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Two very long straight current carrying wires (I origin due Show the field vectors needed20 A) are placed solve the problem clearkyK-axis eSpectivelySnownthe given ...

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Two very long straight current carrying wires (I origin due Show the field vectors needed20 A) are placed solve the problem clearkyK-axis eSpectivelySnownthe given figure below. (a) Find the magnitude ad the direction the net field at the full credits- (b) third long straight current carrying wire placed the origin_ The length the wire andathe and (l.e: Into the page). Calculate the net magnetlc force on the thlrd wlre. Include Important physlcs and math steps clearly ear full credltscurrentthe

Two very long straight current carrying wires (I origin due Show the field vectors needed 20 A) are placed solve the problem clearky K-axis eSpectively Snown the given figure below. (a) Find the magnitude ad the direction the net field at the full credits- (b) third long straight current carrying wire placed the origin_ The length the wire andathe and (l.e: Into the page). Calculate the net magnetlc force on the thlrd wlre. Include Important physlcs and math steps clearly ear full credlts current the wire that opposite Upload your file here for grading: [ Chooze Flla No fle chosen You can upload PDF; Word, Jpg JPEG file. It must be less than 100 MB



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Add Vectors In almost all cases described in problem $97,$ a second wire carries the same current in the opposite direction. Find the net magnetic field that is a distance of $0.10 \mathrm{m}$ from each wire carrying 10 A. The wires are $0.01 \mathrm{m}$ apart. Make a scale drawing of the situation. Calculate the magnitude of the field from each wire and use a right-hand rule to draw vectors showing the directions of the fields. Finally, find the vector sum of the two fields. State its magnitude and direction.

Okay, so for this question, the magnitude off Magnante few due to wear one should be go to the managed to get you to the wire to So therefore, I'm usually I won over to buy all honesty with amuse your eye to over two yr too. As you can tell museum over to buy candy canes allows. So therefore I want over our winds will I to over our two. So if I two is your Taiwan Times are too over our one. So we know I want to 6 a.m. Here are two is the distance between the wire to two point peak which is your 2.0.50 meter. And our one is the distance between the wire one to a point, which is one point by the Amir. So therefore, let's determine the I to so the current wire to Can you go to six. Hello? I m here times Joe going 50 meter over 1.50 meter and this will give us the magnitude of the current and wire two is about to following a low end here And since the direction, um of occurrence in wire wise into the page That means the direction, uh of the currents and wire to should be out of the beige. Or you can say all the page. You will s say, also the plants. He's it seems the question is, was used playing. Okay, so they say although plane and the next question was passing us than that man it if you point you, which is you got to be one minus B two. Okay, so we're museum. I want over to buy online news Your eye to Over to buy are too. So you mentioned museums who over two pi times I won over our long lines I two of our two. So you zero is, uh, our museum. Um, it's a permeability off a free space, which is four parties. 10 departing seven tests out of Europe are impure. I mean, I want six MPR i one which is distant between my ones who point who is 0.50 meter and I took these two m p r and r two is equal to 1.5 years. Which is this on between wire to it to appoint you so therefore we can't determine down that magnetic view appoint you, Which is you go to for pi times 10 to the power off running seven. Tesla has meter upon M. Pierre over to high and has, uh I want to just two point om here. Over. I won, which is one point adviser o meter. I'm sorry, Joe. 0.5 years and minus two of ours who wishes, uh, this one should be six. My bear. And we have to appoint told em here over 1.50 meter and it will give us the net. Magnetic few at point. Q is about 2.13 times 10 to the power off next six. Tesla and, uh, sings. We know that. Do you want to square them be too, because he's closer. And also the current is larger. So there for the direction awfully met, uh, of a Knapman. And then, if you on point, you should be sent as a direction off the B one. Okay, which is the rice? Out of questions. See, while we no need net magnet, if you at point s is equal to score, you want squared plus B two square. So therefore is equal to museum over two apartments where I want over our square parts. I two overarching square. So we know Museo in Iowa are one and all in this case, which is distant between a wire want to appoint ass, which is there? 0.6 year old meter when I two is two m p r and R. Two is the distance. A wire to point asked 0.80 meter so we can determine the my nephew at point s, which is equal to well by tires 10 to the power of the next seven Tesla transmitter. Put em here over to buy, then times the square root. Just six point om here over 0.60 Mir to the power of to Plus to appoint om here. Oh, sorry. Over Joe Point Joe Going a zero meter to the power to this will give us the magnetic view. That point Ass is about 2.6 times 10 to the power off next six Tesla

