Today we'll be finding the average rate of change of a few time intervals based on the table, and we will use the equation. The average rate of change equals F A B minus f eb over B minus a. The first interval. We have one comma two and, uh, for this one A is one. And these two so ffb will be 1018 And if the vehicle will be 0.33 divided by two minus one, and that will give us negative 0.1 5/1, which is negative, 0.15 and the unit is grams for a desolate ER over hours. For the second one, our intervals 1.5 comma two and at 1.5 it's 0.24 and again at 2.18 7.18 minus point 0 to 4 over two, minus 1.5. And that will be negative 0.6 over 0.5, which will give us negative 0.12 grams. Her desolate er over ours. The third interval. We have two commas 2.5, and at 2.5 it's 0.12 and as to its again 0.18 So we will have 0.1 to minus 0.18 divided by 2.5 minus two. I'll give us negative 0.6 over 0.5, which will be negative 0.12 grams for a desolate ER over ours. Our last interval is two comma three at 3.7 and that, too, is 0.18 So we'll have 0.7 minus 0.18 over three minus two, and I will give us negative 0.1 1/1, which is just 0.11 grams her. That's the leader over ours and that finishes off part A for part B. It asked us to find the incident rate of instantaneous rate of change. AT T equals two, if you look back in the chart were given two equals two. However, this is not what we want to be looking at. This number is not the instantaneous sort of change. What we need to do is find two numbers. They give us an average of two. For example, 1.5 and 2.5 and find the average rate of change between those two. And we will use again this equation, so the interval will be 1.52 point five. That's a bracket, and at 2.5 it's 0.12 and at 1.5 it's 0.0 to 4. So we'll have 0.1 to minus 0.0 to 4, divided by 2.5 minus 1.5. That will give us negative 0.12 over one, which is 10.12 grams for a desolate ER over ours. And what this means is, after two hours, the uh, the amount is decreasing by £0.12 per desolate as per hour.