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Under standard conditions, The standard reaction potential for copper is 0.3419V and for cadmium is -0.403OV. what is the standard cell potential for the cell?CdlCd...

Question

Under standard conditions, The standard reaction potential for copper is 0.3419V and for cadmium is -0.403OV. what is the standard cell potential for the cell?CdlCd2+ Il Cu2+ICu? (1 Point)-0.74 V+0.74V0.06 V-0.06 VHow many moles of electrons have been transferred between the species in the following reaction?2Cr3+(aq) 3Cu(s) 2Cr(s) 3Cu2+(aq) Point)

Under standard conditions, The standard reaction potential for copper is 0.3419V and for cadmium is -0.403OV. what is the standard cell potential for the cell? CdlCd2+ Il Cu2+ICu? (1 Point) -0.74 V +0.74V 0.06 V -0.06 V How many moles of electrons have been transferred between the species in the following reaction? 2Cr3+(aq) 3Cu(s) 2Cr(s) 3Cu2+(aq) Point)



Answers

Determine the overall reaction and its standard cell potential at 25 °C for the reaction involving the galvanic cell in which cadmium metal is oxidized to 1 M cadmium(II) ion and a half-cell consisting of an aluminum electrode in 1 M aluminum nitrate solution. Is the reaction spontaneous at standard conditions?

We are given an overall cell reaction as well as the value of the cell potential, and we want to determine the amount of total useful work that can be obtained at standard conditions. Since we know that this work is the work that the system does on the surroundings, this will be equal to the negative of the change in Gibbs free Energy. It's standard conditions and we know that Delta G is equal to negative NFI. So the maximum work that we can attain will get rid of that negative signs so that we're just left with NFI so and as the number of moles of electrons. And if we examine the overall so reaction that were given in the problem statement, we can see that we have cadmium solid going to C D. O H. Two solid and so cadmium goes from a charge of zero as a solid to a charge of two plus. So is oxidized, with two electrons so weakens, we can say that and is equal to two moles of electrons. So W Max is equal to positive and two moles of electrons times Faraday's constant F 96,000 485 Fulham's per mole of electrons times the value of the cell potential which is given as one 0.10 volts or jewels per Coolum. So when we calculate that all out, we're left with work, which is a change in energy. So energy units of jewels. And if we convert that into killer jewels by dividing by 1000 we're left with the maximum useful work attainable from this so reaction to be about 200 12 killer jewels.

This question is very simple. You know the cell potential that corresponds to the chemical reaction. We know the relationship between Delta G and the cell potential Delta G equals negative and F multiplied by the potential giving us negative too 2000 jewels based on the chemical reaction. And that would be four because there's only one mole of cadmium involved in the chemical reaction that would be the energy per mall of cat consumed.

So at the end of it we have aluminum oxidizing to a L. D. Plus. At the cathode, we have cadmium reducing um the least common multiple for the numbers of electrons is six. So we multiply the first equation by two and that'll give us six electrons here and then the second equation by three. So then we have six electrons. Then we can have the electrons cancel out and write the overall equation to a L. Plus three C. D. Two plus, Okay, makes to a L three plus plus three C. D. Then we have um the potential. So if we look up the reduction potential of aluminum, it's going to be negative 1.66 So that means the oxidation potential is 1.66 opposite. Since you've reversed the equation, that's involves the reduction potential of cadmium. From the table is 0.41 negative 0.41 So then you can add both of those up and you get this is a five. This is to this is the 11.25 volts is the cell potential. Um since that's a positive number, the reaction, as written, is spontaneous.

In this problem I can write the value of the shall not is equal to zero 57 P. B h. Is equal to love one by and plus so. And the law we will be equal to one by H plus And which is equal to 10 to the power -2. Here the value of n is equal to fool using notes equation. I can write the value of Ishmael is equal to the note sale -15954 log which minus to the power sticks by E 432 Which is according to -57 minus 0.0 5954. Love. And to depart, managed to three power 6 x one, which is equal to minus point 39 P. So according to the option here, option seeds, correct option C. Mhm Got it.


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