In this problem. On the topic of sources of the magnetic field, we are given a long wire carrying current 30 MPs to the left along the X axis and a second long wire carrying a current of 50 MPs to the right along the line. Why is he put 20.28 m? We want to know where in the plane of these two wires will the total magnetic field be equal to zero? We've been told. A particle with a given charge of minus two micro columns is moving with the given velocity along the lion y is equal to 0.1 m and 00 and we want to find the victim magnetic force that acts on the particle. Then, if an electric field a uniform electric field is allowed is applied to allow this particle to pass through this region unaffected, we want to find the back to electric field now above the pair of wires. The field out of the page of the 50 current will be stronger in the field of the 30 m current in the opposite direction, so they cannot add to zero between the wires. Both produced field into the page and they can only add to zero below the wires when y is equal to minus the absolute value of why so here the total field will get from B is equal to new, not I of, uh two pi r and using the right hand rule, we'll get these fields for both currents so they will be equal to zero. And this was equal to mu not over two pi multiplied by the 50 NPR current divided by the absolute value of why plus zero 0.28 m along the minus K direction less that due to the 30 m p a current, which is 30 MPs divided by the absolute value of why along the K direction. So we can see from here that 50 times the absolute value of why is equal to 30 into mm magnitude of why plus 0.28 meters. So we get 50 times minus. Why is equal to that the into zero point 28 m minus y. And so if we calculate for why, from here we get this will occur when y is able to minus zero point for two meters. So that's the position at which the magnetic field zero Next. For part b of the problem, we want to calculate the victor magnetic force acting on a particle of charge minus two micro columns moving between the two. Why is so we know why is equal to 0.1 m for the particle again? We use the equation B is equal to you know what I over two pi are and this is equal to full pie times 10 to the minus seven Tesla meter per ampere divided by two pi multiplied by 50 MPs over zero. 0.28 minus 0.1 meters along the minus K direction less 30 MPs divided by 0.1 m times in fact. Okay. And so if we calculate as we get the result in field experience by the particle to be one point 16 times 10 to the minus four Kessler and that's a long the minus K direction. Now that we have the magnetic field, we can find the magnetic force so they forced on the particle f. He is equal to Q V cross B, so this is equal to the charge. Q minus two times 10 to the minus six columns are two micro columns, times its velocity 150 times, 10 to the power, six meters per second and I'm Unit Factor. I crossed with the magnetic field when 0.16 times 10 to the minus four, Kessler's. And that's along the minus K direction. So performing the cross product, we get the force of the particle to be three 0.47 times 10 to the minus two Newton's, and this is a long in minus jihad direction. So that's the force that the particle will experience as it moves between the wires. Now, lastly, we want to know the back to electric field that will allow the particle to pass through the region and deflected. So we require this electric force to be three point 47 times 10 to the minus to Newton's, which is the magnitude of the force above, but to be directed to go across along the J direction, and this is equal to the magnitude of the charge times, the electric field. So this is minus two times 10 to the minus six columns and the electric field. Mm. So from here we can rearrange and solve the electric field that's required to allow the particle to pass and deflected. And so calculating We get electric field to be minus one point 73 times 10 to the power for along the jihad direction. Newton's cool on.

