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30. Ethanol has a density of 659 kg/m ' If the speed of sound in ethanol is 1162 m/s, what is its bulk modulus? 1.7 x 108 Pa 8.9 x 108 Pa 2.2 x 108 Pa 6.1 X 10...

Question

30. Ethanol has a density of 659 kg/m ' If the speed of sound in ethanol is 1162 m/s, what is its bulk modulus? 1.7 x 108 Pa 8.9 x 108 Pa 2.2 x 108 Pa 6.1 X 109 Pa 7.7 x 108 Pa31_ Is ethanol easier to compress Or harder to compress than water? easier harder

30. Ethanol has a density of 659 kg/m ' If the speed of sound in ethanol is 1162 m/s, what is its bulk modulus? 1.7 x 108 Pa 8.9 x 108 Pa 2.2 x 108 Pa 6.1 X 109 Pa 7.7 x 108 Pa 31_ Is ethanol easier to compress Or harder to compress than water? easier harder



Answers

What is the speed of sound in gasoline? The bulk modulus for gasoline is $1.3 \times 109 \mathrm{~N} / \mathrm{m} 2^{1.3 \times 10^{9} \mathrm{~N} / \mathrm{m}^{2}}$. The density of gasoline is $0.74 \mathrm{~kg} / \mathrm{L}$.

Using the information provided. Let's calculate the density of the object. So the volume of ethanol displaced. Okay. Is equal to the volume of the object. Yeah. Yeah. Yeah. Mhm. Mhm. So let's let the volume okay. Of ethanol displaced equals V. Still the mass. Uh huh. Ethanol displaced support. The density kinds of volume. The density of ethanol is When 789 grounds for centimeters cubed. This would be the centimetres cubed Units there and this would work out 2.789 v. Graham. Mhm. So the difference in weight after adding the object. Okay. Yeah. Mhm. Yeah. Mhm. Mhm. Mhm. Okay. Mhm. Is 10.5 grounds. Therefore, um we know that the Um the object is 15.8 g. 15 eight g minus 0.78 nine V grams Is equal to 10.5 g. And solving this here, we can solve that V. is equal to 6.7 so therefore the volume. Yeah. Of the displaced object. Yeah. Mhm. Is 6.7 cm cubed. So now we can calculate the density for our object Because we know that the mass of the object is 158 g. The volume is 6.7 cm cubed, and our density here works at 2-4 grams per centimeters cubed. Mhm. Yeah.

Everyone in this question. And they said, that is eternal residency to a 0.78 for your grand career, man, calculate the one limb off. They did a gram of eternal. So first of all, they given made up what they've given, you know, we have given the city. So the city is called to 0.7 18 for you, Grand Prairie, then while you Yes, the next. Red. Yeah, 82 g. So, yeah, The city is equality, loss upon London, and they're full. Mhm. One live is equal to density. Do mass upon Daisy. One million sequel. What is the number? Yeah. Therefore who are living is equal to master density, and that is equal to the bosses. 82. You everybody in cities wine seven ready for you Take me. They didn't find Yeah, And therefore Okay, one room is equality. 105 playing, you know, nine for, um For you. Mm. Yeah, yeah, yeah.

Using the information divided what volume of ethanol contains the same number of molecules as a leader of water. So we know that a leader of water is equal to kilogram of water. Let's find out how many molecules are in a kilogram of water. First convert this 2g, 1 kg equivalent to 1000 g. Yeah. And moller mouths here 18 g Of water equivalent to one mole. And in one mole of water We have 612 times 10 to the 23rd water molecules. Mhm. And this would be equal to one kg. I was 1000 to get into grounds Divided by 18 times avocados number. This is gonna give me 334 Times 10 to the 25th each. Sure molecules. Now this is equal to the number of Ethanol molecules. So we'd have 3.34 times 10 to the 25th ethanol. Mhm. I have an ulcer is C two H 508 molecules. So let's find the mass of there's many molecules. Yeah. Mhm. Yeah. So 6.2 times 10, Yeah. The norm molecules in one more ethanol And one mole of ethanol. See more amounts of 46 g. And this would give us 3.34 times in 25th, divided by avocados. Number Times 46.0. Give me 255 Tend to be three g. Uh after all. And using the density the volume uh ethanol mm. Yeah, request of the mass of the density of each. So the masses. 2.55 times 10 to the third grams. Divided by the density of ethanol, Which is .789 grounds for millimeter seven man. Give me 3.23 Times 10 to the 3rd ml of Ethanol. Uh so that would have the same volume as a leader of water. Or we could change this this week, 3.23 leaders if we convert this to leaders of ethanol, that has the same mass as a leader of water, actually not the same as contains the same number of molecules as a leader of water.

This problem covers the concept of the propagation of sound Pay in a medium. The speed of the sound in a medium, just given by the square root of the ratio of the bulk models of the medium with in city. Okay, so the speed of the sound and water equals square out of the bulk model, Asus 2.2 and two. Then there's nine newton four metre squared, And the density of water is 1000 kg for me, don't you? So the spirit of the Sound and water is 1483 m four seconds, Or in two significant Dessert. The speed of sound in Bata is 1.5 into And there's three m for second.


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