5

Course Contents chapteri3 Lamp in mirror Timer Notes Evaluate Feedback Print Info convex mirror has radius of curvature whose Vegictude is 49 cm. The mirror is isPo...

Question

Course Contents chapteri3 Lamp in mirror Timer Notes Evaluate Feedback Print Info convex mirror has radius of curvature whose Vegictude is 49 cm. The mirror is isPositiomed F horizontal optical bench with its front surface cm. A 8.0 cm long fluorescent lamp oriented is placed at +102 cm is the focal length of the mirror? 24.5 cm You are correct: Your receipt no: Is 149-6014 @ Previous Tries At what distance from the mirror can we find sharp image of the lamp? 19.8 cm You are correct: Your recelp

Course Contents chapteri3 Lamp in mirror Timer Notes Evaluate Feedback Print Info convex mirror has radius of curvature whose Vegictude is 49 cm. The mirror is isPositiomed F horizontal optical bench with its front surface cm. A 8.0 cm long fluorescent lamp oriented is placed at +102 cm is the focal length of the mirror? 24.5 cm You are correct: Your receipt no: Is 149-6014 @ Previous Tries At what distance from the mirror can we find sharp image of the lamp? 19.8 cm You are correct: Your recelpt no- Is 149-4988 @ Previous Tries How tall is the _image of the lamp? 51 m The ratio of the image distance to the object distance is equal to the ratio of the image height to the object height: Submit Answe Incorrect_ Tries 6/12 Previous Tries If the convex mirror were replaced by plane mirror and the lamp moved to 184 cm from the plane mirror; how tall would the image be? What is the magnification for plane mirror? Submit Answer Incorrect, Tries 1/12 Previous Tries Post Discussion Send Feedback



Answers

As shown in Fig. 34.61 the candle is at the center of curvature of the concave mirror, whose focal length is $10.0 \mathrm{cm} .$ The converging lens has a focal length of 32.0 $\mathrm{cm}$ and is 85.0 $\mathrm{cm}$ to the right of the candle. The candle is viewed looking through the lens from the right. The lens forms two images of the candle. The first is formed by light passing directly through the lens. The second image is formed from the light that goes from the candle to the mirror, is reflected, and then passes through the lens. (a) For each of these two images, draw a principal-ray diagram that locates the
image. (b) For each image, answer the following questions: (i) Where is the image? (ii) Is the image real or vitual? (iii) Is the image erect or inverted with respect to the original object?

Okay. In this problem, we have a convict convex lens with a raised curvature of 18 centimeters, and we have an object that's three millimeters tall and 18 centimeters away from the lens reversed as to show this image. The resulting images virtual were asked to find its distance and height of the image the only two equations will need for this is the ideal lens equation. One over the object distance plus one over the image distance equals one over the focal length of lens. We also we're gonna use the fact that the ratio of heights which we call M, is equal to the negative ratio of distances for the image of the object. So we'll do a bit of retracing. Its gonna be not as nice is like as it could be with these non straight lines, but also show you the idea. So here's our lens. And here the three principal Ray's going to the lens notice. They all deflect off the lens, the main race. But virtually an image is formed behind the lens, which has a certain height, and you can determine its height by looking at the intersection of these three principal race so the image has to be a virtual. It's going to be behind the lens. That's always the case. Uh, if we assume a focal length of negative nine centimeters as it asked the part B, we can use the ideal lens equation, recast it in this forum, using just in algebra to find d I. When we play our numbers in, we end up with negative six centimeters to find em. We ultimately find the image height. We, uh, use the definition of them, that the ratio of heights is equal to a negative ratio of distances. And then we've really cast this using a bit algebra to get the image height where we know the object. I it and we know the image, distance and object distance. We have everything we need. We can find the height to be one millimeter, and that's it. Just using the lens equation and the definition of them and a bit of retracing, and that's it.