Hi In the given problem there are two parallel current carrying conductors. The first conductor Is scaring a current I one Given to be 6.00 ampere and that is directed into the plane of paper. Now there is another conductor also kept parallel to it, but the magnitude of current carried by this conductor and its direction both are missing. No, there is a point on the line joining these two conductors, the point B which is at a distance of 0.50 m From the 2nd conductor. The distance between the two conductors is given as 1.00 m And it is given that the magnetic field at Point P. The Net Magnetic Field is zero. Now using right hand pan rule the direction of magnetic field at point B. Due to the first current carrying conductor means we can say to be be at p. due to one As this direction of the current is downward. In the plane of paper, this is B at P 2-1. So In order to get the net magnetic field to be zero. The magnetic field due to the current in the second conductor means b. p. two should be upward in the plane of paper. So for this BP two to be upward, the current I do in the second conductor should be coming out perpendicular to the plane of paper. So this is one of the answer means now we know the direction of this current. Now in order to get the magnitude of this current, we use the concept be at P due to one should be equal to be at the due to two for which the expression for the magnetic field At any point around our current carrying conductor using pattern seven slope. It becomes new not by four pi. Into two. I won by our for current Ivan, the distance will be 1.0 m plus 0.50 m. So it will come out to be 1.50 m is equal to mu Not by four pi. Into two. I two. By the distance is just 0.50 m. So canceling the similar terms from both the sides. No, we get this expression to be equal to and hear this Current Ivan is given as six ampere. So plugging in this value as six ampere Divided by 1.5 Is equal to I two, which is missing divided by 0.5. So finally the magnitude of that current I two here comes out to be 2.00 M. Pierre, which is the answer for the first part of this problem. Now, in the second part of the problem, we have to find magnetic field at another point Q. Here this is the point Q. Having a distance of 0.50 m from this first current carrying conductor towards the left. So the magnetic field at big at point Q means BQ will be equal to the Addition of two magnetic fields. First of all, this is be at issue due to one and using right hand screw rule the direction of this Big one will be upward coming out of the plane of paper minus B. Q. Two due to the second conduct. And that will be downward means into the plane of paper. So This is new not by four pi Into two. I won by the distance 0.5 minus mu Not by four pi two I 2. That it stands again here. It will become 1.5 m. So canceling from meter to meter Munich by four pi. Sorry, these will not be cancelled as we are not equating them, we are adding them. So plugging in the non values before plugging in the non values, we will take the common things out. So first of all, 10 days, 1 -7 means in place. Um you know by four x 10 for -7 will be taken out, Then these two will be taken out leaving behind Ivan the value of 51 which is 6.00 ampere divided by 0.5. Meet up minus two Because we have found the value of item which was 2.00 divided by 1.5. Meet her again. So finally here it comes out to be 2.13 into 10 days par -6 Tesla. Or we can say The net magnetic field at Point Q is approximately 2.13 micro Tesla and direction will be outward coming out of the plane of paper. Answer for the second part of the problem. Finally, in the third part of the problem, the observation point is, yeah, this is the observation point. Let it be S. And the distances of this observation point Are given as zero 60 m here And 0.80 m here. If we apply a pythagoras Tehran, we conclude that Actually this angle will be equal to 90°.. So then we find we have to find the magnetic field, that magnetic field at point S. Due to these two current carrying conductors. So using again right hand screw rule the direction of magnetic field at S due to one will be perpendicular to this distance, joining us with the first conductor and towards the second conductor. So this is Be at S due to one and similarly here, due to the second conductor. This will be yes, be at asked you to. So first of all, we will find these two values and then we will them, we will add them using Triangle ofac tradition in the third part of the problem. So first of all, b. s. one is equal to Munich by four pi into two. I went by our So this is 10 days for -7. Into into for Ivan This is six ampere Divided by our distance, which is 0.60 m. So finally, this value comes out to be To into tended bar -6 Tesla. Then B. S. Two is equal to mu not upon for pie Into two. I do buy art Again, 10 for -7 into two. Into the value of I two. We found in the first part of the problem and that it stands 0.0 m and this value comes out to be 0.5-10 for -6 Tesla. So finally the net magnet will will be given here. This is the square root of the square of bs one plus a squared B. S. Two. Or we can citizens do Square plus 0.5 square. After taking the standard for -6 square as common, which will become tangible -12. Then this standard for -12 can be taken out of the route, Making it 10 for -6. So inside it it will be 4-0.25 Tesla. Or we can say the net magnetic field at this point is The square root of 4.25 into 10 HR -6 Tesla. And finally, the answer for this magnetic field is 2.06. Might grow Tesla answer for that 3rd and the last part of this problem. Thank you.

