Question
The figure below 42 0 (M stralght segments the posiuve direction Determine the maanetic Torce sedmentoomclosencand (nai camescumeni4nte dlreclan shownunlform magnetlc field magniqde0 01a TEiplin Jow VOU coum Indtheeranefourhchese segments from che forcesthree akthonc fmthe calculatlon Involving the magnetic field
the figure below 42 0 (M stralght segments the posiuve direction Determine the maanetic Torce sedment oom closencand (nai cames cumeni 4nte dlreclan shown unlform magnetlc field magniqde 0 01a T Eiplin Jow VOU coum Indthe erane fourh chese segments from che forces three akthonc fmthe calculatlon Involving the magnetic field
Answers
Find the magnitude and direction of the magnetic field $\vec{B}$ at point $P$ in Fig. $30-32$, for $|i|=10 \mathrm{~A}$ and $a=8.0 \mathrm{~cm} .$ (See Problems and 16.)
We have, man Tick Village is given by Do not over for by times I just us over our one squared which will come out as you're not over four pi times I delta theta over our ones. So magnetic field You do arc one with the integration off. Negative by over to toe positive by over two. No, not I d theta over four pi r one equals. Um you know, I over four by our one times. Bye equals mu not I over four are one. Now for our two. It is with the same, but this is with our one on out of the page on this will be mu not I over four are too out of the page, so we will have total be It will be. Want us be too equals mu not I. Over four one over R one minus one over R two into the page and putting the values in. We will find B equals 7.9 times. 10 to the negative five esa into the page
Uh huh. Be at a will. Be, um, you know, I over to buy the Let's call it the one out of the page to us, Milner. I over two pi the two into the page, and the one is two centimeters. Do you do is Forbes. Last week was six centimeters. Andi. That's how you will get be a will to be 6.7 times 10 to the 95 Tessa out of the page, mhm at point B or two. It will be in the similar way it will be two times 10 to 94. Tessa into the page on at point C or three. It would be 6.7 times 10 to the 95 Jessa out of the page. Out out of the bag is the dot out of
Hello students in this question we have to find the magnetic field at point C. Okay so we have the two disciples that is over and 02. Okay. And the magnetic movement of the first one is and when equals two am not and for the second one M two it is equal to 16. I'm not. So this open is situated at the actual point. So that magnetic field of even will be equals to the you know two divided by 45. And this I'm going to ever buy. These are not Q. Okay so everyone is equals to this. I am not some you not divided by four path blurb. I am not aware they are not cute. And this Magnetic field will be in the direction of the Apple movement. So this will be towards the right. Okay now talking about the magnetic field B2 which is due to the photo. So this will this is on the equatorial position. Sorry. Here we will have another factor too. Yeah. To do excel situation. Okay this is exhale, this is equatorial. So um you know to develop before by and this is um to develop our mhm dash is cute. Okay so you not divided by 45 and M. Two which is equal to 16 and not ever be our dish which is to our not so too are not to the power three. And this disciple after this magnetic field after solving is equals two mu not divided by 45. Yeah who am not where they are not cute and this will be opposed to the double movement because it is in the equatorial situation. So the net magnetic field at once, she will be equals two B one plus B two. Both are equal in magnitude. Okay? But oppose it in the direction. So the net result will be equals to zero. Okay, so this is the answer for the problem. Okay, so from the given options option C. Is the correct answer here. Thank you.
In this problem, we apply a bio say words law by your say a word more to complete the main T field due to current caring segments at various locations. Bye. Or say what law says b it x Y Z is equal to mu nod divided by four pi which are a constant times. A current times Delta is cross our unit director divided by our square which is a constant mule I divide before by, um, Delta is cross our director derived by our three. We rotate the unit director on care into our vector divided by our so our camp is a call to our matter developed by its magnitude. Then our Delta X s story is a delta s main chute times in the Jacob direction and our factories excite plus wah jee plus z k the cross product use us Del Delta is cross on physical thio. Delta is Z I can't minus X k kept then for the what a off the problem. But a the field on nosy exes Between zombie 0005 meter it will be four by times 10 to the ball with minus seven, divided by four by five square power through You're too this above. We have two MPR current times three times dental power minus two meter downs. A five meter in I kept direction, which gives us 2.4 times dental power minus 10 Tesla in high cave direction. Similarly, for part B um man tick, he'll be at 06 meter and zero will be zero since Izzy Musical The X, which is 1/4 0 For her part, see off the problem. Similarly, be seven meter seven meters zero we can find by substituting a values a magnetic field or for minus 4.3 times dental bar minus 11. Tesla in KK of direction in body for the points minus three. Me to remind us for. And zero. We get the man tick field all from 1.4 times 10 to the power minus 10 Tesler in K kept direction.