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Enxlc _ Name AlrodhworPHYS 218 Test 31: Falcons tuck their = wings = and free-fall falcon straight down from above when diving prey- Suppose starts its dive from = ...

Question

Enxlc _ Name AlrodhworPHYS 218 Test 31: Falcons tuck their = wings = and free-fall falcon straight down from above when diving prey- Suppose starts its dive from = height of 60.0 m above pigeon_ The pigeon notices the falcon when i Is 20.0 m away and Ibegins its own free-fall dive to escape, albeit unsuccessfully: How far In m wlll dne pigeon dive before it is caught by the falcon? ha 60.0 m 9 Vot 5 &t fuus^ -9.6 mls 0+- { (-.8)+1 60-(-20 Jom 74315 40 (igan 8.16 +32.86s

Enxlc _ Name Alrodhwor PHYS 218 Test 3 1: Falcons tuck their = wings = and free-fall falcon straight down from above when diving prey- Suppose starts its dive from = height of 60.0 m above pigeon_ The pigeon notices the falcon when i Is 20.0 m away and Ibegins its own free-fall dive to escape, albeit unsuccessfully: How far In m wlll dne pigeon dive before it is caught by the falcon? ha 60.0 m 9 Vot 5 &t fuus^ -9.6 mls 0+- { (-.8)+1 60-(-20 Jom 74315 40 (igan 8.16 +32.86s



Answers

A peregrine falcon dives at a pigeon, The falcon starts downward from rest with free-fall acceleration. If the pigcon is $76.0 \mathrm{m}$ below the initial position of the falcon, how long does the falcon take to reach the pigeon? Assume that the pigcon remains at rest.

This 81 number problem in which the initial height of the Falcon it's given s equal to 100 ft and the speed with which it is jiving diving is two under 20 ft per second. So and when it will hit the pigeon, I will become equal to zero, which means we will be using ah minus 60 NTS squad plus HVT plus it s equal to etch and plugging all the values we will be having minus X twenties word plus 220 t miss 100 equal to zero letters Divide both sides by minus four. We will be getting for the Esquire minus 55 D minus 25 equal to zero, which is in the form off. It is squired less BT plus equal to zero. So t will be equal to minus B plus minus B Esquire minus 40 c, by the way. So let us complete the history questions. We will be having April before vehicle to minus 35 see ableto Why is 25 so time when we could go minus me plus miners me square minus four in tow, end to see do into for so this identify plus miners views can do to Yes, 8200 for 25. I eat so there in victory. Really? Lefty, I need 55 minus 1024. Letter to find by under if you bless the fight by eight. Okay, so venues will be. I never feel up. Little point for four. You see him under will be 55 less on the door before. That is well being a client. 19 seconds. So this is negative. Lunn Being looked at that time cannot be negative. So the real approximately being what important? 19 2nd. Thank you.

This is a even number problem in Fitch. If Falcon is at a height off initial, I'd like to say initial it 100 ft and it is diving downward with any cell velocity of 220 ft. Presidents. It will remind us 220 ft for a second when, after detonating ground, it side will be zero. So we'll be using minus 16 d squared, plus HVT plus s equal to etch that is plugging all the values it will become minus 16 t Esquire's minus 220 t plus 100 equal to +00 little divide both sides by minus four. This will be 40 x squared plus 55 D minus 25 equal to zero. So which in the form off? 80 Esquire plus BT plus equal to zero in which people were equal to minus B plus minus B squared minus 40 c And the route, by the way. So let us find the value of tea. Using these three questions, he will be minus B that is minus 55 plus minus 55 whole squared minus four in tow for indoor Honest and defoe do it. But to win 24 So this season, minus 55. Bless minus. It's a big toe. Do five squad. Yes, for him. Three for fire, but it So we have time minus five, minus three for 500 by eight and minus five. Place for 500. But it this will definitely be negative. So be lifted as time cannot be negative. So we have equal toe. You mind if I yes, a little 4 to 5 by eight. That is six point 69 seconds. Approximately this media time. Thank you.

