Okay, so for number seven, let me change the color here. F E, N B R two or an elemental form B R. Is a negative one in the compound, F E. Is a plus too. If you're going from zero to plus two, that means that's a loss of electrons. So that means that this is oxidized. So this would be the reducing agent and then browning is going from a zero to a negative one, that's a gain of electrons. So this is reduced. So we would call it the oxidizing agent. Then on B, we've got a plus one on hydrogen and negative one on iodine, plus one on the H two, S. H and H two. S. +04 negative two on the oxygen. To figure out the sulfur, we've got two hydrogen at a positive one plus sulfur plus negative eight on the oxygen adds up to the neutral compound, which is zero. So if we're going to end up being a plus six here, then here we've got plus one on the H and H two S, negative two on the sulfur, elemental iodine. So that's zero. Oxygen is a negative two hydrogen as a plus one. Then you've got your id I'm going from a negative 1-0. So that's going to be a loss of electrons. So that means that this is oxidized. We would call this the reducing agent and then you've got your sulfur going from a positive six to a negative two. That's a gain an electron. So that means it is reduced and we would call this the oxidizing agent, then in C you've got hydrogen peroxide. So it's a plus one on the hydrogen and minus one on oxygen mono atomic ion, which is the same as its charge, plus two oxygen. Here is a negative two hydrogen as a plus one mono atomic ion, same as its charge, which is plus three negative two on oxygen plus one on hydrogen. If he goes from a plus two two plus three, that means this is a loss of electrons. So that means this is oxidized. We would call this the reducing agent and then you've got this oxygen going from a negative one to a negative two. That's a gain an electron. So this is reduced and we would call this the oxidizing agent.