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Learning 00a7o Matkenc; Connccuonbenccn inilitive uncersancintolaaccsa and Itaslandard fommaliem KoluePartThk drotlem dez #h Ira concep: of Icrqua the 'tiist" tha:anoff- 6c tarcaonlics boly that tends makc It rotatc. (Figure 1}Determine > Ihe sum Ihc: torqqucs on ihc 8e08# Consiler onl; thc to qucs Gxccdthc chiklrenExpress Your answveteiMsand ) _Vic Available Hintis)AE+Et= 0 == WL -W. LSubuditFuMOM E#SE%Incorrect; Try Again; altempts remaininoFigureGilles has Jslan^ideriice (nguicD

Learning 00a 7o Matkenc; Connccuonbenccn inilitive uncersancintolaaccsa and Itaslandard fommaliem Kolue Part Thk drotlem dez #h Ira concep: of Icrqua the 'tiist" tha:anoff- 6c tarcaonlics boly that tends makc It rotatc. (Figure 1} Determine > Ihe sum Ihc: torqqucs on ihc 8e08# Consiler onl; thc to qucs Gxccd thc chiklren Express Your answve teiMs and ) _ Vic Available Hintis) AE+ Et= 0 == WL -W. L Subudit FuMOM E#SE% Incorrect; Try Again; altempts remainino Figure Gilles has Jslan^ ideriice (nguic Dean ciweight The txc txina now sit cn the same {daofire seesaw Vith Gilles dizance 1 2 from tne piotand Jean at Part D Wunene shqula Mlarca Dosmic" Jacjub' palarce sb85aw? Express Your answee Tetns of Lz and View Available Hint(s) Aap



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$\mathrm{FcCl}_{\text {j }}$ solurion addcd ro $\mathrm{K}_{i}\left[\mathrm{Fc}(\mathrm{CN})_{6}\right]$ givcs (a) while with KSCN gives (b). (a) and (b) respecrively arc (a) $\mathrm{Fe}_{1}\left[\mathrm{Fe}(\mathrm{CN})_{\mathrm{G}}\right]_{3}, \mathrm{~K}_{3}\left[\mathrm{Fe}(\mathrm{SCN})_{6}\right]$ (b) $\mathrm{\Gammae}_{4}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]_{3}, \mathrm{~K}_{3}\left[\mathrm{Fe}(\mathrm{CNS})_{6}\right]$ (c) $\mathrm{Fc}_{3}\left[\mathrm{Fc}(\mathrm{CN})_{i}\right]_{2}, \mathrm{Fc}(\mathrm{CNS})_{3}$ (d) $\mathrm{Fe}_{4}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]_{3}, \mathrm{KFe}(\mathrm{CNS})_{3}$

Hi everyone. So in this question they asked the electronic compilation of four elements are given as and uh one is managed to reassure people. The second managed to two years to do before 30s managed to do is to to be 3420s. When I should we ask you to pay six years 23 people? Which of the following enrichment gives the character order in terms of increasing electronic equity of lemons. So option she is correct. Oh son. Yeah. See is correct. Mhm correct. Alder off. Okay. Increasing electronic entity of the lemon teas increasing. Okay. Mhm. Electronica activity. Mm. Mhm. Yeah. Of the element ease. Mm As follows. Yeah. One X two creation To be 6 3 ash too three p 1 we can say at live India smaller than Okay. One is to to rest. Oh yeah to be three that is nitrogen which is smaller than nice to us to be for decades oxygen. Mhm Yeah, it is smaller than 1" to 3 years to to be for you that is floating chlorine. Is the lament having a guest electronic. It'd in the periodic table Florrie is the Lemon Read I. Yeste 11 12 negativity in the periodic table and erotic devil. Thanks loved

The geometry of the coalition and it can be predicted Officer managing behavior isn't? Which of the following? Is that correct? Yes, it is correct because magnetic behavior can be seen by the general first is the correct And I see him for two minutes involved the S two hi creation. Yes and I plus to have electronic conference and that is really 840 and seeing is that a strong field again that will pairing. So it will be the yesterday for all of us and it is within a group. Do you cannot value follows. It is incorrect because they don't know what they do for us five days then for me then P. D. C. LLC and for whom I am very scared. Ford is also correct. So correct. Option will be 1, 2 and four Palestine, correct.

Okay. And this problem, we have a scattering experiment where we have electrons being accelerated through a potential difference and scattering off some lattice who had some angles and creating an interference pattern. And this angle is to the first maximum of our interference pattern. So the first thing we're asked to do is arrested to change this table up and express V S V e to the negative one half the negative. So one over the square root of E. We can do that for all the members of the table I'm going to do if the first and last. Sometimes it actually is useful to be lazy, and this is one of those times. We're also asked to get the sign of data and get a table for it. We could plot there's results, and we'd have a fairly straight line us. I'm going to take the first and last elements and use that to compute an approximate of a slope which were asked to do to do that here. So the slope I have is about point two eight five seven. So from here, we're going to be asked to find the the lattice spacing from this information. Let's see where this slope will be useful. So we start from a two slit interference equation says we're looking at the first maximum. We have an equal to one. So we have designed data, goes Landa. And since we're solving for D, we can isolate it for later climbed over science Ada. So we need to know what land is. So to do that we can find the Debra Ugly way of life of our electrons recalled at Lambda for Debra Glade wavelength is one Oh is a chew over route to Emmy, where he is the energy connect energy of a particle. And this energy is going to simply be equal to the electric potential energy through his potential difference to be two AM charge of the electron times v the potential difference. Okay. And so we can actually in one more step, separate out all the constants from the interesting variable. So to Emmy, all this is a big constant and we have our potential difference to the one half power. Negative one half power. So plugging this lambda in tor interference equation, we have a much Constance and multiplied by V, the one negative one half over science data and take a look. This ratio is approximately going to be the slope of what we found in that second table. So, numerically, we have planks. Constant six point six to six. Even negative thirty for jewel seconds all over the square root of two times the mass of electron nine point one. Either negative thirty four. This is kilograms times the So this is not a This is a little e tried to burn, like trying one point six ten to the negative nineteen. Jules, this is that big constant. And then we can use our slope that we computed experimentally point two eight five seven. And when we play everything in that should give us the result from our approximate slit spacing. Just doing a little calculation. Oh, one mistake. This is not an eight to the negative. Thirty forces tonight of thirty one look okay. No, no. So when all said and done, I have three point five times ten the negative ten meters, or about a third of a nana meter. And this is my result for this. Let spacing using the experimental data and a little bit of algebra. Thank you.

So any problem 1 75 of chapter six compounds of P block elements to so in this question, majesty following. Uh so uh 40 xenon cetera fluoride, which is xia for So this is the structure of the non tetra fluoride as seen on having the eight valence electron. And uh out of these four are the bond peers and involved and who are the lone lone pairs? So these are the long pair of electrons. So that makes uh it's a scare planner. So it has four bond pair and too long beard. So that makes, its hybridization is basically sp three due to. Okay, so uh shape is this carefully? Okay, so next is the non hexafluoride. X. EF six. So this is the structure in which six bond pair and one lone pair. So this is distorted Octa federal. And makes its hybridization sp three D three. So it's hybridization is sp three D three and its shape is distorted of capital. So the next is ex ceo three. So this is the pyramidal shape and then we have XC offer and this is the battleship. So therefore the correct match becomes for a. That is much with the R. For be that much with the B. Foresee, that is S. And for the that is your


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