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BaSOxls) 322+(aq) S042 (2ak;Nazso ( Na SO4 -) is added thp edulln0.0150 (al: Through cansldertlan = Lc Chatelier , Princ ipic nowvllLolubil8350NaASoAssumc that no...

Question

BaSOxls) 322+(aq) S042 (2ak;Nazso ( Na SO4 -) is added thp edulln0.0150 (al: Through cansldertlan = Lc Chatelier , Princ ipic nowvllLolubil8350NaASoAssumc that no chinsivolume (sules trom the xsditlon(ol Calculute thc solubility Of BaSO; In a 0,01Sconcentraton 0if 5047 Ioans MeFotneal1204Paluempi

BaSOxls) 322+(aq) S042 (2ak; Nazso ( Na SO4 -) is added thp edulln 0.0150 (al: Through cansldertlan = Lc Chatelier , Princ ipic nowvll Lolubil 8350 NaASo Assumc that no chinsi volume (sules trom the xsditlon (ol Calculute thc solubility Of BaSO; In a 0,01S concentraton 0if 5047 Ioans Me Fotneal 1204 Paluempi



Answers

A solurion when diluted wirh $11 \mathrm{O}_{2} \mathrm{O}$ and boiled, gives a white precipirare. On addition of cxcess NI I Cl/Nl 1 OI I, the volume of prccipirare decreascs leaving behind a whire gelarinous precipirare. Idcnrify rhe prccipirarc which dissolves in $\mathrm{N} 1 \mathrm{l}_{i} \mathrm{OI} \mathrm{I} / \mathrm{NH}_{4} \mathrm{Cl}$ (a) $\Lambda \mathrm{l}(\mathrm{OH})_{3}$ (b) $\mathrm{Ca}(\mathrm{OH})_{2}$ (c) $\mathrm{M}_{g}(\mathrm{OH})_{-1}$ (d) $\angle \mathrm{rl}(\mathrm{O} \mathrm{H})_{2}$

So we're given with three parts off discussion Starting with first. We have represented the reaction off E g three, your four dissociation forming an I C E table that leads to I for in Asia See for change e for equal it So at initial there is no dissociation, so products So the product side off I C E table will remain zero As there is dissociation, the change will be positive. Three for silver and positive s for P or 43 negative as because there is one more off molecule form while for silver there are three moles off silver formed e equilibrium will be three s and s Now we'll write the equation for ke sp so ke sp will be equal Go the concentration off e g positive three days to poetry because three more three molecule formation on concentration off beautiful three Negative Now K s P will be equal to three s raised to power three multiplied with s equals 27 s place to power For now we substitute the value off Ke SP which is already provided in the question substituting the value we have 1.8 multiplied 10 days to plan Negative 18 equals 27 Yes, please To power for So this gives us the solid ability as equals 1.6 Multiply tenders to one negative five moving towards the but be We are given with calcium carbonate And here is the reaction for dissociation As initially we don't have any association. So the change off initial will be zero change for I C E table will be es and s because there is only one more regular formation over here. For the re write the equation for ke sp ke sp will be equal to concentration off calcium too positive and carbonate So it gives us s multiplied with s substituting the value from the given caution we have 8.7 multiplied tenders to one negative nine equals square Saal Ability s will be equal to 9.3 multiplied 10 days to power. Negative fire Moral leader Using the same method, we have etched gcl Toe association as initially Nord Association. So the value for initial will be zero for change. It will be positive s for HD and to us for two moons off seal, substituting the value into the equation. We have gai sp equals in the concentration off H g too to positive multiplied with seal negative raised to the power to we have s multiplied with us square I'm substituting the ke sp value from the equation. From the given question, we have 1.1 monty pretenders to plant negative 18 equals Full s cute. Now we have solid ability equals 6.5 multiply 10 days to one negative seven.

Calculate more excitability from past even though the relationship between Caspian muller saw liability for each of the compounds. The silver Fox State there are three silvers and there's one prostate. So the silver concentration is going to be three ass and will need to Cuba. And then the foster concentration is s So K SP, which is 1.8 times 10 to the negative eight it's gonna be 27 as to the fourth and s then is going to be 1.6 times tend to negative fit lead to the same thing for calcium carbonate. In this case, Caspi is just gonna be equal to s square where s is the most value bility and also equal to the calcium concentration and the carbonate concentration. So K SP is 8.7 times tend to negative nine that'll equal s squared and asked will be 9.3 times 10 the negative five for mercury one chloride the situation I will be able to cast P because the A G two comes off his one unit But there will be two chloride so the chloride concentration is going to be two s Will square the mercury one concentration will be equal to s It's okay, SP 1.1 times 10 detective 18 will be equal to four sq. Where s will be 6.5 times 10 negative seven.

