5

[-2 ~1 A = 2 0 0 5GivenFind the determinant of the matrix ASelect one: a.-12b: 12c 10d.-10...

Question

[-2 ~1 A = 2 0 0 5GivenFind the determinant of the matrix ASelect one: a.-12b: 12c 10d.-10

[-2 ~1 A = 2 0 0 5 Given Find the determinant of the matrix A Select one: a.-12 b: 12 c 10 d.-10



Answers

Find the determinant of the matrix. $$\left[\begin{array}{llll} 0 & b & 0 & 0 \\ 0 & 0 & c & 0 \\ a & 0 & 0 & 0 \\ 0 & 0 & 0 & d \end{array}\right]$$

Hello there. So here we go. On Thes matrix is a four by four matrix, and we need to compute the determinant, uh, using the expansion by co factors. Okay, so let's start by considering the second row. Okay? So when we're when we're computing the determinant using the expansion by co factors, we need to fix, um row or column. In this case, e mentioned, it already is the second row. So the formula for that determinant is equals to 8 to 1, see toe one plus a two to see to to plus 8 to 3 C +23 until last 8 to 4 c two four And here you can observe that these entries on the metrics are zero. So that implies that thes elements here are zero. The A's corresponds to the entries on the on the metrics. So that's why all these terms are equals to zero right now. So we just need to focus on the factors. See 21 So, just to remind you the formula to compute the cool factor is for the factors C. I. J is equal to minus one to the power off I plus J times. The minor I j So basically, what this formula say that if in case that the summation off the indices is off, then we need to change the sign off the minor. In case that the estimation is even then we just maintain the same value off the minor. Okay, so taking that, taking that into account the factors ito want this decimation of two plus one is three, which is a not number. So we need to put here a minus sign. So minus one on the minor off the position to one corresponds to eliminate the second row on the first call on we. And with these matrix here for 71 5, 10 5 on 050 Okay, so here we need to complete this determinant is a three by three matrix. So we're going to apply the same procedure, the expansion by co factors. In this case, I'm going to focus on the last row. I'm going to take this element which corresponds to the coefficients. The A on the associated co factor that corresponds to this matrix that form here. So, basically, this co factors Ito one is equal to minus one from this part the five from the formula on the determinant off. 4155 Okay. And this is equal to minus one times minus 75 which is equal to 75. Okay, so I'm going to ride that here. C 21 is equal to 75 on. Then we need to multiply. The by the entry 81 8 to 1 is equal. You can observe. Here is three is the only element, non zero on that row three. So that implies that the determinant off this matrix is equals. 23 times 75 which is It was 2 225. Now we're going to take another reference, not the second row, but the column number four. Okay, so let me copy here really fast at the Matrix again. Yeah. Oh, 300 Okay. 85 10, 5, 6050 Okay, so we need to focus now on the fourth cold. I mean, this part here. So the formula for the determinant in this case is equals to a 41 a. 14 a 14 C 14 plus 8 to 4 c +24 plus a +34 c +34 on plus a +44 C +44 Here, the zero entries corresponds to see +44 on C 24 So we need to compute C 34 and C 14 Okay, so C 14 is equal to take in this element here. We eliminate the first roll, this fourth column and we end. Uh, I'm sorry. I forgot. Here. This mention off these industries is five, which is off. So we need to put here minus one. Then this multiply to the determinant off this matrix. 85 10 605 Okay, on here, we're going to use again expansion by co factors. And we obtain here minus one. From this part here, we're going to choose the first row off this matrix to complete the determinant. So it's just three on eliminate. We eliminate this first row first column, and we end with these metrics here, and we need to compute the determinant off the matrix 5 10 05 And this is equal to minus 75. Then we need to compute these term here to see 34 So the C 34 The summation off this in this is again off So we need to put here a minus one on multiplying the determinant off. What matrix? Well, the Matrix is Oh, yeah. We need to eliminate the third role on the fourth call. So we end with these metrics here for So here We got minus 247 85 10 on 605 Okay. Oh, sorry. Here is here is 300 Okay, great. So again, here, use the expanding by CO factors to compute this turning. So we choose this role because he's the one that have the mawr zeros. So it becomes easier to compute the determining so minus one here three, we eliminate the second roll the first column and we end with this matrix here for 705 on the result off. This is equal to minus on. Dhere, we got Yes, I forgot. Here the three is in the position to one, so we need to add also minus sign here. So it's other minus one on, then. Times three, this will be positive. So at the end, we obtained three times 20 and this is equals to 60. Okay, so let me regret here again. All so we got that the formula for the determinant is equal to a 14 c 14 plus a +34 C +34 Because the other ones are the A 14 is equal toe, want a 34 is equals to five and the values off the co factors are C 14 is minus 75 on C 34 is equals to 60. So the formula give us that the determinant is equal to minus 75 plus five times six. This is equal to 225.