Hello, everyone In this problem, there is a current carry conductor along acceptance in which guarantees 30 and beer along the get developed sex. Is Jerry any other long conductor after position trying to it. Meter on biases Jet is zero and x zero on it Carry suffering 50 ampere. And on what date back sex is, there are two parts in the question. In the first part, we have to fight the tradition in the plane off the fight. Would you shouldn't a play off the way. Average next Magnetic fie! Your total memory feelings Too busy. Oh, in second part, we have to complete the foods on the judge off to my crew Cooler moving with velocity. What p six into 10 to the power six Need up our second a law. What did to back sexes at that position? Judo. When one and you know okay, in the turn part, we have to complete that electric field is to be applied so that Judge Rami's under flapping from its but now we start solving it one by one. Trust me, design you are I'm growing the regular McGee. This is the first way image simply and purely horrendous ploy. This is not thinking by this is audience image 30 appear current. It's ploy the city will buy Axis. This is all again. This is your taxes. Suppose we have taken any quite be extra space spittle excesses on beer country your magnetic field at people s Because you know we will calculate hit magnetically at me. Go first. Well, having that many do you know I went up one by s on direction. If you find it will be over that it's kicker similarly magnifique. Do you second back? Um you know I one bite. Why wait Less sets and it will be minus Caykur And this value is given toe zero for us. No simplify such you, madam. So from this equation, by comparison, you will get extra me wonderful. Two meter or humid I X coordinate B minus uncertain. You may die because it is four Perimeter at magnetic field is to be Do not Even so, the second bar. I can be a brother who understand this is about it. This is not thinking by having a family and bigger So it could be a building And Scott in it is you. Why do it, Mr Obama? Zero This is your by excess. This is first by having doctoring 30 Ambien. And this is your taxes. Here it is a judge. You at this position, It is moving along. This direction at this distance is given. Why one leader So active position off judge. Really Quite a magnetically. So here we will write the magnetically. It will be you not do do This way it will be new nuts I upon by into a while back on direction you can find my right symptom room So it is outward so that will be less cake up. Similarly, you knock. I do. Who by? Why I wanted this district will be white money maker. I'm not absent between can't get no substitutes ever. You will get Magarri feel at the position. Off moving Billy four. Fine. And you can do the power off minus seven. 30 one. Bite into quite one Kika. Full bite into 10 to the Barbara minus seven. Move by. Quite village tippy getting up on Sunday. This baby. But wait 16 to 10 to the power. My passport giving up on you. Notably retest. Um no foods on the charts. due to my village finish defined its you. We crossed me. No substitute of any charges to my group. Negative. Minus point to 10 to the power off minus six. Better city is bunch of physics in tow. Tend to devour six, I guess. Magnetically 1.16 10 to the power of my passport. Here you go. Now we have to find that prospect off. I get so on solving this value ability minus up. Who? Gica new guy. So this is the answer. A second bar? No. We have to solve the time. We have to find the magnetic field assistant. So we have to find electric thing. Which is, to be of like, so that charges will under clapping that is forced due to magnetic field should be equal. And a Fortunato force, you know, an epically no substitute minus minus. It becomes palace. So electric will be will get 11 17 and to 10 to the power for Newton Papua along by exists, that is bigger. So this is that tire answer. Thanks for watching it


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