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Determine the t-percentile that Is required to construct each of the Level: following pne sided confidenceConfidence level 99.9%, degrees of freedom =17Petermineith...

Question

Determine the t-percentile that Is required to construct each of the Level: following pne sided confidenceConfidence level 99.9%, degrees of freedom =17Petermineithe t-percentile that Is required to construct each of the following two sided confidendel level:Confidence level 9586, degrees of freedom =21

Determine the t-percentile that Is required to construct each of the Level: following pne sided confidence Confidence level 99.9%, degrees of freedom =17 Petermineithe t-percentile that Is required to construct each of the following two sided confidendel level: Confidence level 9586, degrees of freedom =21



Answers

Find the critical value $z_{c}$ necessary to construct a confidence interval at the level of confidence c. $c=0.85$

For this problem. We have four parts. We need to determine the level of competence given, uh, uh, confidence coefficient. And, uh, each time disease given, like, for example, the football 1.64 We can use the technology like, before, and, uh, find that, uh, the area. Find one when a south found the confidence ever war we can use, Um, the people. So from from the table, if we're looking for the value closest toe 4645 is 1.65 That corresponds to the point. Might be were not a people person will be. His, uh, six began from, uh, Tabo. We can't find 0.95 or 25 person talking. You hear this table business? Hey, uh, is the two point seven deprived trust part 2.58 the popular? So, uh, is the my 90%? That's part of the problem. When the equals for this one, we do not have a value. A box of years. You all right? Four. Oh, have the cab rate. For example, Baltimore CPF from negative point. You're why people All right, The area comes to be 0.9596 So that the last 6% here

Uh huh. We want to construct the confidence interval for P 11 sp two given the data X one and one X two M two at 95% confidence. This question is testing an understanding of how to build a confidence interval about the difference of population of 14 P. One and P. Two. We proceed through steps A through D. Listed here to stall. But first a we calculate the point estimates of one and two. He had one and he had to. This is the hot one equals excellent over and one we had to have two of them to next and be because of the critical Z scores well for over two for 95% confidence from a normal curve we used a Z. Table. Let's give Z off over to 1.96 next and see repetitive, confident digital itself. So the bounds of confidence and people are given by P. Had 11 sp had to remind us that critical Z score times the statement in the square root sign. This gives bound negative 110.48 to 90.0 to zero to go to. This doesn't include zero, So we interpret this to mean where 95% confidence the difference of proportions within our internal bounds and that he had one is less than we had to.

The following is a solution to number one. And we're asked to find a 90% confidence interval for the difference of the two population means given this uh sample data. So we're gonna use to sample Z interval because the sample size is so large. Whenever the sample size is greater than 30 that's kind of the magic number. The Z. And the T interval are essentially the same thing. So we're just gonna use the tea interval and the way we do that on C. I. T. Four, if you go to stat and then tests, it's this ninth option down here, the two samp Z. And that stands for two samples. The intervals click nine. And then under the summary stats, make sure this is highlighted. Now we're given the sample uh standard deviation but this one asked for the population standard deviation to just put the sample standard deviations here for signal one sigma, two, your ex bar, you're in For the first sample and then your X. Bar, and then you're in for the second sample the sea level, since this is a 90% confidence. And what we'll do .9 and then we calculate and that's about 4.2 and 5.8. Let's go and write that down. So it's going to be ill Not round just so we have a very accurate answer 4.19 6 1 all the way up to 5.8039. So that's the 90% confidence interval Using that data and then the second part, it's the same thing. But this time it's the 99% confidence interval and then we have different data down here, we're still going to use the Z ah the two samples the interval because that sample size is large enough where it basically converges to the T interval. So we'll go to stat and then tests and it's the ninth option. Now we'll have to actually change these. So the S one which is signal one was nine. The S. Two which in this case will be sigma two is four And then the X one bar is negative -112. And then that sample size was 30 and then the X two bar was negative 98. And then that sample size was 40 And then that sea level. Remember we want to do a 99% confidence interval. So 99 and then we calculate And that gives us this here. So negative 18.54 and negative 9.465. So let's go and write that down. So parentheses negative 18.54. All the way up to -9465. So that is our two samples, the interval for these two data sets

So for this problem we're going to find the confidence level and the significance level for A 90 confidence interval And then also for a 99 confidence interval. Okay so let's start with a so mhm confidence level Yeah thanks. It's actually going to be our confidence interval just in decimal form. So for a what was 90%? We move the decimal over two places. So our confidence level is just going to be 0.90 now to find our significance level. Mhm Yeah is going to be one minus Well we actually want this is a here is going to be one minus my confidence level or my confidence interval? Sorry my confidence level. Uh Okay so one 0.9 is going to be 0.1. So that's going to be my confidence level for a and then my significance level four A as well now for be my confidence level is my confidence interval Decimal form. So I move the decimal over two places. So that's going to be 0.99 for my confidence level and then for my significant level of significance level, yes, is going to be 1 -0.99, which means that is going to be 0.01 for my significance level.


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