So this question asks us to find the determinant of the Matrix if it exists. And so first we noticed that the Matrix A is a square matrix, and so therefore the determinant must exist. Um, and so over here I just have a general matrix m with a B c d. As its components. And we know that for two by two matrix, the determined is simply just a D minus BC. And so we can use this for determine it for finding the determinant of a. So we get zero times zero, which is just zero minus b type C, which is negative one times two. We see that this is just cool to two. Positive too. And so that is our answer. The determinant l A is too

Hello there. So here we got these metrics three by three matrix on We need to complete the determinant by using the expansion bike of factors. So let's start by taking as reference the second row. So the role in this case that we're going to take into account is too. So this role, basically, we need to focus on this part. So just Thio, remember how it's done. The host computed the determinant off a matrix by, uh, by expanding cough by expansion of co factors is basically in this case, we need to take a reference row or a column in this case, the second World. So the formula is 8 to 1 c toe one plus a two to see 22 on plus a +23 c +23 You can notice that here we can change the way we change the role. Then this formal will change. We can either choose a row or a column, and we're going to see that the result will not change. Yeah, So what? So the entries this a 11 a one a two to a 23 corresponds to the entries off the matrix on here. The sea to one city to and see 23 corresponds to the co factors just to remind you, the co factors say I j is computed as minus one. And this made to the power off the summation off the indices on the minor. Okay, so basically, this formula for the factor is just taking the minor on. In case that the information off these indices is off, then we need to change the sign to the minor. Otherwise, we just copy the value in case that I plus J is even. We just need to copy the value off the minor. So that's how we're going to compute here. These the determinant. So let's start with C 21 Okay. Uh, sorry, but we need thio also taking what advice for thes entries. So 8 to 1 corresponds to this entry on the Matrix and is equals to zero. So it doesn't make sense to compute the co factors into one because there is all at the end will be there. So we just need to focus on 62 63. So city too. The information off these numbers are is four. So we don't need to change anything, so we need to compute the minor. So that means taking here this position to to eliminating the second row on the second column here and then appear a matrix. The matrix five minus 31 and three. We need to take the determinant off. These Matri's under determinant off. This matrix is 18 on. We need to repeat this procedure with the next factor, but let me erase here these lines. Great. 12 03 Okay, so now we need to take the C 23 factor. The summation off these two indices is five, which is off. So we need to put here minus one, and then the minor, the minor in this case, is taking out the second row on the third column, just as is specified here on the indices on. Then we need to take the remaining matrix 5016 uncompleted determinant for that matrix. Here. The result is minus 30. Great. So we got the co factors on the entry so we can compute the determinant. So the entries a 18 to 1 here. All right. 822 is equals to 12 on 8 to 3 is equal 24 Okay, So de determinant off a is equal to 12 times 18 plus four times minus 30 on the result of this is equal to 96. Okay, so that is the value of the determine if we choose the Second World Now, we're going to repeat this procedure, but taking now a column instead off a rock. So now we're going to take the second column. So the column will be the second one. So the matrix I'm going to copy here really fast. 50 minus 30 12 for 16 and three. Okay, so now we need to take into account this. Come here. So in that case did determinant off these metrics will be 812 C 12 plus 8 to 2 C 22 and plus eight, 32 three to see 32 So the first thing is that a 12 is equal to zero. We have already complete the value of city, too. City to was equals to 18 on. So we just need to complete the value of C 32 on the co factory off three C 32 is equal. First, the summation off the indices is off. So we need to put here a minus one and then the minor. So c three to is this position. We eliminate the third role on the second color. We have these matrix and we need to complete the determine off this which is equals to minus 20 at the end. So we got the value for the co factors and we can replace the values and take computer determinants. So the determinant off the matrix A is equal to 12 times 18 from this part, plus six time minus 20 and this is equal to 96 as well.

We have eight number problem in which let us assume a determinant is given us 2.2 minus 1.4. Was it a 0.5 and one comma? 1.0. So we need to find determinant off A which is equal to 2.2 minus 1.4. They opened fire and 1.0 Okay, So we will be finding by multiplying days to and then performing the oppression of subjection. So 2.2 into one minus minus 1.4 into 0.5, which is two point to bless little 0.7. That is 2.9. This will be the answer. Thank you so