Hi in this given problem, there is a converging lens first of all and this converging lands has been kept in front of a plane mirror like this. As shown in the figure. The gap between this converging land's end up playing mirror That is given us 30 centimetre for the length of this converging lenses given us Yeah, Is equal to plus 8.0 centimetre. And an object has been kept in front of these converging lens. At a distance object distance S. O. Is equal to plus 40 centimetre. Now we have to find the distances of all the images formed by this combination. So first of all, using lens equation which is a relation among the image distance, a sign object, distance S. O. And the focal length of the converging lens and plugging in all known values here, one by S. I. We have to find it Plus one by s. 0. 14. It's going to one x 8. This one by S. I. is equal to one x 8 -1 x 40. L C M here will be 40. This is why I -1 Is equal to four x 40. So s either distance of image comes out to be plus then centimetres. So that is towards right of the lens means it is somewhere here. The image. The primary image. The first image. So it's the distance will be and centimeter. Now this image will serve as an object for the plane mirror at a gap of 20 centimeters. So using the rules for the image formation by a plane mirror, the image will be formed at the same distance behind the mirror. But this is our even the first image, it will be I do the second image. No a distance of fasting age. This is the first answer for this given problem. Now this image will serve as a virtual objects for the plane mirror from which its distance is A total distance was 30 -10 centimeter from the converging lens. To that remaining distances 20 centimeter. So image form why this plane mirror will be behind the mirror at the same distance. So the distance of second image, that is as I do. So we can mark this As I. One so as I went was 10 centim from the converging lands is S. I do is 20 centimeter. The words right wrong the plane mirror. Now this image will again serve as an object for these converging lens. So now this distance of the image from the converging lines that will be because this is 20 centimeters. So this distance now will be 30 plus 20 means 50 centimetres. So now this image formed by the plane mirror will again serve as an object product converging lens. So the object that stands this time will be S. 02. That will be S. 03 because it will be the third image. So S. 03, That is 50 centimeter local. And still it will be the same 8.0 Centimeter and we have to find the stance of final in age. So using Land situation again, one by s. i. three Less, one by S. or three Is able to one by F. one by S. I. three. We have to find it. one by s. 0. 3 that is 50 Is equal to one x 8. This one by S. I. Three, It will be given by one x 8 miners, one by 50 here, L. C. M. That is 400 50 minus eight means 42 by 400. So finally Is s. I three Extensive 3rd image from the converging lens. It will come out to be Plus 400 x 42. Since this is 9.5 centimetre being positive. This is also real wilder in each formed y plane mirror that was worth juvenile and the very first image that was also real. So in this way we are getting to real images and one virtual image by this combination of lens with the mirror. Thank you

In this question, We are given this set up. So we have a candle here. He then, uh, there is a lands over here, uh, converging lands. And then there's also, uh, Mira. Well, here, mhm concave mirror, right. And then, uh, the distance between the candle and the lands is 85 cm, and then the focal length of the dance is the detours. Um, okay, The focal line of the mirror concave mirror is 10 cm and the distance between the center of the curvature, the candle is placed at the center of the curvature of the mirror, which is 20 cm. Okay, so in this question, we want to locate, uh, the image is formed by the lands and the mirror lens combination. Okay, so, uh, the first image is image formed by the lens only. Okay, The second image is we manage fallen by, uh, mirror plus lens combination. Okay. For each of the image, we are supposed to draw a diagram. And then for each image, you want to locate the image, uh, determine whether the images real or virtual direct or in the burger. Okay, respect to the original object. Okay, so for the first situation. Okay. Image from Buy the land for me if you have this radiogram. Okay. Um Okay. So, uh, okay. So this is an image formed by the land, Tony. Okay, so the image distance, it's around 51 cm. Okay, the image is real, and then you go out there. Okay? Mhm, um, for the image formed by the mirror lens combination. Okay, So, uh, we have this rain diagram for the era came in and lands. So from the mirror alone, the image here is inverted and real, okay. And it's at the same location as where the object is, where the candle is. So just imagine that when you have the lands, you have ah ah, image from the mirror at this location. And then you expect the image to be formed at this location. Okay. Yeah. So the image formed by the mirror and lens combination The image location, The final image location is still 51 cm to the right of length. Okay, by this time, the image Yes, real and I'm right. Okay. So 51 cm to the right of lands. Real All right. Okay. Compared to the, uh, to the original candle. So this one is, uh, mirror last lens. The sign is the image by mirror. Okay, so, uh, that's how we answer this question. Okay? And it's nice that the image formed by the mirror is at the same location where the candle is, uh to say is inverted when the after passing through the lens. Then the image becomes, uh, upright compared to the old, uh, competitive object. Okay. And then it's also real. Okay, so that's all for this question.