So the first thing we wanna do is right are balanced equation. Okay, so for K sp that's always going to be the solid in equilibrium with its ions. So opposed to chloride. And then we'll write the expression for K sp that's the concentration of the lead. Two plus times the concentration of the chloride square. Right? We ignore our solid. And these are going to ionized in a ratio of X 2 to X. Right? So we can say that our K sp Which is 17 times 10 to the -5 is going to equal X times two X squared Or four x cubed. So we solve for X. That's our moller sally ability. So we get .016 moller for our second example. So we've got calcium phosphate skin. So we've got ions three calcium ions and to phosphate ions these are going to break up And the ratio of three x two X. It's OK, sp equals a concentration of our calcium ion cubed times are concentration of phosphate ion squared. So RKSP is one Times 10 to the -33. So that's going to equal three x cube times two X squared. Which is going to equal 108 x to the 5th. So when you saw for X You're going to get one Times 10 to the -7 Moller. So there's your mole or sell ability for that one. Okay. And then finally we've got silver carbonate. So that will give us to silver ions and a carbonate ion. These will break up in a ratio of two x two X to K. S. P. Is going to equal the concentration of your silver ion squared times the concentration of carbonate and RKSP is eight Times 10 to the -12. So that's two X squared times X. So that's going to equal for execute. And if you solve for X, you've got your molars sally ability as one Times 10 to the -4 Moller.

So the first thing we want to do is write out our reactions. S o The 1st 1 is gonna be silver sulfate dissolving, so it's gonna be two silver ions for everyone sulfate ion. Now, the next thing we can do is set up a nice table and let X equal the Moler Sally ability of the salt. When we do that, we can just multiply X by the coefficients in the equation. So let's start with initial. So for initial, we're not gonna have anything in solution. Remember that initial represents when nothing has happened yet. So when nothing's happened, you don't have any products. Our change is going to be, um, in terms of X, which you've done in other equilibrium problems just gonna multiply X by the coefficients in the equation of So that would be two x for silver and just one x for sulfate. So at equilibrium, it's just gonna be zero plus the change. So it's just gonna be to X and X. So now we write the K S P expression and we substitute in our X values for the concentrations. And so just remember writing the cast p expressions that the coefficients in the equation become exponents in the chaos P expression. So this gives us with K S P is equal to four x cute, and we can locate up. Excuse me. Look up. KSPN appendix J. That gives us 1.2 dents into the minus five equals for X cubed. So X is going to be 0.144 Moeller, remember we assigned X to be the Moler Sally ability of the salt. So, um, X is gonna be your answer. X is the moler scalability of G too. S 04 in the same rule applies for all of these. You know, I'm not writing out the full X. I'm sorry the full ice table. Because for ke sp expressions, you always end up with just zero plus something when you're finding the Moler Sally ability. So if you just right, that's something you don't need the whole zero part. So basically, the shortcut is to look in the expression or in the reaction and say OK, this coefficients one, this coefficients to sew for lead. It's gonna be one X and for bromide, it's gonna be two X. And if you did write it all out. It would be zero for lead, zero for bromide plus X plus two X. So you kind of take that shortcut and not write out the whole, um, ice table unless your teacher does ask for it every time. So now we plug into R K s P expression. So that's gonna be concentration of lead two plus four X concentration of bromide or two X and then squared from the prohibition. In the reaction that's gonna be four x cubed. We look up KSPN Appendix J and X, which is the Moler scalability of lead to bro. My is 40.105 for silver iodide. It's actually even simpler cause we just have a 1 to 1 ratio. So this is just gonna be X and X, So that gives us X squared in the K S P expressions, silver concentration times, iodide concentration, and that gives us an X or a 1,000,000 Moeller scalability of 1.2 times 10 to the minus eight. Same thing for calcium oxide late. It's just gonna be two exes, So ke sp is gonna equal X squared. You look up ke sp in appendix J and set it equal to X squared. So Ke SP is 1.96 times 10 to the minus eight x or the Mark Muller Sally ability is 1.4 times 10 to the minus four.


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