Similar Solved Questions

5 answers
1 Departien 1 Matb eigenvalues- ~eigenvectors 5 ict Phyelce 4' L, method T(hath > 4 LLLLLOULHLL 77) solve the following - system:
1 Departien 1 Matb eigenvalues- ~eigenvectors 5 ict Phyelce 4' L, method T(hath > 4 LLLLLOULHLL 77) solve the following - system:...
5 answers
C ,yHzOz(ppm]C &#die
C ,yHzOz (ppm] C & # die...
5 answers
Use the graph o f (x) shown below graphy =4-f()CannnlaaenvulrbiruIvReilaci Abou Ve-4 Roloc #Kcu * E4rSren UpraldSha DowlaaldCutetUndo Resaish Ratsech
Use the graph o f (x) shown below graphy =4-f() Cannnlaaen vulrbiruIv Reilaci Abou Ve-4 Roloc #Kcu * E4r Sren Uprald Sha Dowlaald Cutet Undo Resai sh Rat sech...
1 answers
Consider a symmetric step-index waveguide [see Eq. (29.1)] with $n_{1}=1.50, n_{2}=1.46, d=4 \mu \mathrm{m}$ operating at $\lambda_{0}=0.6328 \mu \mathrm{m} .$ Calculate the number of $\mathrm{TE}$ and $\mathrm{TM}$ modes.
Consider a symmetric step-index waveguide [see Eq. (29.1)] with $n_{1}=1.50, n_{2}=1.46, d=4 \mu \mathrm{m}$ operating at $\lambda_{0}=0.6328 \mu \mathrm{m} .$ Calculate the number of $\mathrm{TE}$ and $\mathrm{TM}$ modes....
5 answers
W 1 1 6 V L [ 1 1 1 1 1 U 1 1 1 1 1 1 L 1 1 1 1 1 1 1 ] 0 X 1 1 1 1 1 2 1 E 1 iil { 1
W 1 1 6 V L [ 1 1 1 1 1 U 1 1 1 1 1 1 L 1 1 1 1 1 1 1 ] 0 X 1 1 1 1 1 2 1 E 1 iil { 1...
5 answers
[C] A 30-meter length of steel cable with linear density of 8 kilograms per meter is dangling from winch How much work is required to wind the entire chain on the winch? When converting mass to weight use g =9.8 m/sec?_ Be sure to EVALUATE the integral required to answer the question. (12pts)Include diagram that clearly illustrates what your variable represents_
[C] A 30-meter length of steel cable with linear density of 8 kilograms per meter is dangling from winch How much work is required to wind the entire chain on the winch? When converting mass to weight use g =9.8 m/sec?_ Be sure to EVALUATE the integral required to answer the question. (12pts) Includ...
5 answers
F(xi) 1.0 1.218280 1,.2494612 1.2782413 1.30473
f(xi) 1.0 1.21828 0 1,.24946 12 1.27824 13 1.30473...
5 answers
Suppose another unbiased estimator (call it Aof the population mean is a sample statistic with astandard error equal σA=σn1/3Then Ais preferable as an estimator for the population mean.Select one:TrueFalse
Suppose another unbiased estimator (call it A of the population mean is a sample statistic with a standard error equal σA=σn1/3 Then A is preferable as an estimator for the population mean. Select one: True False...
1 answers
Which neutral atom is isoelectronic with each of the following ions? $\mathrm{Ga} ^{3+}, \mathrm{Zr}^{4+}, \mathrm{Mn}^{7+}, \mathrm{I}^{-}, \mathrm{Pb}^{2+}.$
Which neutral atom is isoelectronic with each of the following ions? $\mathrm{Ga} ^{3+}, \mathrm{Zr}^{4+}, \mathrm{Mn}^{7+}, \mathrm{I}^{-}, \mathrm{Pb}^{2+}.$...
5 answers
So Ive for X ? 6
So Ive for X ? 6...
5 answers
Evaluate lim (1+2x + 2)""x X-0Click "submit assignment in the right side of this screen to submit your solution:
Evaluate lim (1+2x + 2)""x X-0 Click "submit assignment in the right side of this screen to submit your solution:...
5 answers
Time (in min Total Distance Traveled (in milesYou are road tripping for Spring Break with friends You leave your house at 3.30 and start recording the total miles you have traveled at five minute interva2520.2 25.7 31.8 39.5 45. C 67.9 75.6Find the regression equation of the data using matrices and the ideas ' of inverses and identiities8687.895.4100102_
Time (in min Total Distance Traveled (in miles You are road tripping for Spring Break with friends You leave your house at 3.30 and start recording the total miles you have traveled at five minute interva 25 20.2 25.7 31.8 39.5 45. C 67.9 75.6 Find the regression equation of the data using matrices ...
5 answers
A rod of length L, carrying a uniform charge/length 2, lies along the X-axis, centered at x =0. Find the electric field E distance 2 away from the rod, along its perpendicular bisector The integral that you should get is easiest to do trigonometrically: It may be helpful that d(tan8)d0 = sec?0.
A rod of length L, carrying a uniform charge/length 2, lies along the X-axis, centered at x =0. Find the electric field E distance 2 away from the rod, along its perpendicular bisector The integral that you should get is easiest to do trigonometrically: It may be helpful that d(tan8)d0 = sec?0....
5 answers
1 J 1 1 1 1 6 8 L 1 L 1 4 1 [ V V 1 1 1 We ! 1 JUK 1 8 3
1 J 1 1 1 1 6 8 L 1 L 1 4 1 [ V V 1 1 1 We ! 1 JUK 1 8 3...

-- 0.021629--