's convert grams to malls. Excuse me, Let's convert moles to grams by multiplying moles of Yuria And you can trust me on this and making the assumption everybody knows how to do molar masses By the molar mass of Yuria which 60 point is 60.6 grams per mole and the answer is 187 grams of Yuria And there it is. Thank you so much for joining me


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