Hi, everyone. Here it is given effective index of broad to be 1.55 radius of curvature is six centimeters. Position of objectives is to the left. 25 centimeters. Addition of images. 65 centimeter refractive index of air to be one so and air upon s and rode upon as Jess and road minus and air upon armed and a ridge. But upon okay, fight and rot. 1.55 upon has tests. Mhm. So I just living 30 centimetre The remains displace. It's positive until it means the image is real. Right? And on the side of our outgoing And on that side of Okay. Mhm outgoing Lee heads. I made it 30 centimetre. Who? The right of left surface. Mhm. This image. It's the object for car Surface on the right. Uh huh. And a road a ball s an air upon as tests an air minus and roll upon arm. Mhm. Yeah. Here. Yeah, actually going to be and minus 30 centimetre l is the length mhm so from equation when you can write 1.55 upon all my necessary Let's burn upon 65. It's got to one minus 1.55 upon minus six. So l will be 50.3 centimeters. That's all. Thanks for


Similar Solved Questions

5 answers
0/1 points Previous Ans Vets TR4 5,P022.Hy NotesAsk Your Teacherbeam thermal neutrons (KE: first-order Bragg peak?025 cV) scatters from crystal with Interatomic spacing 30 nm. What the angle of the
0/1 points Previous Ans Vets TR4 5,P022. Hy Notes Ask Your Teacher beam thermal neutrons (KE: first-order Bragg peak? 025 cV) scatters from crystal with Interatomic spacing 30 nm. What the angle of the...
5 answers
If the number iS selected at Fandlom fror the %et of all five-digit numbers in which the SUm of the digits is equal to 43, what is the probability that che HIber Will be divisible by 11"
If the number iS selected at Fandlom fror the %et of all five-digit numbers in which the SUm of the digits is equal to 43, what is the probability that che HIber Will be divisible by 11"...
2 answers
20. (5 pts: and have joint distribution with pdf I(T,v) = e-(r+v) for m > 0,W > 0, The random variable U iy defined t0 be equal to U = Fut Find the pdl of U_
20. (5 pts: and have joint distribution with pdf I(T,v) = e-(r+v) for m > 0,W > 0, The random variable U iy defined t0 be equal to U = Fut Find the pdl of U_...
5 answers
Acetic acid is a common fatty acid in wastewaters_ (a) Write a balanced overall equation for aerobic oxidation of acetic acid, assuming ammonia is available as a nitrogen source and that fsimax) applies.(b) How many grams of oxygen are required to oxidize 100 g of acetic acid?(c) How many grams of bacteria are produced per gram of acetic acid metabolized?
Acetic acid is a common fatty acid in wastewaters_ (a) Write a balanced overall equation for aerobic oxidation of acetic acid, assuming ammonia is available as a nitrogen source and that fsimax) applies. (b) How many grams of oxygen are required to oxidize 100 g of acetic acid? (c) How many grams of...
5 answers
DETAILSQueationTha Maximum rate 0f cnange o( (*y 4)#at Ina Point (1,1,-4 =
DETAILS Queation Tha Maximum rate 0f cnange o( (*y 4)# at Ina Point (1,1,-4 =...
5 answers
Q We (robssulyj 4 MA&< hij 4 tyt & P ,'f k fias hms Wlrd 6 #k (n 106+504 4+ lthnp t 4xJet (4 At @est mCe MCs Cc) qf- leest #iC (6) U a la 5t ~wice_ (a) 7; Slaw +xt (-6)-C (W) s Le W ka? P= n (n-') (n-1) ~ (n-v+
Q We (robssulyj 4 MA&< hij 4 tyt & P ,'f k fias hms Wlrd 6 #k (n 106+504 4+ lthnp t 4xJet (4 At @est mCe MCs Cc) qf- leest #iC (6) U a la 5t ~wice_ (a) 7; Slaw +xt (-6)-C (W) s Le W ka? P= n (n-') (n-1) ~ (n-v+...
5 answers
+1200VThe diagram below shows series of equipotential lines They are parallel cach other and separated by distance d 1.6 cm: What the magnitude and [3 point] direction of electric field in the diagram?+6 C0v0.Cov-6.00v1200V=10 O0Vis launched from point and luter passes point charge 74.5 pC b) (5 points] field on the charge as It - travels C How much work is done by the electric - through point B t0 pcint C? [L #C 1060] from point _
+1200V The diagram below shows series of equipotential lines They are parallel cach other and separated by distance d 1.6 cm: What the magnitude and [3 point] direction of electric field in the diagram? +6 C0v 0.Cov -6.00v 1200V =10 O0V is launched from point and luter passes point charge 74.5 pC ...
4 answers
2 4 4 1 Plve 8 N9u
2 4 4 1 Plve 8 N9u...
5 answers
