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13) (201 Some colleze students belleve that using non prescribed stimulants (e K , Adderall) whlle studylng will enhance thelr academic performance, To test this, r...

Question

13) (201 Some colleze students belleve that using non prescribed stimulants (e K , Adderall) whlle studylng will enhance thelr academic performance, To test this, researcher Fandamly as;igned college students who have not been duipnosed with ADHD take dose Lncr stimulant drug (ZOm Adderolll = pIucebu (sugar plII} , und then Kave them cognitive test deslgned DSes learning; reasoning und iemory Econs could range from 100; hikher scores indicale Detter petformatce): The sample of n= 30 students wh

13) (201 Some colleze students belleve that using non prescribed stimulants (e K , Adderall) whlle studylng will enhance thelr academic performance, To test this, researcher Fandamly as;igned college students who have not been duipnosed with ADHD take dose Lncr stimulant drug (ZOm Adderolll = pIucebu (sugar plII} , und then Kave them cognitive test deslgned DSes learning; reasoning und iemory Econs could range from 100; hikher scores indicale Detter petformatce): The sample of n= 30 students who took dOSl Adderallhad _ lest Jverage ol Me 66 wilh Mandard devlation al $ 14,whlle thesumple 0t 28 wha took the placebo hadan JvCnel ol M 77 wlth suandard devlation ol $ Does the dato Jtcm thls experiment provide enough evidence conclude that the Use ol non presct bed stImulant;has Slenlilcant eIlect on college students' performunce? Use ~alled test with a 14) (8} Referring the study Irom Q13,compute the value o/ 5m (the estimate of the standard error of the dilference of means) und write. sentence Interpreting the value context 15) (8 Baseo Jnswer 013, cun VoU conclude that the Use students' performance? Why or why not? non prescribed stimulants ennonces college



Answers

The stimulant Ritalin has been shown to increase attention span and improve academic performance in chil dren with ADHD (Evans et al., 2001). To demonstrate the effectiveness of the drug, a researcher selects a sample of $n=20$ children diagnosed with the disorder and measures each child's attention span before and after taking the drug. The data show an average increase of attention span of $M_{D}=4.8$ minutes with a variance of $s^{2}=125$ for the sample of difference scores. a. Is this result sufficient to conclude that Ritalin significantly improves attention span? Use a onetailed test with $\alpha=.05$ b. Compute the $80 \%$ confidence interval for the mean change in attention span for the population.

Looking at Ritalin, which is also, um, called methylphenidate, and it's also called method validate and methylphenidate. A Ritalin has a chemical formula C 14, H 19 and 02 and if we look at its structure, it would be the structure here. And for part A where EST is Ritalin in acid or a base. So Ritalin is a base because it has a secondary, a mean functional group, and, um after the lone pair, well, the electrons on nitrogen can be donated to a proton so that it behaves as a Louis space. We're also asked if it is an electrolyte or a non electrolyte, since it is in organic, non polar molecule. Um, there is no dissociation. So it is a non electrolyte for Part B or us to calculate the malaria t of Ritalin in a man's bloodstream, assuming five liters of blood. If we take a 10 mg dose of the Ritalin C 14 age 1902 Now let's find number of moles here. Convert to grams and the molar mass of Ritalin is 233 31 g per mole. This would yield 4.29 times 10 to the negative five Moles of the Ritalin And who can solve for the mill arat E of the Ritalin. So we have the number of moles divided by the volume of blood. Is five leaders in this workout too 8.6 times 10 to the negative six Mohler. So this would be the initial morality of the Ritalin in the bloodstream. For part C, we're told that the concentration of Berlin in the bloodstream decreases by half of its initial value every three hours. So we're asked, what is the concentration after six hours? Well, after three hours, concentration would be 8.6 times 10 to the negative six. Mohler divided by two, which would be 4.3 times 10 to the negative six. Mohler. And then after six hours, it would be 4.3 times 10 to the negative. Six. Mohler divided by two. And after six hours, the riddling concentration would be 2.2 times 10 to the negative six. Mohler. There would be our answer


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