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Intense Khlte Hght Incident dittrac- pnting that has 540 Iines/mm What highest arder Khlch the complete visIbla apcetnimtnia nratinot KEntcrardet;cccond ordorWhatI...

Question

Intense Khlte Hght Incident dittrac- pnting that has 540 Iines/mm What highest arder Khlch the complete visIbla apcetnimtnia nratinot KEntcrardet;cccond ordorWhatIathe angular separatlon bettea theclolet edge (400 nm)the red eUge (700Ithe fnst oroer spectrum producedte qrabnor

Intense Khlte Hght Incident dittrac- pnting that has 540 Iines/mm What highest arder Khlch the complete visIbla apcetnim tnia nratinot KEntcr ardet; cccond ordor WhatIathe angular separatlon bettea theclolet edge (400 nm) the red eUge (700 Ithe fnst oroer spectrum produced te qrabnor



Answers

Intense white light is incident on a diffraction grating that has 600 . lines/mm. (a) What is the highest order in which the complete visible spectrum can be seen with this grating? (b) What is the angular separation between the violet edge $(400 . \mathrm{nm})$ and the red edge $(700 . \mathrm{nm})$ of the first-order spectrum produced by the grating?

Okay, So this problem, we have a grading never center long. Um, we're going to have a red line at 6 56 nanometer way playing. Um, which is gonna put it? Its first order will be a little bit higher than the blue violet line, which would be about here, And the rest of the waves will be between them. So we seem to calculate the status between those. So the red line data are devalue. Let's do that. So with that in black, because it's gonna be used for both of them. So devalue, we're gonna do one out of every. They're spoiling 4500 groups for per centimeter. So what, you want about about 4500. But that's gonna give us around 2222 nanometers between each slip. Okay, So for our sign data for red for a red line, it's gonna equal 6 56 was it says 6 56 But about 2222. So that angle it's gonna be equal to 17.17 degrees. And for a blue line, uh, it's wavelength is for 34 and over 2222 that data will equal 11.26 degrees, man. Okay, so the angular separation would be around six degrees, uh, between, uh, the red line in the blue line.

Hello students in this question we have a limited red light of wavelength lambda R equals to 6 56.2816 nanometers from hydrogen lamb. And this is forming a second order spectrum. That is M equals to two at an angle Theta equals to 42 point double zero degree from the central axis. So we have to determine the number of lines per centimeter. That is a. So one by eight. Okay, so we can right here that a scientist to it is equal to M. Lambda. So from here we get one by eight. It is equals two, one by A. It is equal to scientists to develop a. M. Lamba. Okay, so one by a. It is equal to sine theta which is 42 point a double zero degree. The verb A. M, which is two and lambda which is 6 56.2816 nanometer. That is 10 to the power minus nine. Okay, meet up. So one by A. From here and it is equals two. Fight 09789 lines per meter. Or in the centimeter we have to determine it. So this will be equals 25098 lines per centimeter. Okay, so this become answer for this problem. Okay, no next for this question. We have a blue light having lambda blue. This is equal to 4 86.13 to 7 nanometer. And for the second order that is again um equals two. We have to determine angular location data. So again we can write that a scientist to it is equal to M. Lambda. So lambda blue. So scientists from here it is equal to M. Lambda blue divided by A. And this one by a. We have calculated. Okay, so enriches equals two and lambda Blue, which is 4 86.13 to 7 nanometer. That is 10 to the power minus nine m and one by a in the meter lines per meter. We have obtained as 509789 Okay. Lines per meter. So from here, after solving the scientist that is equal to 0.4956 So from here this is equal to scientists. Of scientific is equal to this value, so tita is equal to 29.7 degrees. So this become answer for this problem. Thank you.

Hi, everyone. Here it is. Given that the hydrogen spectrum has red light off mainland 6 56 nanometers on the blue line for 34 nanometers, we have to calculate angular separation between these two spectral lines obtained with diffraction by grating that having 45,000 groups percent limited. So braiding is facing Bilby. Yeah. Dispense divided by number of ratings, that is 4500. So you will get 2.26 and 10 to the power off minus percent emitter are 2.26 So we'll find two. Totally. I'm prison wrongly minus 6 m anger off by extraction parts. Emmett Order can be given by Sign up, Peter Toby and land up on deep so we can find angular separation for first quarter spectrum Bill B sine inverse up and Lambda one upon d minus, Sign in words up and Lambda Tau upon D. So why using this formula, we can find the angular separation between them for first order, second order into one for first started, we can write sine inverse off Ambon. Baby length is given 6 56 and 10 to the power. My last night. The spacing is 2.2 and tow. Tend to the par minus six minus. Sign in. Worse off one for blue line. It is given 4. 34. Tend to the power minus nine upon 2.0 10 to the power minus six on solving it. This would be 5.91 degree. This is our balancer. Similarly, we can find him taken. Order the sign in worse off. Go into 6. 56 and tow 10 to the power minus nine upon 2.2 into 10 to the power minus six. Minus sign in. Worse off. Go into 4. 34 10 to the power minus nine. Divided by 2.2 and 10 to the power minus six. So it will be 32 degree 3. 13.2 degrees. Now if similarly we can find for in order sign in birds off three, 6 56 and toe 10 to the power minus nine. Upon to find Toto into 10 to the power minus six. Minus sign in. Worse off. Three into four, he fought can toe the power minus nine upon 2.22 into 10 to the power minus six, but it becomes 26.5. If you find for red or this bangle becomes greater than one for fourth order sign in verse, value becomes greater than one soul. It is not possible for red. Correct, that's what. Thanks for watching it.

We have reading, expressing D equals tension. Native to meter divided by 4500 equals. Two Going to do times 10 to the native six Major Now using scientific equals Landover D We have done over D. We have theta equals signing worse than over d are mm them over d m them never d so for M we're going to find a different values of Tedder. So for the first order, we find today 17.17 degree for the second orderly firing tear it'll be 11.26 degree so we can find the delta theta equals 17.17 bigly minus 11.26 degree equals 5.91 degree. This is for the forced in the second ordered. Similarly, there's a tender for second and third order and tender for third and fourth. Daughter will come out to the 30.2 degree on 26.5 degree


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