Use the phasor method, described in conjunction with Fig. 7.17 to explain how two equal-amplitude waves of sightly different frequencies generate the beat pattern shown in Fig. 7.19 or Fig. $P .7 .19 a .$ The curve in Fig. $P .7 .19 b$ is a sketch of the phase of the resultant measured with respect to one of the constituent waves. Explain its main features. When is it zero and why? When does the phase change abruptly and why?
Use the phasor method, described in conjunction with Fig. 7.17 to explain how two equal-amplitude waves of sightly different frequencies generate the beat pattern shown in Fig. 7.19 or Fig. $P .7 .19 a .$ The curve in Fig. $P .7 .19 b$ is a sketch of the phase of the resultant measured with respect ...
5 answers
7DeCermine wheller each of #e follcwing Sequences Sl Con vergent 9 diveryen4 IfF,s converge , fiaa ;t5 Iimi ES a) an = "2 - en + e-n(9 bn = 3j35 61Sqdr e roots)
7 DeCermine wheller each of #e follcwing Sequences Sl Con vergent 9 diveryen4 IfF,s converge , fiaa ;t5 Iimi ES a) an = "2 - en + e-n (9 bn = 3j35 61 Sqdr e roots)...
4 answers
Find the equivalent resistance between points A and B in the drawing:R1 =22 n R2 =l10 M MNR4 =20 n WNR3 =66 nNumberUnits
Find the equivalent resistance between points A and B in the drawing: R1 =22 n R2 =l10 M MN R4 =20 n WN R3 =66 n Number Units...
5 answers
Question Qne Evaluare che followings 24)3 log(ei)2i limz + ( 4 Arg(5 i) . sin( iln3)(3+2+2+2+2 points)
Question Qne Evaluare che followings 24)3 log(ei)2i limz + ( 4 Arg(5 i) . sin( iln3) (3+2+2+2+2 points)...
5 answers
Factor completely. Remember to look first for a common factor. If a polynomial is prime, state this.$$3 x+x^{2}-10$$
Factor completely. Remember to look first for a common factor. If a polynomial is prime, state this. $$ 3 x+x^{2}-10 $$...
5 answers
Perloim the Indlcated operatons and wnte your answers the Ionn bi , where and are real numbers_(1-0-(2+810-(2 + 81= -1+9i (Sinplly your answer )Thal 5 Incorrect;# hi and c + di are complex numbers, tho ddterence dolined 49 +6) - (cedf)=(a c) ' (bOk
Perloim the Indlcated operatons and wnte your answers the Ionn bi , where and are real numbers_ (1-0-(2+81 0-(2 + 81= -1+9i (Sinplly your answer ) Thal 5 Incorrect; # hi and c + di are complex numbers, tho ddterence dolined 49 +6) - (cedf)=(a c) ' (b Ok...
5 answers
A media rating company that publishes television ratings uses arandom sample of 1600 households and finds that 20% watched aparticular show in a given week. What is the approximate margin oferror?0.5%1.0%1.5%2.0%
A media rating company that publishes television ratings uses a random sample of 1600 households and finds that 20% watched a particular show in a given week. What is the approximate margin of error? 0.5% 1.0% 1.5% 2.0%...
5 answers
Let T : VR? be a linear transformation such that T(u) Tlv) = (-30,50) . and T(3u - 20 + Jw) = (20.60)_ Find T(gw)(80, 70) .(-28,37) (B) (27.-23) (9 -36,44) (30,-28)
Let T : V R? be a linear transformation such that T(u) Tlv) = (-30,50) . and T(3u - 20 + Jw) = (20.60)_ Find T(gw) (80, 70) . (-28,37) (B) (27.-23) (9 -36,44) (30,-28)...
5 answers
5.21: A giant wheel of radius 40 m is fitted with a cage and platform on which a man can stand. The wheel rotates at such a speed that when the cage is at X (as shown) the force exerted by the man on the platform is equal to his weight: The speed of the man isman in cagewhedl120 m/s28 mls20 mls14 mls80 mls
5.21: A giant wheel of radius 40 m is fitted with a cage and platform on which a man can stand. The wheel rotates at such a speed that when the cage is at X (as shown) the force exerted by the man on the platform is equal to his weight: The speed of the man is man in cage whedl 120 m/s 28 mls 20 mls...
5 answers
Express the IntegrallimitRiemann Gums Do not evaluate the limit (Use the right endpointscad suhintera a5 our sample polts
Express the Integral limit Riemann Gums Do not evaluate the limit (Use the right endpoints cad suhintera a5 our sample polts...
5 answers
What appears to be happening to the country's population every 22 years?It appears that the population growing by factor of 3 every 22 years_ It appears that the population is growing by factor of 2 every 22 years _ There does not appear to be pattern:It appears that the population is decreasing by factor of every 22 years
What appears to be happening to the country's population every 22 years? It appears that the population growing by factor of 3 every 22 years_ It appears that the population is growing by factor of 2 every 22 years _ There does not appear to be pattern: It appears that the population is decreas...

-- 0.021682--