All right. So 0.90 killing of Falcon is 28 years for second. They're an angle of 35 degrees below the horizontal er of the world on a few market there. Right. And then here's this uses port of, you know, 0.3 to 5 kilograms of it flying horizontally. Um, and they stick together. And the question is, what is there combined? Velocity and angle like that. Okay, what we're gonna do is we're going to actually figure out components of the momentum here. Right? So the Falcon, Okay, we'll figure out the X component and why component? And we're just gonna add them together. The dove. Really? Because in this collision, the momentum is not gonna change. Okay, so let's figure this out. Right. The dumb is easy, right? The doves Original X, no momentum is gonna be played 3 to 5 times seven. They re convict this. Okay, on. Let's see 0.3 to 5. Correct? Yes. Times seven. That's correct. This is 2.275 That's killing around meters per second, and that's in the X direction. It's going to be zero in the wider actions. There's not any of that right. Okay. And then the dove is gonna be, um, in the X direction. We have 35 degrees. We're gonna use the coast sign, so it's gonna be 0.9 times 28 times, Khost 35 because it's the adjacent side to that angle. Right? We make sure that I have in degrees, and indeed I am, Marcus. 0.9 times, 28 times. Khost 35. And the x component of this guy's momentum is going to be 20 0.6426 Okay, so let's see. Store that in memory register. There isn't in the y. Component here is going to be 0.9 times 28. This is just m times V. Right time sighing of 35. Okay. What is that? So this is Queen nine times. 28 times signed 35. And this is going to be noticed that it's a downward component here. You. So we gotta make this guy negative. So this is gonna be negative. 14 0.454 I'm gonna store that in some memory. Interesting. There we go. And that's kilogram meters per second. OK, so now we have to do is just add these guys together. OK, so that guy plus two twinge. Whatever. There it is. This is 22.918 and this one is negative. 14 point for four kilograms, meters per second. And now we have to do. This is kilograms meters per second. Now we have to do is figure out um, the magnitude of the spectre. Okay, so let's drop. Make sure this guy this is a momentous vector. I will get the velocity. I guess by dividing by the combined mass to this side is 14.454 This is 22.98 Hot noose would be the square root uh, 22.918 squared plus 14 point or 54 square. So what is that? And we grabbed this guy that guy squared amusing like, exact values in my calculator or more or less exact values. Okay, uh, squared. So I'm getting 27.95 This is momentum. Remember, this is kilograms meters per second. So we're not We don't have the answer yet. We will get the angle be the same. Of course. And then that angle is gonna be tan minus one 14.454 over 22.918 I expect that to be an adorable angle. Okay. Sudsy inverse tangent of that kind of. I This guy, we're getting 32.2 degrees. Do you use it? See, we've got an answer here. Oh, yeah. Uh, okay. And then let's figure out what the with the velocity is, right. You know, the momentum is 27.95 That zero kilogram meters per second on. And then the mass is one time mass are masses 0.9 plus 0.3 to 5. Says that 1.2 to 5.9 plus punk. Yeah, at 1.2 to 5, killing her hands. Right. So the velocity is going to be just momentum divided by mass, right? 27.95 divided by 1.2 to 5. Okay, hold on. Get that man. Magnitude divided by the mass. 22.1 meters per second. Okay, so it is if we draw a picture of it and got use red for this, right? It is combined velocity of both birds. Corporates. Okay, I is 22.1 meters per second, and then this angle is, uh You see, it was 32.2 degrees. There you go. All right.

In this problem, we're going to talk about conservation of linear momentum. Eso are we need to remember first, is that the linear woman toe p associate ID with the movement of particle is equal to the mass off a particle times the Velocity V. Also, if we have two particles and they're moving with different philosophies, let's save you one envy, too. And let's say that these particles undergo a collision. So the momentum of the first particle p one because the momentum of the second particle, too that's the total initial momentum, is equal to the final moments about the first particle. Cuban crime was the final momentum of the second particle P to crime. Okay, and I I have to consider in our problem is a falcon that has a mess off 480 g. Uh, that goes into a dive. That means that it's moving. It moves completely downwards with a speed V and reaches occasion with the speed V of 45 m per second. So this is the speed of the falcon downward. The pigeon that's caught by the Falcon has a mass off 200 and 40 g, and initially it's a breast, Okay? And then the fucking grabs the pigeon. Ah, and holds it in its mouth. Inclusion and way also know that the collision between the two birds last time t of 0.1 five seconds Question a our voice to find what is the speed off the, uh of the birds, the birds after the collision. So what we need to do here is to apply conservation of honorable men To have that the massive welcome times the speed of the Falcon is equal to the masses of Falcon because the massive patient this is the total final mass times the speed of the whole system. Notice that initially the patient does not have momentum because it's speedy. Zero So V is equal to m f divided by M f close and P time this week. Uh, actually, this this is Yeah, I'm sorry. So v is 480 g, divided by 480 plus 240 times via and VF is 45 m per second. So we is 30 m. Recycle that in question. Be We have to calculate what is the average force that the Falcon exerts over the page. So we need to remember is that the impose can be written as the average horse times the time long wage the force was applied on. This is equal to the variation in momentum off the object upon which the forces exerted. In our case, we want to know the forces that over the vision So we're gonna calculate the change momentum of division. Initially, the vision had no velocity. So the change of momentum is just the final woman. So as is in P green divided by doubt that you on the massive vision is 0.24 kg. The velocity the speed is 30 m per second as we found in question A and then we divided by 0.0 15 seconds. So after is equal to 480 nutrients. And this concludes our exercise


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