Okay. And this problem, we have a scattering experiment where we have electrons being accelerated through a potential difference and scattering off some lattice who had some angles and creating an interference pattern. And this angle is to the first maximum of our interference pattern. So the first thing we're asked to do is arrested to change this table up and express V S V e to the negative one half the negative. So one over the square root of E. We can do that for all the members of the table I'm going to do if the first and last. Sometimes it actually is useful to be lazy, and this is one of those times. We're also asked to get the sign of data and get a table for it. We could plot there's results, and we'd have a fairly straight line us. I'm going to take the first and last elements and use that to compute an approximate of a slope which were asked to do to do that here. So the slope I have is about point two eight five seven. So from here, we're going to be asked to find the the lattice spacing from this information. Let's see where this slope will be useful. So we start from a two slit interference equation says we're looking at the first maximum. We have an equal to one. So we have designed data, goes Landa. And since we're solving for D, we can isolate it for later climbed over science Ada. So we need to know what land is. So to do that we can find the Debra Ugly way of life of our electrons recalled at Lambda for Debra Glade wavelength is one Oh is a chew over route to Emmy, where he is the energy connect energy of a particle. And this energy is going to simply be equal to the electric potential energy through his potential difference to be two AM charge of the electron times v the potential difference. Okay. And so we can actually in one more step, separate out all the constants from the interesting variable. So to Emmy, all this is a big constant and we have our potential difference to the one half power. Negative one half power. So plugging this lambda in tor interference equation, we have a much Constance and multiplied by V, the one negative one half over science data and take a look. This ratio is approximately going to be the slope of what we found in that second table. So, numerically, we have planks. Constant six point six to six. Even negative thirty for jewel seconds all over the square root of two times the mass of electron nine point one. Either negative thirty four. This is kilograms times the So this is not a This is a little e tried to burn, like trying one point six ten to the negative nineteen. Jules, this is that big constant. And then we can use our slope that we computed experimentally point two eight five seven. And when we play everything in that should give us the result from our approximate slit spacing. Just doing a little calculation. Oh, one mistake. This is not an eight to the negative. Thirty forces tonight of thirty one look okay. No, no. So when all said and done, I have three point five times ten the negative ten meters, or about a third of a nana meter. And this is my result for this. Let spacing using the experimental data and a little bit of algebra. Thank you.