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Provide the major organic product of the following_ co Ch) CH (CH;ANH;(crtess)Draw the molecule on the canvas by choosing buttons from the Tools (for bonds), Atoms_...

Question

Provide the major organic product of the following_ co Ch) CH (CH;ANH;(crtess)Draw the molecule on the canvas by choosing buttons from the Tools (for bonds), Atoms_ and Advanced Template toolbars: The single bond is active by default:

Provide the major organic product of the following_ co Ch) CH (CH;ANH; (crtess) Draw the molecule on the canvas by choosing buttons from the Tools (for bonds), Atoms_ and Advanced Template toolbars: The single bond is active by default:



Answers

Draw Lewis structures for the following organic molecules: $\mathrm{C}_{2} \mathrm{H}_{3} \mathrm{F}, \mathrm{C}_{3} \mathrm{H}_{6}, \mathrm{C}_{4} \mathrm{H}_{8} .$ In each there is one $\mathrm{C}=\mathrm{C}$ bond, and the rest of the carbon atoms are joined by $\mathrm{C}-\mathrm{C}$ bonds.

All right. So acetone has, uh, these three carbons. This one is bonded to an oxygen double bonded. And then this one has three beaches And the other one Also has three ages. So normally it's abbreviated, but we like to draw them all out just to show all of the different ponds. All right. And then we want, so the shape around these two carbons is going to be the same and it's going to be touched a federal because you have four electron domains. And that means it's 109.5 degree bond angles as well. And then this carbon has three electron domains. Double bond counts as a single domain, no lone pairs. So it's going to be Trigano planer, Which means it will be flat in the plane and we'll have 120° bond angles.

For this question, we have to draw the Lewis structures of the following molecule. So for part A, we have C two after four or a touch of for ethylene draw the Louis structure. We will count the number of bounds electrons that we have. So each carbon has four valence electrons and each floor has seven, so of a total of £36 electrons. So to draw the loose structure, we will have the carbon. And we know that there is a carbon to carbon double bond because in the name, uh, Tetra for ethylene, that Ian at the end indicates that there is a carbon carbon double block. So each carbon has bonded to two florins. And we will use the rest of our electrons to complete the octet of the florins and that we have exactly enough electrons to do so. So that is, they lose structure for part A. For part B, we have propane again. We're gonna count the number of bounce left drugs that we have. Each carbon has four valence electrons and each hydrogen has one, so it gives us a total of 20 bounce electrons. You will have a three carbon chain and then we have eight electrons, so each carbon will have enough hydrogen to complete York types of carbons. This uses up all of our electrons as well Call with bonds. So that is a little structure of her heartbeat. For part C, we have you to dying, and again we're going to count the number of electrons and the total number of electrons. For this, uh, is 20 to 22 bounds electrons and the name of you to die. And we know that we will have to carbon to carbon Delavan somewhere in the molecule so we can have a carbon carbon double bond here and then another carbon. And then I had a carbon carbon double bond. We have ch two sore. First carbon will be wanted to two hydrogen. Our next carbon is bonded to one hydrogen. Our next carbon has also bonded to one higher gent in our last carbon is bonded to to hide regions in all these bonds, um, use of all of our electrons and all of our carbons with full locked up for party. We have pro pine. The number of bounce elections that we have in total is 16 and by the name Propylene. We know that we will have a carbon to carbon triple bond. So we have our first carbon CHD, which has bonded to three hydrogen and you will be carving Dickerman Single bond and then thes two carbons will be bonded by a triple bond. So that is where our triple bond is, and we have this last Carbon is born into one hydrogen so that issues of all of our electrons and all of our carbon of people locked up so that it's a little structure for party. Last day for party, we have been doing acid. You will. We have £46 electrons and we'll start by drawing a normal benzene ring. So will be alternating or carbon to carbon single bonds and carbon to carbon double bones. Five of the carbons will be attached to a hydrogen and one will have a acid. So this carbon is wanted to this carbon and you will have a carbon oxygen double bond and then a carbon oxygen single bond just bonded to hydrogen. We will use the rest of our electrons to have the lone pairs to our oxygen's. This is where our ass it is and we will have bins OIC acid. So that is a little structure for party

Hi, everyone. So, in this question, they asked that is the the four principal elements that forms or guinea campaign a number of bonds on by each lament so well, English and tabular form. So we'll wait here. Serial number, then four principal elements. Yeah, or principal elements. Elements. Uh, that forms the organic compound. Then you can say symbols. The mashed number of bonds from by these 11. Number of bombs fall. Yeah, number of bones from by this 11 mhm number of bonne femme. So serial number one 92 and then three, then four. So first one is carbon. Second one is I drove some. The third one is oxygen in the last one is nighters No carbon. It's Somali. See, Diane hydrogen. Then Oxygen is there's Yeah, the nitrogen Is this? Yeah, Yeah. Mhm. So I'm gonna bring this one back. Our buns. Therefore then hydrogen one Option two and nitrogen. Solidly. Thanks


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